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Amy and Jed are among 35 people, who are standing in a line, on behind 03 Dec 2019, 02:09
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D
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68% (02:44) correct 32% (02:41) wrong based on 197 sessions

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Amy and Jed are among 35 people, who are standing in a line, on behind the other, waiting to buy movie tickets. The number of people in front of Amy plus the number of people behind Jed is 24. If there are 15 people behind Amy, including Jed, how many people are in front of Jed?

A. 23

B. 25

C. 27

D. 29

E. 31
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D
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Amy and Jed are among 35 people, who are standing in a line, on behind 03 Dec 2019, 02:21
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Bunuel
Amy and Jed are among 35 people, who are standing in a line, on behind the other, waiting to buy movie tickets. The number of people in front of Amy plus the number of people behind Jed is 24. If there are 15 people behind Amy, including Jed, how many people are in front of Jed?

A. 23

B. 25

C. 27

D. 29

E. 31
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Explanation: Number of People Ahead & Behind Amy & Jed = 24
Total people = 35
Number people in front of Between Zed & Amy = 33-24 = 9
We know including fed, 15 are behind amy. = 14-9 = 5
So 5 are behind Jed, esle all are in front of JED i.e. 29
IMO-D
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Amy and Jed are among 35 people, who are standing in a line, on behind 04 Dec 2019, 00:14
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Number of people in front of Amy = Total - Number of people behind Amy - Amy = 35-15-1=19

We are also given that

Number of people in front of Amy + Number of people behind Jed = 24

So, 19 + Number of people behind Jed = 24

Number of people behind Jed = 24-19 = 5

Therefore, Number of people in front of Jed = Total - Number of people behind Jed - Jed = 35-5-1 = 29

Answer is (D)
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Amy and Jed are among 35 people, who are standing in a line, on behind 17 May 2021, 06:47
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Bunuel
Amy and Jed are among 35 people, who are standing in a line, on behind the other, waiting to buy movie tickets. The number of people in front of Amy plus the number of people behind Jed is 24. If there are 15 people behind Amy, including Jed, how many people are in front of Jed?

A. 23

B. 25

C. 27

D. 29

E. 31
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We are told that Jed is standing behind Amy.

Let x = number of people behind Jed
Let y = number of people ahead of Jed but behind Amy
Let z = number of people ahead of Amy


So, our diagram looks like this: BACK|-----x people----JED------y people------AMY----z people------|FRONT

Amy and Jed are among 35 people
We can write: x + y + z + Jed + Amy = 35 people
In other words, x + y + z + 2 = 35
Simplify: x + y + z = 33

The number of people in front of Amy plus the number of people behind Jed is 24.
We can write: x + z = 24

There are 15 people behind Amy, including Jed
x + y + Jed = 15
In other words: x + y + 1 = 15
Or: x + y = 14

Take:
x + y + z = 33
x + z = 24

Subtract the bottom equation from the top equation to get: y = 9

Take: x + y = 14
Since y = 9, we know that x = 5

Take: x + y + z = 33
Since y = 9 and x = 5, we know that z = 19

We have: BACK|-----5 people----JED------9 people------AMY----19 people people------|FRONT

How many people are in front of Jed?
The number of people in front of Jed = y + AMY + z
= 9 + AMY + 19
= 29

Answer: D

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Brent
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Amy and Jed are among 35 people, who are standing in a line, on behind 10 Nov 2022, 09:13
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Given

  • There are 35 people including Amy and Jed
  • Amy is in front of Jed, not necessarily in immediate front.

Let's say the line looks as follows

-------x people------- Amy ------- z people ------- Jed ------- y people-------

Question = z + x + 1 ?

Amy and Jed are among the 35 people

x + y + z + 2 = 35

x + y + z = 33 ---(1)

The number of people in front of Amy plus the number of people behind Jed is 24

x + y = 24 ---(2)

There are 15 people behind Amy, including Jed

z + 1 + y = 15

z + y = 14 ---(3)

(1) + (2)

x + y + z + y = 38

y = 38 - 35 = 5

x = 24 - 5 = 19

Therefore 19 + 5 + 1 = 29

IMO D
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Amy and Jed are among 35 people, who are standing in a line, on behind 20 May 2024, 06:08
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