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# According to the table above, the number of fellows was approximately

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Math Expert
Joined: 02 Sep 2009
Posts: 44586
According to the table above, the number of fellows was approximately [#permalink]

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30 Jul 2015, 10:33
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76% (01:19) correct 24% (01:22) wrong based on 191 sessions

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According to the table above, the number of fellows was approximately what percent of the total membership of Organization X?

A. 9%
B. 12%
C. 18%
D. 25%
E. 35%

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:

2015-07-30_2131.png [ 29.71 KiB | Viewed 3213 times ]
[Reveal] Spoiler: OA

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Re: According to the table above, the number of fellows was approximately [#permalink]

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30 Jul 2015, 11:08
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Bunuel wrote:

According to the table above, the number of fellows was approximately what percent of the total membership of Organization X?

A. 9%
B. 12%
C. 18%
D. 25%
E. 35%

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:
2015-07-30_2131.png

Fellows = 9209
Total Membership = 78 + 9209 + 35509 + 27909 + 2372 = Approx (0+9200+35500+28000+2370) = Approx. 75000

Fellows as % of total Membership = 9200*100/75000 = 12.26 = 12%

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Senior Manager
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According to the table above, the number of fellows was approximately [#permalink]

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30 Jul 2015, 15:14
1
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First, I checked the answer choices to know what the spacing is before I went to calculate the answer. Since they were spread somewhat, I could be a bit more generous in my estimation for each number.
[not large enough, thus 0] $$+ 10000 + 35000 + 28000 + 2000 = 75000$$

$$\frac{10000>}{75000>}$$ =~$$\frac{1}{8}$$
Little less than $$10000$$ divided by little less than $$75000$$ is $$\frac{1}{8} = 12.5$$%

IMO. B
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Re: According to the table above, the number of fellows was approximately [#permalink]

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30 Jul 2015, 20:01
1
KUDOS
Roundup to the thousand

so we have 9+35+28+2 = 75
9/75x100 = 12
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Re: According to the table above, the number of fellows was approximately [#permalink]

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31 Jul 2015, 00:40
1
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dividing by 1000 and rounding up,

0+9+36+28+2/5 = 75/5 = 12%
Director
Joined: 21 May 2013
Posts: 621
Re: According to the table above, the number of fellows was approximately [#permalink]

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31 Jul 2015, 02:44
1
KUDOS
Bunuel wrote:

According to the table above, the number of fellows was approximately what percent of the total membership of Organization X?

A. 9%
B. 12%
C. 18%
D. 25%
E. 35%

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:
2015-07-30_2131.png

Total no of members=75,000(approx)
Fellows=9,200
% of fellows=(9200/75000)*100
=12%
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Re: According to the table above, the number of fellows was approximately [#permalink]

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31 Jul 2015, 07:14
1
KUDOS
No. of Fellows = 9,209
Total members = 75,077

Percentage of Fellows = 9,209/75,077 = 9,200/75,000 approximately ~ 12%. Ans (B).
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Joined: 21 Jan 2015
Posts: 149
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Concentration: Strategy, Marketing
WE: Marketing (Consumer Products)
Re: According to the table above, the number of fellows was approximately [#permalink]

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06 Aug 2015, 00:27
1
KUDOS
Bunuel wrote:

According to the table above, the number of fellows was approximately what percent of the total membership of Organization X?

A. 9%
B. 12%
C. 18%
D. 25%
E. 35%

Ans: B

Solution: sum all the numbers and then do (Fellows/Total sum)* 100=
using the approximation method, ans will come to approx 12%
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Math Expert
Joined: 02 Sep 2009
Posts: 44586
Re: According to the table above, the number of fellows was approximately [#permalink]

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17 Aug 2015, 07:40
Bunuel wrote:

According to the table above, the number of fellows was approximately what percent of the total membership of Organization X?

A. 9%
B. 12%
C. 18%
D. 25%
E. 35%

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:
2015-07-30_2131.png

OFFICIAL SOLUTION:

From the table, the number of fellows is 9,209, and the total membership is the sum of the 5 numbers, which is 75,077. Therefore, the number of fellows is 9,209/75,077 of the total membership, or approximately 12 percent. The best answer is B.
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Re: According to the table above, the number of fellows was approximately [#permalink]

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31 Jan 2016, 08:25
mejia401 wrote:
First, I checked the answer choices to know what the spacing is before I went to calculate the answer. Since they were spread somewhat, I could be a bit more generous in my estimation for each number.
[not large enough, thus 0] $$+ 10000 + 35000 + 28000 + 2000 = 75000$$

$$\frac{10000>}{75000>}$$ =~$$\frac{1}{8}$$
Little less than $$10000$$ divided by little less than $$75000$$ is $$\frac{1}{8} = 12.5$$%

IMO. B

+1 Kudos...

Better approach to this Q
Math Expert
Joined: 02 Aug 2009
Posts: 5771
Re: According to the table above, the number of fellows was approximately [#permalink]

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31 Jan 2016, 09:00
ArunpriyanJ wrote:
mejia401 wrote:
First, I checked the answer choices to know what the spacing is before I went to calculate the answer. Since they were spread somewhat, I could be a bit more generous in my estimation for each number.
[not large enough, thus 0] $$+ 10000 + 35000 + 28000 + 2000 = 75000$$

$$\frac{10000>}{75000>}$$ =~$$\frac{1}{8}$$
Little less than $$10000$$ divided by little less than $$75000$$ is $$\frac{1}{8} = 12.5$$%

IMO. B

+1 Kudos...

Better approach to this Q

Hi,
the answer choices are given in a way that we dont require to get into extensive calculations..

fellows= 9000 approx..
total = 3500+28000+2000=65000..
so 9000/65000..

lets see the choices..
A. 9%
B. 12%
C. 18%
D. 25%
E. 35%

What can be the broad limits of x..
1) The value has to be greater than 9%, as the denominator is 65,000.. for 9% it should have been 100,000.. so A out..
2) the value has to be smaller than 18%, as the denominator should be less than 50,000 ... so C,D and E are out

only B 12% is left
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Re: According to the table above, the number of fellows was approximately [#permalink]

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29 Nov 2016, 13:53
Nice Official Question.
Here is what i did =>
Number of fellows => 74999=> 75000(approx)
number of fellows => 9200=> 9000(approx)
Hence required percentage => p(let)
$$\frac{p}{100}*75000=9000$$

p=12

Hence B

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Re: According to the table above, the number of fellows was approximately [#permalink]

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15 Mar 2018, 12:53
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Re: According to the table above, the number of fellows was approximately   [#permalink] 15 Mar 2018, 12:53
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