NEW HERE? LEARN MORE
closeclose
Last visit was: 25 Apr 2024, 16:27 It is currently 25 Apr 2024, 16:27
Decision Tracker
My Rewards
New posts
New comers' posts

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel

At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship

SORT BY:
Date
Kudos
Tags:
Find Similar Topics 
Show Tags
Hide Tags
User avatar
L
Bunuel
Math Expert
Joined: 02 Sep 2009
Posts: 92915
Own Kudos [?]: 619022 [9]
Given Kudos: 81595
Send PM
CAT Tests Forum Quiz Mode
At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   Updated on: 10 Jul 2019, 05:00
9
Bookmarks
Expert Reply
00:00
A
B
C
D
E

Difficulty:

15% (low)

Question Stats:

81% (01:48) correct 19% (02:21) wrong based on 232 sessions
Hide Show timer Statistics
At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship B leaves the same port in the same direction traveling 25 mph. At what time does Ship B pass Ship A?

(A) 8:30 PM
(B) 8:35 PM
(C) 9 PM
(D) 9:15 PM
(E) 9:30 PM

Source: Nova GMAT
Difficulty Level: 550
ShowHide Answer
Official Answer
A

Originally posted by Bunuel on 28 May 2017, 03:32.
Last edited by Sajjad1994 on 10 Jul 2019, 05:00, edited 1 time in total.
Added Source
Most Helpful Reply
User avatar
B
MvArrow
Manager
Manager
Joined: 06 Sep 2016
Posts: 107
Own Kudos [?]: 56 [12]
Given Kudos: 100
Location: Italy
Schools: EDHEC (A$)
GMAT 1: 650 Q43 V37
GPA: 3.2
WE:General Management (Human Resources)
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   28 May 2017, 06:04
9
Kudos
3
Bookmarks
We can also use the GAP approach.

Ship A in 3hrs travels 45km
Ship B has to close that GAP.

Rate(B) - Rate(A) = 25 - 15 = 10mph

Then we can set up the following equation

45 = 10T
T= 45/10 ---> 9/2 hence 4,5hrs

So the time required is 1pm + 3 + 4,5 hrs = 8.30 therefore A.
General Discussion
User avatar
P
Luckisnoexcuse
Current Student
Joined: 18 Aug 2016
Posts: 531
Own Kudos [?]: 577 [1]
Given Kudos: 198
Concentration: Strategy, Technology
Schools: Kenan-Flagler '20 (M)
GMAT 1: 630 Q47 V29
GMAT 2: 740 Q51 V38
Send PM
GMAT ToolKit User Reviews Badge
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   28 May 2017, 03:37
1
Bookmarks
Ship A travels 112.5 Km( 15 *7.5) in 7:30 hrs (from 1 PM to 8:30 PM) Ship B travels 112.5(25*4.5) Km in 4:30 hrs

hence option A


Sent from my iPhone using GMAT Club Forum
User avatar
S
mohshu
Senior Manager
Senior Manager
Joined: 21 Mar 2016
Posts: 448
Own Kudos [?]: 117 [1]
Given Kudos: 103
Send PM
Reviews Badge
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   29 May 2017, 03:48
1
Kudos
MvArrow wrote:
We can also use the GAP approach.

Ship A in 3hrs travels 45km
Ship B has to close that GAP.

Rate(B) - Rate(A) = 25 - 15 = 10mph

Then we can set up the following equation

45 = 10T
T= 45/10 ---> 9/2 hence 4,5hrs

So the time required is 1pm + 3 + 4,5 hrs = 8.30 therefore A.


Gud one..
+1 for this method
User avatar
P
amanvermagmat
Retired Moderator
Joined: 22 Aug 2013
Posts: 1186
Own Kudos [?]: 2499 [2]
Given Kudos: 459
Location: India
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   29 May 2017, 04:13
1
Kudos
1
Bookmarks
Let them meet 'n' hours after 4 pm. From 1 to 4 pm, ship A has already travelled = 15*3 = 45 miles
So in 'n' hours, A has total travelled = (45 + 15n) miles
and B has travelled = 25n miles

Since they meet at that time, distances should be equal OR 45+15n = 25n
Solving we get n=4.5

So the ships meet 4.5 hours after 4 pm, OR at 8.30 pm
Option A is the answer
User avatar
L
pushpitkc
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 2873
Own Kudos [?]: 5205 [0]
Given Kudos: 47
Location: India
GPA: 3.12
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   29 May 2017, 04:26
Since, the ship A leaves three hours early and travels 15 mph, it would have traveled 45 miles.

Now the speed relative to Ship B, which travels at 25 mph is 10 miles/hour
Since the distance it need to cover up is 45 miles, time take can be given by formula
Time taken = Distance to cover/Relative Speed
= \(\frac{45}{10}\) = 4.5 hours.

Since the ship B leaves port at 4 PM, it would meet Ship A exactly 4.5 hours later(at 8:30 PM) (Option A)
User avatar
B
MvArrow
Manager
Manager
Joined: 06 Sep 2016
Posts: 107
Own Kudos [?]: 56 [1]
Given Kudos: 100
Location: Italy
Schools: EDHEC (A$)
GMAT 1: 650 Q43 V37
GPA: 3.2
WE:General Management (Human Resources)
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   29 May 2017, 11:09
1
Bookmarks
mohshu wrote:
MvArrow wrote:
We can also use the GAP approach.

Ship A in 3hrs travels 45km
Ship B has to close that GAP.

Rate(B) - Rate(A) = 25 - 15 = 10mph

Then we can set up the following equation

45 = 10T
T= 45/10 ---> 9/2 hence 4,5hrs

So the time required is 1pm + 3 + 4,5 hrs = 8.30 therefore A.


Gud one..
+1 for this method


Thank you very much :-D
avatar
B
ShreyansJ
Intern
Intern
Joined: 03 Nov 2016
Posts: 18
Own Kudos [?]: 3 [0]
Given Kudos: 23
Location: United Kingdom
Schools: IIMA
GMAT 1: 620 Q47 V30
GMAT 2: 710 Q48 V39
Send PM
GMAT ToolKit User Reviews Badge
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   30 May 2017, 02:01
Option A: 8.30 PM

A @ 1PM, 15 MPH
B @4PM (3 hrs later), 25 MPH. by the time B starts, A would have travelled 45 miles (15MPH * 3 H)
So, as A is moving away from B, the combined rate would be = 25 - 15 = 10 MPH and the distance to be covered is 45 miles.
Time = 45/10 hrs = 4.5
so, 4 PM + 4.5 = 8.30 PM.
User avatar
L
ScottTargetTestPrep
Target Test Prep Representative
Joined: 14 Oct 2015
Status:Founder & CEO
Affiliations: Target Test Prep
Posts: 18761
Own Kudos [?]: 22052 [0]
Given Kudos: 283
Location: United States (CA)
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   01 Jun 2017, 10:21
Expert Reply
Bunuel wrote:
At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship B leaves the same port in the same direction traveling 25 mph. At what time does Ship B pass Ship A?

(A) 8:30 PM
(B) 8:35 PM
(C) 9 PM
(D) 9:15 PM
(E) 9:30 PM


We can let the time traveled by Ship A = t + 3 and time traveled Ship B = t.

Since Ship A is traveling at a rate of 15 mph, the distance of Ship A = 15(t + 3) = 15t + 45, and since Ship B is traveling at a rate of 25 mph, the distance of Ship B = 25t.

Let’s now determine t:

Ship A’s distance = Ship B’s distance

15t + 45 = 25t

45 = 10t

45/10 = 9/2 = 4.5 hours = t

Recall that Ship B left port at 1 p.m + 3 hours = 4 p.m. Thus, Ship B passes Ship A at 4 p.m + 4.5 hours = 8:30 p.m.

Answer: A
User avatar
S
Nunuboy1994
Director
Director
Joined: 12 Nov 2016
Posts: 569
Own Kudos [?]: 118 [0]
Given Kudos: 167
Location: United States
Schools: Yale '18
GMAT 1: 650 Q43 V37
GRE 1: Q157 V158
GPA: 2.66
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   13 Aug 2017, 13:56
Bunuel wrote:
At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship B leaves the same port in the same direction traveling 25 mph. At what time does Ship B pass Ship A?

(A) 8:30 PM
(B) 8:35 PM
(C) 9 PM
(D) 9:15 PM
(E) 9:30 PM


15( T +3) =25T
15T +45 =25T
45=10T
T=4.5

4pm + 4 hr 30 m

8 30 pm

A
User avatar
G
Basshead
Director
Director
Joined: 09 Jan 2020
Posts: 966
Own Kudos [?]: 223 [0]
Given Kudos: 434
Location: United States
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   17 Oct 2020, 11:46
15 ( T + 3) = 25T
15T + 45 = 25T
45 = 10T
T = 4.5

It takes 4.5 hours for Ship B to catch up to Ship A.
User avatar
bumpbot
Non-Human User
Joined: 09 Sep 2013
Posts: 32679
Own Kudos [?]: 822 [0]
Given Kudos: 0
Send PM
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink] New post   14 Oct 2022, 11:26
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
GMAT Club Bot
gmatclubot
Re: At 1 PM, Ship A leaves port traveling 15 mph. Three hours later, Ship [#permalink]
14 Oct 2022, 11:26
Moderators:
Bunuel
Math Expert
92915 posts
yashikaaggarwal
Senior Moderator - Masters Forum
3137 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne
Main navigation
GMAT Resources
Partners
MBA Resources
www.gmac.com|www.mba.com | | GMAT Club Rules | Terms and Conditions