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Boat Question on GMATPrep

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Boat Question on GMATPrep [#permalink]

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New post 26 Jul 2009, 14:06
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I can't seem to setup this question properly to solve it. Maybe I'm looking at it incorrectly:

A boat traveled upstream a distance of 90 miles at an average of (v-3) miles per hour and then traveled the same distance downstream at an average speed of (v+3) miles per hour. If the trip upstream took half an hour longer than the trip downstream, how many hours did it take the boat to travel downstream?

The way I have this setup is using formula: D = speed * time

Upstream: 90 = (v-3)*(t + 0.5 hr)
Downstream: 90 = (v+3)*t

I'm trying to solve for t but it's getting more complicated than I expected. Can someone see what I'm doing wrong? Thanks,
danswer

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Re: Boat Question on GMATPrep [#permalink]

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New post 26 Jul 2009, 14:47

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Re: Boat Question on GMATPrep [#permalink]

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New post 27 Jul 2009, 11:11
Thanks mate...will do a search before I post. I bet every question on GMATPrep is posted :-)

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Re: Boat Question on GMATPrep [#permalink]

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New post 27 Jul 2009, 15:05
danswer wrote:
Thanks mate...will do a search before I post. I bet every question on GMATPrep is posted :-)


Search is a great tool especially if you need a quick turnaround. Most if not all of the of the challenging GMAT Prep questions have been answered in the past. There are a few ways to search:

1. Use the Custom Google search available on the top of GMAT Club forum pages.

2. This one is my personal favorite as I use Google Chrome for browsing. In the address bar of Chrome (or any other google search toolbar) type in your search criteria followed by site:gmatclub.com

e.g. A boat traveled upstream a distance of 90 miles site:gmatclub.com

This will use the google search but limit it to just the gmatclub.com website. I am not sure why but many times I get better results this way then using the custom google search.

3. Advanced search accessed by clicking on the 'Search' link next to 'User Control Panel' link on all forum pages.

Option 3 tends to provide a larger result set compared to 1 and 2.

I hope this helps.

Regards,

Nookway

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Re: Boat Question on GMATPrep [#permalink]

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New post 27 Jul 2009, 17:24
make an equation like this, without the usage of t...90/(v - 3) = 90 / ( v + 3) +0.5

90v+270 - 0.5(v^2 - 9) = 90 v - 270

540 - 0.5(v^2 - 9) = 0

1080 - v ^ 2 + 9 = 0

v^2 = 1089

v = 33mph

90/27 = 10/3 = 3.33hr

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Re: Boat Question on GMATPrep   [#permalink] 27 Jul 2009, 17:24
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