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Bunuel
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Yug1812
Hi can you help me with clarity on the second step after squaring the equation? how did the first term change to (4 - \sqrt{15}) from ((\sqrt{4-\sqrt{15}})

Bunuel
Question 30 - Official Solution:

What is the value of \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\) ?

A. \(-4\)
B. \(-2\)
C. \(-1\)
D. \(1\)
E. \(2\)


We want to find the value of the expression \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\). To simplify this expression, we can start by squaring it.


\(=((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10}))^2=\)

\(=(4-\sqrt{15})(4 + \sqrt{15})^2(\sqrt{6} - \sqrt{10})^2=\)

\(=(4-\sqrt{15})(4 + \sqrt{15})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})^2=\)

Applying the difference of squares identity \((a - b)(a+b)=a^2-b^2\) to \((4-\sqrt{15})(4 + \sqrt{15})\) we can simplify to:


\(=(16 -15)(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})^2=\)

Now using the identity \((a - b)^2=a^2-2ab+b^2\) to simplify the squared term::


\(=(4 + \sqrt{15})(6 - 2\sqrt{60}+10)=\)

\(=(4 + \sqrt{15})(16 - 4\sqrt{15})=\)

\(=(4 + \sqrt{15})4(4 - \sqrt{15})=\)

\(=4(16-15)=4\).

Since the square of the expression is 4, the expression itself must be either 2 or -2. However, since the product of two positive terms and one negative term is negative (\((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})=positive*positive*negative=negative\)), we know that \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\) is negative. Therefore, the final answer is -2.


Answer: B­

Because the whole expression, \( (\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10}) \) is squared and when squaring the first term, \( (\sqrt{4-\sqrt{15}})\), we loose the outer square root and get \( 4-\sqrt{15} \).

Hope it's clear.
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