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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
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rohanadagouda23 wrote:
Bunuel Can you explain the solution ?
TIA


At a particular school, 60 male students play sports. How many male students attend the school?
let male = m and female = f
we require to know male students who do not play game to find m...


Lets see the statements--



(1) At the school, 3/4 of the female students play sports.
so \(\frac{3}{4} f\)play sports and 60 male students play sports..
so tOTAL who play games = 3/4 f + 60
Nothing about male students who do not play game
Insuff

(2) At the school, 1/4 of the students do not play sports.
now we know 3/4 of total students play game..
But we do not know the ratio of f:m..
Insuff

Combined--
we know ONLY 3/4 of Total play games and ALSO from (1) 3/4 of 'f' play game
\(\frac{3}{4} (T) = \frac{3}{4} (f+m) = \frac{3}{4} m + \frac{3}{4} f\)...
also from (1) this is equal to \(\frac{3}{4} f + 60\)..
so \(\frac{3}{4} m + \frac{3}{4} f = \frac{3}{4} f + 60\).
OR 3/4 m = 60 or m= 60*4/3=80
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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
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rohanadagouda23 wrote:
Bunuel Can you explain the solution ?
TIA


At a particular school, 60 male students play sports. How many male students attend the school?

(1) At the school, 3/4 of the female students play sports. Not sufficient.
(2) At the school, 1/4 of the students do not play sports. Not sufficient.

(1)+(2) When combining we have the following:


Notice that we should find the number of male students which is Total - Females, yellow box (T-F).

Write equation for Sports column: 60 + 3/4*F = 3/4*T --> T - F = 80. Sufficient.

Answer: C.

Hope it's clear.

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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
Why it cant be B

3/4 of total play sport, so if there are m males and f females then 3/4(m+f) play sports ie. 3/4m +3/4f

however we know 60 males play sports so 3/4m =60 and m =80
We dont need A for that.
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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
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varundixitmro2512 wrote:
Why it cant be B

3/4 of total play sport, so if there are m males and f females then 3/4(m+f) play sports ie. 3/4m +3/4f

however we know 60 males play sports so 3/4m =60 and m =80
We dont need A for that.


That's not correct. Yes, we know that 3/4 of total play sports but it does NOT mean that 3/4 of males play sport.
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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
Bunuel wrote:
At a particular school, 60 male students play sports. How many male students attend the school?

(1) At the school, 3/4 of the female students play sports.
(2) At the school, 1/4 of the students do not play sports.



Here is my logic, please let me know if there are any flaws in this.


(1) No info about male students. Insufficient
(2) Cannot make any inferences about the number of male students either. Insufficient.

Combined: Statement 1 tells us that 3/4 females play sports and statement 2 tells us that 3/4 of the all students play sports.
For 3/4 ratio of females to be maintained on the whole school level, we need male students to have the same ratio. Any other ratio would change prove statement 2 wrong. Which tells us that 3/4 male students play sports.

Answer:C
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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
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Re: At a particular school, 60 male students play sports. How many male st [#permalink]
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