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At a certain picnic, each of the guests was served either a
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At a certain picnic, each of the guests was served either a [#permalink] New post  19 Oct 2005, 09:04
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At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?

(1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.
(2) A total of 120 scoops of ice cream were served to all the guests at the picnic.

OPEN DISCUSSION OF THIS QUESTION IS HERE: at-a-certain-picnic-each-of-the-guests-was-served-either-a-90254.html
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chets
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[#permalink] New post  19 Oct 2005, 09:14
C)

how many were served double scoops? let number of people served double scoops = x, number of people served single scoops = y.
x=?

statement I: 60% were served double scoops. (x+y)*60/100 = x. or y=2x/3. insufficient.

statement II: total scoops = 120. number of single scoops + number of double scoops = 120. 2*x+y=120. insufficient.

together, 2x+y=120 and y=2x/3, so x = 45. 45 people were served double scoops.
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ywilfred
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[#permalink] New post  19 Oct 2005, 20:30
Total # of guests = n

From (1), 60%*n got double scoops, but we have no value for n. So (1) is not sufficient.

From (2), we have no useful information here. (2) is not sufficient.

Using both (1) and (2), we can equate 60%*n*2 + 40%*n*1 = 120 and solve for n.

Ans: C
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mahesh004
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[#permalink] New post  20 Oct 2005, 10:54
X is single scoop, Y is double scoop

X + 2Y = 120
Y/X + Y = 60/100
100Y = 60X + 60Y
40Y = 60X
Y = 3/2X
X = 30
Y = 45
Answer: C
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ywilfred
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[#permalink] New post  15 May 2006, 01:10
Assume number of people = x

St1:
0.6x --> double scoops
0.4x --> single scoop

Insufficient as we cannot solve for x

St2:
Insufficient as we cannot break down the number of people who were served double scoops and the number of people who were served single scoops.

St1 and St2:
0.6x(2) + 0.4x = 120

Sufficient as we can solve for x, and thus 0.6x.

Ans C
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gmatmba
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[#permalink] New post  15 May 2006, 12:43
At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?
(1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.
(2) A total of 120 scoops of ice cream were served to all the guests at the picnic


(1) We dont know total # of guests, so not sufficient

(2) not sufficient either

Taking both together:

Let there be x guests,
(0.6x*2) + 0.4x = 120
Solving, x=75 guests

Hence C
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x2suresh
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Re: Arithmetic Percent [#permalink] New post  13 Dec 2008, 19:35
above720 wrote:
This question is no. 55 in the DS Section of The Official Guide GMAT Review (11th Ed):

At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?

(1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.

(2) A total of 120 scoops of ice cream were served to all the guests at the picnic.

Besides obtaining the answer, can someone please explain how you would come up with the total number of guests at the picnic (if this was instead a problem solving question with the 2 details provided after the question stem)?


assume x= total number of guests

x*0.6*2 (2 scoops)+ x*0.4* 1(1 scoop) =120
x 1.6=120
x= 75
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Re: Arithmetic Percent [#permalink] New post  14 Dec 2008, 08:09
At a certain picnic, each of the guests was served either a single scoop or a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?

(1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.

(2) A total of 120 scoops of ice cream were served to all the guests at the picnic.

from 1.......insuff
from2
insuff

both

120 = 1.2x+0.4x.........suff..........c
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Re: DS: Picnic, Ice Cream [#permalink] New post  28 Sep 2009, 06:09
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yangsta8 wrote:
At a certain picnic, each of the guests was served either a single scoop of a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?

1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.
2) A total of 120 scoops of ice cream were served to all the guests at the picnic.


x - single scoop, y - double scoops. the question asks about y.

1: insufficient, only ratio y/(x+y) given
2: insufficient (x+2*y = 120, can't calculate y)

1+2: sufficient
y = 0.6*(x+y)
x+2*y = 120 -> sufficient to calculate y -> C
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Re: DS: Picnic, Ice Cream [#permalink] New post  30 Sep 2009, 06:29
hmm.pretty surprised..I somehow remember seeing a diff. solution somewhere..anyways this is an OG question so the OA C must be correct.
IMO I got B.
Single scoop=x
Double scoop=x+x=2x
This makes stmt 2: 3x=120 making it suff..
HUh>??
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abhivarma03
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Re: DS: Picnic, Ice Cream [#permalink] New post  02 Oct 2009, 04:03
I would like to know,whether the number of scoops can be divided in a way other than
Single=40
Double=40

That makes the total scoops equal to 120
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duttarupam
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Re: DS: Picnic, Ice Cream [#permalink] New post  03 Oct 2009, 04:42
yangsta8 wrote:
At a certain picnic, each of the guests was served either a single scoop of a double scoop of ice cream. How many of the guests were served a double scoop of ice cream?

1) At the picnic, 60 percent of the guests were served a double scoop of ice cream.
2) A total of 120 scoops of ice cream were served to all the guests at the picnic.


IMO E

The Q doesn't say whether any quest has been serverd 2 scoops of double scoop or single scoop.
:lol:
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 09:46
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At a certain picnic, each of the guests was served either a single scoop or a double scoop ice-cream. How many of the guests were served a double scoop of ice-cream?

(1) At the picnic, 60 percent of the guests were served a double scoop of ice-cream --> \(\frac{x}{y}=\frac{4}{6}=\frac{2}{3}\), where \(x\) is the # of people served single scoop and \(y\) the # of people served double scoop. Clearly insufficient to calculate single numerical value of \(y\).

(2) A total of 120 scoops of ice-cream were served to all the guests at the picnic --> \(1*x+2*y=120\). Again not sufficient.

(1)+(2) \(x=\frac{2}{3}y\) and \(x+2y=120\) --> \(\frac{2}{3}y+2y=120\) --> \(y=45\). Sufficient.

Answer: C.
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 09:53
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At a certain picnic, each of the guests was served either a single scoop or a double scoop ice-cream. How many of the guests were served a double scoop of ice-cream?

All guests = guests served a single scoop ice-cream + guests served a double scoop ice-cream

1) At the picnic, 60 percent of the guests were served a double scoop of ice-cream.

It is just percent but we need numbers. Insufficient.

2) A total of 120 scoops of ice-cream were served to all the guests at the picnic.

So, we know that All guests = 120 but it still insufficient.

1)&2) We know from first statement that the number of guests served a double scoop of ice-cream is 60% of the number of all guests. Therefore, we take 120 from second statement and get 0.6*120 = 72.

Hope it helps
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 09:58
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walker wrote:
At a certain picnic, each of the guests was served either a single scoop or a double scoop ice-cream. How many of the guests were served a double scoop of ice-cream?

All guests = guests served a single scoop ice-cream + guests served a double scoop ice-cream

1) At the picnic, 60 percent of the guests were served a double scoop of ice-cream.

It is just percent but we need numbers. Insufficient.

2) A total of 120 scoops of ice-cream were served to all the guests at the picnic.

So, we know that All guests = 120 but it still insufficient.

1)&2) We know from first statement that the number of guests served a double scoop of ice-cream is 60% of the number of all guests. Therefore, we take 120 from second statement and get 0.6*120 = 72.

Hope it helps


Walker I think statement (2) is saying that "120 scoops of ice-cream were served" not that the total # of guests were 120. Am I interpreting the statement in the wrong way?
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 10:20
@Bunuel: Thanks man, I found your answer explanatory.

i found i was doing some stupid mistakes while solving this :)

@ walker: i have a Question, how can we assume total # of Guests = total # of scoops?
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 10:46
amod243 wrote:
@Bunuel: Thanks man, I found your answer explanatory.

i found i was doing some stupid mistakes while solving this :)

@ walker: i have a Question, how can we assume total # of Guests = total # of scoops?


st 1 indicates total scoops of ice cream and its different from total number of guests
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 16:06
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You are right, guys, my bad
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 17:12
walker wrote:
You are right, guys, my bad


And yet, you got away with a 50 on Quant?? Man, this is unfair!!!!

{J/K}
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Re: OG-12 DS Problem # 61 [#permalink] New post  09 Feb 2010, 18:21
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Yeah, I know. Q51 would be better :)
By the way, one very silly mistake on my real GMAT led me to Q50.... So, be very careful....
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Re: OG-12 DS Problem # 61 [#permalink]
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