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An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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30 Jul 2015, 10:18
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An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc? A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3 Kudos for a correct solution.
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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30 Jul 2015, 10:26
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. Alloy1: Copper: Zinc = 5:3, Let Quantity = x i.e. Copper in Alloy1 = [5/(5+3)]*x = (5/8)x and Zinc in Alloy1 = [3/(5+3)]*x = (3/8)xAlloy2: Copper: Zinc = 1:7, Let Quantity = y i.e. Copper in Alloy2 = [1/(1+7)]*y = (1/8)y and Zinc in Alloy1 = [7/(1+7)]*y = (7/8)yAfter Combining the two alloys Copper = (5/8)x + (1/8)y Zinc = (3/8)x + (7/8)y Now, (5x + y)/8 = (3x + 7y)/8 i.e. 2x = 6y i.e. x = 3y i.e. x/y = 3/1 Answer: option D
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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30 Jul 2015, 14:16
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. IMO: D Cu:zn = 5:3 Cu:zn = 1:7 Thus in 1st alloy in total of 8(5+3) parts 5 parts contain copper ==> Cu1 = 5/8 In 2nd alloy in total of 8(1+7) parts 1 part contains copper ==> Cu2 = 1/8 After combining Cu: Zn = 1:1 In final combination in total of 2 parts 1 part contain copper ==> 1/2 Attachment:
1.jpg [ 19.2 KiB  Viewed 65534 times ]
Thus Cu2 : Cu1 = 1:3 The ratio of Alloy1 : Alloy2 is asked = 3:1




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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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31 Jul 2015, 01:01
simple mixtures problem.
5x + y = 3x + 7y (since quantity of Cu and Zn in resultant mixture is equal)
2x = 6y x = 3y
Ans. = D



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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31 Jul 2015, 06:31
Let Alloy_1 be x units, and let Alloy_2 be y units. So, fraction of copper in Alloy_1 = 5x/8, and fraction of zinc in Alloy_1 = 3x/8. Similarly, fraction of copper in Alloy_2 = y/8, and fraction of zinc in Alloy_2 = 7y/8. Mixing them, we get copper = 5x/8 + y/8; zinc = 3x/8 + 7y/8. So, 5x+y = 3x+7y > x = 3y > x/y = 3/1. So, they must be mixed in the ratio 3 : 1. Ans (D).
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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31 Jul 2015, 13:48
Putting together an equation with the numbers  5x+y/ 3x+7y = 1
Solving it out  2x=6y
Hence 3/1
Option D



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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05 Aug 2015, 22:23
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3 Ans: D Solution: While the ratio of Cu and Zn in both the mixture is given but not the quantity. so we assume that M1 is x, and M2 is y. now we know in M1= 5x/8 Cu, 3x/8 Zn in M2 y/8 Cu and 7y/8 now we want to make the total quantity of Cu and Zn equal use the following data and make equation 5x/8 + y/8 = 3x/8 + 7y/8 it gives x = 3y so the ratio must be x:y = 3y:y = 3:1
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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14 Oct 2015, 23:56
let ratio of 1st alloy and 2nd alloy in 3rd mixture=k:1 5k+1=3k+7 k=3 ans 3:1 (D)



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An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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Updated on: 08 Mar 2018, 22:04
An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
let x=alloy 1 y=alloy 2 (5x/8)+y/8=4(x+y)/8 x/y=3 3:1 D
Originally posted by gracie on 23 Jan 2017, 09:44.
Last edited by gracie on 08 Mar 2018, 22:04, edited 1 time in total.



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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08 Mar 2018, 20:22
Hi All, Beyond the algebra that can be used here, there are often other approaches that are fairly straightforward (and sometimes faster/easier than doing "math"). Since the answers provide 5 ratios for us, we can use them "against" the information in the prompt to find the one ratio that gives us an equal proportion of copper and zinc. Let's TEST THE ANSWERS: The two ratios… C:Z 5:3 and C:Z 1:7 Answer A: 1:5 gives us (5C + 3Z) + (5C + 35Z) > 10C and 38Z > NOT a match Answer B: 7:3 gives us (35C + 21Z) + (3C + 21Z) > 38C + 42Z > NOT a match Answer C: 5:3 gives us (25C + 15Z) + (3C + 21Z) > 28C + 36Z > NOT a match Answer D: 3:1 gives us (15C + 9Z) + (1C + 7Z) > 16C + 16Z > This IS a match Answer E: 4:3 gives us (20C + 12Z) + (3C + 21Z) > 23C + 33Z > NOT a match Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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12 Mar 2018, 15:33
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3 We can let the ratio of the first alloy of copper to zinc = 5x: 3x We can let the ratio of the second alloy of copper to zinc = y : 7y We can create the equation: 5x + y = 3x + 7y 2x = 6y x = 3y x/y = 3/1 Answer: D
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An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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14 Jun 2020, 20:08
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. Hi VeritasKarishma , I was trying to solve this using weighted average and here is what I did: The final mixture contains alloy in the ratio 1:1 \(\frac{W1}{W2}\) = \((\frac{5}{3}1)/(1\frac{1}{7})\) \(\frac{W1}{W2} = \frac{7}{9}\) Can you please tell where did I go wrong ?



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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14 Jun 2020, 20:23
ShreyKapil08 wrote: Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. Hi VeritasKarishma , I was trying to solve this using weighted average and here is what I did: The final mixture contains alloy in the ratio 1:1 \(\frac{W1}{W2}\) = \((\frac{5}{3}1)/(1\frac{1}{7})\) \(\frac{W1}{W2} = \frac{7}{9}\) Can you please tell where did I go wrong ? I think I understand where I went wrong. I should not use the ratio copper is to alloy as is. It should be "part" by "whole". \(\frac{W1}{W2}\) = \((\frac{5}{8}\frac{1}{2})/(\frac{1}{2}\frac{1}{8})\) \(\frac{W1}{W2} = \frac{1}{3}\)



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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16 Jun 2020, 21:22
ShreyKapil08 wrote: ShreyKapil08 wrote: Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. Hi VeritasKarishma , I was trying to solve this using weighted average and here is what I did: The final mixture contains alloy in the ratio 1:1 \(\frac{W1}{W2}\) = \((\frac{5}{3}1)/(1\frac{1}{7})\) \(\frac{W1}{W2} = \frac{7}{9}\) Can you please tell where did I go wrong ? I think I understand where I went wrong. I should not use the ratio copper is to alloy as is. It should be "part" by "whole". \(\frac{W1}{W2}\) = \((\frac{5}{8}\frac{1}{2})/(\frac{1}{2}\frac{1}{8})\) \(\frac{W1}{W2} = \frac{1}{3}\) Yes, think about the physical quantities you are dealing with  concentration (part/whole), volume, amount Concentration of copper is 5/8 and 1/8 in the two. You need to mix them to get concentration of 1/2. You need to find the ratio of the volumes in which you mix them. Check here: https://www.veritasprep.com/blog/2011/0 ... mixtures/
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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16 Jun 2020, 21:59
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. Amount of copper in 40 gm of mixture=20gm....(1:1, 1/2*40=20) Amount of copper in alloy 1 in 40 gm of mixture=25 gm(5:3..5/8*40=25) Amount of copper in alloy 1 in 40 gm of mixture=5 gm(1:7..1/8*40=5) C2..............C...............C1 5................20.................25 C2/C1=(2520)/(205) =5/15 C1:C2=3:1 D:)



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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17 Jun 2020, 08:13
VeritasKarishma wrote: Yes, think about the physical quantities you are dealing with  concentration (part/whole), volume, amount Concentration of copper is 5/8 and 1/8 in the two. You need to mix them to get concentration of 1/2. You need to find the ratio of the volumes in which you mix them. Check here: https://www.veritasprep.com/blog/2011/0 ... mixtures/Thank you for confirming VeritasKarishma, I did go through the blog you mentioned above and others in the series. I must say I could never approach the Weighted average and mixture problems the way I do now after reading those blogs. Thank you for sharing such an insightful write up.



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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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07 Jul 2020, 05:42
Consider either copper or zinc. I am gonna consider copper here. There are two alloys with ratio 5:3 and 1:7.To make the ratio equal means it should be 4:4. So I am gonna use the quick and simplest way to calculate the ratio. 5 1 4 3 : 1
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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07 Jul 2020, 20:33
Bunuel wrote: An alloy of copper and zinc contains copper and zinc in the ratio 5 : 3. Another alloy of copper and zinc contains copper and zinc in the ratio 1 : 7. In what ratio should the two alloys be mixed so that the resultant alloy contains equal proportions of copper and zinc?
A. 1 : 5 B. 7 : 3 C. 5 : 3 D. 3 : 1 E. 4 : 3
Kudos for a correct solution. Going through the options is the easy approach. 3*(5:3)+1*(1:7)=15:9+1:7=16:16 And that's what we need. Answer D.
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Re: An alloy of copper and zinc contains copper and zinc in the ratio 5 :
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