GMATCoachBen
Alejandra is designing a game of chance. For one part of the game, a player is to randomly choose 3 marbles, without replacement, from a box containing 𝐵 blue marbles, 𝑅 red marbles, and no other marbles. Alejandra correctly determined the positive integers 𝐵 and 𝑅 so that the number of possible selections in which 2 blue marbles and 1 red marble are chosen is twice the number of possible selections in which 2 red marbles and 1 blue marble are chosen.
The positive integers 𝐵 and 𝑅 that Alejandra determined must be such that 𝐵 is the number that is ___
1___ the number that is ___
2___ 𝑅.
Based on the information provided, select for
1 and for
2 the options that create the most accurate statement. Make only two selections, one in each column.
We need to translate this into an equation:
"the number of possible selections in which 2 blue marbles and 1 red marble are chosen is twice the number of possible selections in which 2 red marbles and 1 blue marble are chosen."
For the 2 blue and 1 red, note that "And" means "multiply". We are choosing 2 blue out of B total blue marbles, and 1 red out of R total red marbles. Let's use this timesaving formula for combinations, when we are choosing 2 out of N: (NC2) = \(\frac{N(N-1) }{ 2}\). (This formula for "pairs" can come up in other contexts, such as handshakes or games played between 2 teams.)
(BC2) * (RC1) = \(\frac{B(B-1) }{ 2} \) * R
For the 2 red and 1 blue, we use the same method:
(RC2) * (BC1) = \(\frac{R(R-1) }{ 2} \) * B
Then, let's set up our full equation. It says that 2 blue and 1 red is twice the number for 2 red and 1 blue:
\(\frac{B(B - 1) }{ 2} \) * R = 2 * \(\frac{R(R - 1) }{ 2} \) * B
We simplify, by crossing off the B and R on both sides, and 2 on the bottom on both sides:
(B - 1)= 2(R - 1)
B = 2R - 1Finally, we read carefully and double-check that we are filling in the blanks correctly, so that it matches our equation:
"𝐵 is the number that is ___1___ the number that is ___2___ 𝑅."B is 1 less than the number that is twice R.