Hi can you help me with clarity on the second step after squaring the equation? how did the first term change to (4 - \sqrt{15}) from ((\sqrt{4-\sqrt{15}})
Question 30 - Official Solution:What is the value of \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\) ? A. \(-4\)
B. \(-2\)
C. \(-1\)
D. \(1\)
E. \(2\)
We want to find the value of the expression \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\). To simplify this expression, we can start by squaring it.
\(=((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10}))^2=\)
\(=(4-\sqrt{15})(4 + \sqrt{15})^2(\sqrt{6} - \sqrt{10})^2=\)
\(=(4-\sqrt{15})(4 + \sqrt{15})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})^2=\)
Applying the difference of squares identity \((a - b)(a+b)=a^2-b^2\) to \((4-\sqrt{15})(4 + \sqrt{15})\) we can simplify to:
\(=(16 -15)(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})^2=\)
Now using the identity \((a - b)^2=a^2-2ab+b^2\) to simplify the squared term::
\(=(4 + \sqrt{15})(6 - 2\sqrt{60}+10)=\)
\(=(4 + \sqrt{15})(16 - 4\sqrt{15})=\)
\(=(4 + \sqrt{15})4(4 - \sqrt{15})=\)
\(=4(16-15)=4\).
Since the square of the expression is 4, the expression itself must be either 2 or -2. However, since the product of two positive terms and one negative term is negative (\((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})=positive*positive*negative=negative\)), we know that \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\) is negative. Therefore, the final answer is -2.
Answer: B