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AB
*C
__
DE

In the correctly worked multiplication problem shown above, A, B, C, D and E are different non-zero digits. What is the valued of D?

(1) A = 3
(2) D is an even digit


(1) A = 3

dont know about b and C
so, D can be any value from 3 to 9
Not sufficient

(2) D is an even digit

dont know about A, B & C
D can be 2, 4,6,8

Not sufficient

(1) + (2) : A = 3 and D is an even digit

C must be 1,2 or 3

1 and 3 cant be possible, so C = 2

D must be 6

Sufficient

Answer C
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Why can C be just 1 or 2? Why can't it be 4, 5, ..., 9?
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vatsal323
When we combine the two statements, the only possible values for C are 1,2 and 3 as 4 onwards the value of D becomes a two digit number (4 x 3= 12) and so on, Hence the only values of C are 1,2 and 3 in which D has to be an even digit therefore C is 2 which gives D as 6.
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vatsal323
Why can C be just 1 or 2? Why can't it be 4, 5, ..., 9?

When A is 3, C equal to or greater than 4 would make the result a 3-digit number, the question has set the constraint that the result should be a two digit number.
For example, 30*4=120
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A alone insuff
B if D is even A has to converted to 6 if more then it becomes 3 digit hencce sufficient

IMO C
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vatsal323
Why can C be just 1 or 2? Why can't it be 4, 5, ..., 9?
if it's four 4 5 9 it becomes 3 digit
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