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# Carlos decreased his daily caloric intake by 20%, and Carol increased

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Joined: 12 Dec 2016
Posts: 1544
Location: United States
GMAT 1: 700 Q49 V33
GPA: 3.64
Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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13 Jan 2018, 17:22
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45% (medium)

Question Stats:

68% (01:56) correct 32% (02:10) wrong based on 51 sessions

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Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%
Intern
Joined: 31 Dec 2017
Posts: 28
Concentration: Finance
Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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13 Jan 2018, 18:17
2
chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

33⅓
37%
40%
48%
50%

Carlos' original caloric intake be $$x$$, and Carol's be $$y$$.

$$0.8x = 1.2y$$

$$x = \frac{1.2y}{0.8} = \frac{(1.2-0.8)y}{0.8} = 50\%$$
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Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)
Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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14 Jan 2018, 00:52
chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%

Let both consume 100 units now...

So, 100 units now is 80% of his previous consumption ; thus previous consumption was 125 units...
Again, 100 units now is 120% of his previous consumption ; thus previous consumption was 83.33 units...

Thus, Carlos’s original caloric intake was $$\frac{(125 - 83.33)}{125}*100$$ = 33⅓ %, hence answer will be (A)
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Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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14 Jan 2018, 04:55
Abhishek009 wrote:

Let both consume 100 units now...

So, 100 units now is 80% of his previous consumption ; thus previous consumption was 125 units...
Again, 100 units now is 120% of his previous consumption ; thus previous consumption was 83.33 units...

Thus, Carlos’s original caloric intake was $$\frac{(125 - 83.33)}{125}*100$$ = 33⅓ %, hence answer will be (A)

hi..
you have gone wrong with the BASE... IT will be 83.33 and not 125

chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%

Always try to pick smart numbers.... here it can be 120...
so Carlos decreased his daily caloric intake by 20%,
$$\frac{80}{100}x=120.......x=120*\frac{100}{80} = 150$$

and Carol increased her daily caloric intake by 20%
$$\frac{120}{100}y=120.......y=120*\frac{100}{120} = 100$$

Increase % = $$\frac{150-100}{100}*100=50$$%
E
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Joined: 21 Jul 2014
Posts: 66
GMAT Date: 07-30-2015
Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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10 Mar 2018, 04:58
chetan2u wrote:
Abhishek009 wrote:

Let both consume 100 units now...

So, 100 units now is 80% of his previous consumption ; thus previous consumption was 125 units...
Again, 100 units now is 120% of his previous consumption ; thus previous consumption was 83.33 units...

Thus, Carlos’s original caloric intake was $$\frac{(125 - 83.33)}{125}*100$$ = 33⅓ %, hence answer will be (A)

hi..
you have gone wrong with the BASE... IT will be 83.33 and not 125

chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%

Always try to pick smart numbers.... here it can be 120...
so Carlos decreased his daily caloric intake by 20%,
$$\frac{80}{100}x=120.......x=120*\frac{100}{80} = 150$$

and Carol increased her daily caloric intake by 20%
$$\frac{120}{100}y=120.......y=120*\frac{100}{120} = 100$$

Increase % = $$\frac{150-100}{100}*100=50$$%
E

Sir chetan2u
How did you decide the smart number to be 120. I took 100, which involved a little more calculations.
Re: Carlos decreased his daily caloric intake by 20%, and Carol increased   [#permalink] 10 Mar 2018, 04:58
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# Carlos decreased his daily caloric intake by 20%, and Carol increased

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