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so the question asks to find an APPROXIMATE value? You could have mentioned that in question

It is not approximate value.

\(\frac{57}{150}*100\) is exactly \(= 38\)%.

Please check the calculation.
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rma26
so the question asks to find an APPROXIMATE value? You could have mentioned that in question

It is not approximate value.

\(\frac{57}{150}*100\) is exactly \(= 38\)%.

Please check the calculation.

Do you have a quick way of getting the percentage from 57/150? I got that part relatively quickly but I had trouble getting 38.

Posted from my mobile device
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gmathopeful19
sashiim20
rma26
so the question asks to find an APPROXIMATE value? You could have mentioned that in question

It is not approximate value.

\(\frac{57}{150}*100\) is exactly \(= 38\)%.

Please check the calculation.

Do you have a quick way of getting the percentage from 57/150? I got that part relatively quickly but I had trouble getting 38.

Posted from my mobile device

Reduce by 3 to get 19/50, which is the same as 38/100.
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Hi Bunuel

can you please help me in understanding why it it out of 150 not 200?
what percent of the cars without air conditioners had traction control systems?

AC AC'
TC 6 57 63
TC' 44 93 137
50 150 200

why it is not (57/200)*100?
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Bunuel
Official Solution:

Among the 200 cars displayed at an auto show, 50 had built-in air conditioners and 63 had traction control systems. If 12% of cars with air conditioners had traction control systems, what percent of the cars without air conditioners had traction control systems?

A. 35
B. 36
C. 38
D. 40
E. 45

Of the 50 cars with air conditioners, 6 (\(12\%\) of \(50 = \frac{50}{100}*12 = 6\)) had traction control systems. This means that \(63 - 6 = 57\) cars had traction control systems but did not have air conditioners. As there were \(200 - 50 = 150\) cars without air conditioners, the answer to the question is \(\frac{57}{150}*100\% = 38\%\).

Answer: C


Hi Bunuel

can you please help me in understanding why it it out of 150 not 200?
what percent of the cars without air conditioners had traction control systems?

AC AC'
TC 6 57 63
TC' 44 93 137
50 150 200

why it is not (57/200)*100?

The question asks: what percent of the cars without air conditioners had traction control systems?

So, we need (cars without air conditioners but with air conditioners)/(cars without air conditioners) = 57/150.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I like the solution - it’s helpful.
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