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30. What is the value of \((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} - \sqrt{10})\) ?

A. -4
B. -2
C. -1
D. 1
E. 2

Solution:

Root(15) = 3.88
Root(6) = 2.45
Root(10) = 3.16

=> Expression = \((\sqrt{0.12})(7.88)(2.45 - 3.16)\)

\(\sqrt{0.12} = \sqrt{\frac{12}{100}} = \frac{2\sqrt{3}}{10}\)

=> Expression = \((\frac{2\sqrt{3}}{10})(7.88)(2.45 - 3.16)\)
=> On solving, we get an approximate value of -2

Answer: B

p.s. Since I knew the values of roots, that is why I was able to solve it, but still not the GMAT way, because GMAT does not require such calculations. Different approaches are welcome!

Start with the 3rd Binomial Factor and square it/immediately take the square root so as to not change the value.

But, since it is a (-)negative value, first multiply it by (-1) to change it to positive, and remember that we must REVERSE the changed sign later.

(Sqrt(10) - sqrt(6)) —— square this and immediately take the square root.

You end up with:

Square root of:

16 - 2 * sqrt(60)

Simplify the root: 60 = (4) (15), so:

16 - 4 * sqrt(15)

Take 4 common

4 (4 - sqrt(15) )—— which is all under a square root

Now, we can combine this 3rd binomial factor with the 1st binomial factor, also under a square root

You have the following ALL UNDER a square root:

(4 - sqrt(15)) * 4 * (4 - sqrt(15) ) =

4 * (4 - sqrt(15) )^2 —-

We can take the square root of each factor

2 * (4 - sqrt(15) ) —-

Now we can multiply this by *(-1) to change it back to its original sign

(since we squared a negative value in the beginning and then immediately took the square root, thereby altering the original negative sign of the binomial factor)

(-) 2 * (4 - sqrt(15) )

The middle binomial joins now and creates a Difference of Squares factoring pattern:

(-) 2 * (4 - sqrt(15) ) * (4 + sqrt(15) ) =

(-) 2 * (16 - 15) =

(-) 2 * (1) =

-2
B

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hey - where are the answers?
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Bunuel
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hey - where are the answers?

The OA's are in the first post. Don't you see them???
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dont see the answers sir.
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dont see the answers sir.

They are directly below each question under the spoiler tag

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Q4
if
7^8 = m
8^7 = n

56 ^ 56
= (7*8)^56
= (7^56)(8^56)
= [(7^8)^7][(8^7)^8]
= m^7 * n^8

Ans: B
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Q6

Sqrt (49%) - 7/100

= sqrt (49/100) - 7 /100
= 7/10 - 7/100
= 63/100
= 63%

Ans: D
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Q7
(0.12)^2

= [12 x 10^-2]^2

= 12^2 * 10^-4

= 144 * 10^-4

= 0.0144

= 1.44 %
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Q12

1/3 root (2.7%) - 1/4 root (0.16%)

=1/3 root (27* 10^-3) - 1/4 root (16*10^-4)

=1/3 root [(3^3*10^-3)] - 1/4 root [(2^4)*(10^-4)]

= 3^1 * 10^-1 - 2^1*10^-1

= 0.3 - 0.2

= 0.1

= 10%
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Q16

Let List price = x
Let cost price = C

0.70x = 1.19C
C = 0.70x/1.19

By what % was her list price more than her cost price
=(L-C)/C
=[x - (0.70x/1.19)]/0.70x/1.19
= [(119-70)x/119]/70x/119
=49x/119/70x/119

=(49/119)/(70/119)

=49/70

=7/10

= 70%
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Q19

Remember |x| = x, when x>0 or -x, when x<0
=> when there are negative values, you need to put a (-1) in front when opening the modulus
=> Note rt5-rt7 <0, rt3-rt5<0

|rt3 - |rt5-rt7|| - ||rt3-rt5|-rt7|

= |rt3 - [(-1)*(rt5-rt7)]| - |(-1)*(rt3-rt5) - rt7|

= |rt3 - [-rt5 + rt7]| - |rt5-rt3-rt7|

= |rt3 +rt5 - rt7 |- |rt5-rt3-rt7|

= rt3+rt5-rt7 - [(-1)*(rt5-rt3-rt7)]

= rt3+rt5-rt7 - [-rt5+rt3+rt7]

= rt3+rt5-rt7 + rt5 - rt3 - rt7

= 2 * rt5 - 2 *rt7
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Q26

(a^m)^n = a^mn
A^m^n =/=a^mn

x^x= sqrt [(sqrt2)/2]

x^2x = (sqrt2)/2

x^4x = 2/4 = 1/2 = 2^-1

A:1/2^4 = 2^-4 => intuitively, you know you can make a negative 1, try it out


[2^-4]^(2^-4)*4

= [2^-4]^(2^-4)*(2^2)

= [2^-4]^(2^-2)
= [2^-4]^(1/4)
= 2^-1

Hence x = 2^-4 = 1/16
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27. A cloth merchant professes to sell at a loss of 5%. However, the merchant falsifies the meter scale and gains 25%. What is the measure of the scale that he uses when measuring 1 meter of cloth?

A. 70
B. 72
C. 75
D. 76
E. 77

Solution:

Let the original price = 100
Merchant professes to sell at loss of 5% => Actual sell price = 95

But even at 95, he gains 25% so let us assume measure of scale = x

\(1.25x = 95 => x = \frac{95*100}{125} = 19*4 = 76\)

Answer: D


Q27, this is what i did:
Length = L
M= meter

Revenue = m*L
let K be the meter scale being used

0.95*L*M= 1.25*L*M*K
0.95= 1.25*K
K=0.95/1.25=19/25=76/100
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Q34

Let x=2

50% = 1/2, after 5 visits, 1/32 left in the bank <1/2 [YES]

Let x = 3

33.33% = 1/3

after 5 visits, (2/3)^5 left in the bank = 32/243 <81/234 [YES]

[Note: after 1st visit, 2/3 left in the bank; after 2nd visit, it's 2/3 left of the 2/3 in the bank =(2/3)^2 ... and so on and so forth]

let x = 4; after 5 visits, (3/4)^5 left in the bank =243/1024 <256/1024 [YES]

let x =5; after 5 visits , (4/5)^5 left in the bank = 1024/3125 >1/5 [NO]

the range = 4-2 = 2 (Option B)
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av1901
NCC
This is amazing Bunuel!!
Hope you get 100+ replies soonest because I would love to have such tests for all topics of Quant!
Thank you for this!!!

If people post some of their solutions to problems, we shall reach that 100 reply barrier soon and for the DS Diagnostic test as well. Lets get going


Thanks v much for posting the solutions. Onwards to 100 replies on each thread!!
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solutions for level 7 and 8?
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