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As part of a certain game in which a computer generated a ra
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Updated on: 25 Oct 2013, 14:24
Question Stats:
70% (01:50) correct 30% (02:02) wrong based on 63 sessions
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As part of a certain game in which a computer generated a random number several times, 6 more numbers greater than 0 resulted than numbers less than 0. 0 never resulted. How many times was the result greater than zero? (1) 2 more numbers greater than 1 resulted than numbers less than 1. (2) The sum of all the numbers that resulted was 3.75.
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Originally posted by manishuol on 29 Apr 2013, 12:09.
Last edited by Bunuel on 25 Oct 2013, 14:24, edited 1 time in total.
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Re: Computer generated a random number
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01 May 2013, 05:00
Option E.
For every Six positive numbers the computer generates, it will generate a negative number. ( 6 more numbers greater than 0 resulted than numbers less than 0). And 0 is never resulted.
so in a set of 7 numbers the computer generates, there are 6 positive numbers and 1 negative number.
from statement 1: for every 2 numbers greater than 1, it generates a number less than 1. but this doesn't give info about how many times the game is played, hence we cannot determine how many times the numbers generated are >0. insufficient.
from stmt 2: sum of all the number is 3.75. clearly insufficient.
1+2 , again doesnt give any additonal info regarding the number of time the game is played or the values it generated that result in 3.75. so both combined as well insufficient.
hope it is clear.



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Re: Computer generated a random number
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25 Oct 2013, 14:15
Official Explanation from GMAT Hacks
Answer: E The question splits the random numbers into two groups. There are p positive numbers and n negative numbers, and p = n + 6.
Statement (1) is sufficient. This also splits the numbers into two groups, but not the same groups. We can use the information to deduce how many more numbers are greater than zero than greater than one, but because we've only been given differences up to this point, we can't find the actual total. For instance, if there are 10 positive numbers, there are 4 negatives. With a total of 14, that would be 8 greater than 1 and 6 less than 1.
That scenario works, but the differences will remain the same if you add 10 to each number: 20 positives, 14 negatives, 18 greater than 1, and 16 less than 1.
Statement (2) is also insufficient. We know nothing specific about the numbers beyond their range. The answer would be much different if the numbers were closely bunched around 0 and 1 (say, 0.01 or 1.03) than if they were spread further out (say, 3 and 5).
Taken together, we still don't have enough information. Given a set of numbers that consists of a mix of positives and negatives, you can simplify the matter by assuming that many of them could cancel out. For instance, if there are 10 positives and 4 negatives, you could say that 4 of the positives are each 2 and 4 of the negatives are each 2. (That's a sum of 0.) Then you only have to consider the sum of the 6 remaining numbers, not the group of 14 as a whole. It's too timeconsuming to work out a pair of contradictory examples, but since we don't know anything about the size of the numbers, we could construct many different sets that fit the requirements that sum to 3.75. Choice (E) is correct.



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Re: As part of a certain game in which a computer generated a ra
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11 Apr 2019, 19:04
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Re: As part of a certain game in which a computer generated a ra
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