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Carlos decreased his daily caloric intake by 20%, and Carol increased

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Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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New post 13 Jan 2018, 16:22
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Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%
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Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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New post 13 Jan 2018, 17:17
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chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

33⅓
37%
40%
48%
50%

Carlos' original caloric intake be \(x\), and Carol's be \(y\).

\(0.8x = 1.2y\)

\(x = \frac{1.2y}{0.8} = \frac{(1.2-0.8)y}{0.8} = 50\%\)
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Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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New post 13 Jan 2018, 23:52
chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%


Let both consume 100 units now...

So, 100 units now is 80% of his previous consumption ; thus previous consumption was 125 units...
Again, 100 units now is 120% of his previous consumption ; thus previous consumption was 83.33 units...

Thus, Carlos’s original caloric intake was \(\frac{(125 - 83.33)}{125}*100\) = 33⅓ %, hence answer will be (A)
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Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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New post 14 Jan 2018, 03:55
Abhishek009 wrote:

Let both consume 100 units now...

So, 100 units now is 80% of his previous consumption ; thus previous consumption was 125 units...
Again, 100 units now is 120% of his previous consumption ; thus previous consumption was 83.33 units...

Thus, Carlos’s original caloric intake was \(\frac{(125 - 83.33)}{125}*100\) = 33⅓ %, hence answer will be (A)


hi..
you have gone wrong with the BASE... IT will be 83.33 and not 125

chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%


Always try to pick smart numbers.... here it can be 120...
so Carlos decreased his daily caloric intake by 20%,
\(\frac{80}{100}x=120.......x=120*\frac{100}{80} = 150\)

and Carol increased her daily caloric intake by 20%
\(\frac{120}{100}y=120.......y=120*\frac{100}{120} = 100\)

Increase % = \(\frac{150-100}{100}*100=50\)%
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2)Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html
3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


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Re: Carlos decreased his daily caloric intake by 20%, and Carol increased  [#permalink]

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New post 10 Mar 2018, 03:58
chetan2u wrote:
Abhishek009 wrote:

Let both consume 100 units now...

So, 100 units now is 80% of his previous consumption ; thus previous consumption was 125 units...
Again, 100 units now is 120% of his previous consumption ; thus previous consumption was 83.33 units...

Thus, Carlos’s original caloric intake was \(\frac{(125 - 83.33)}{125}*100\) = 33⅓ %, hence answer will be (A)


hi..
you have gone wrong with the BASE... IT will be 83.33 and not 125

chesstitans wrote:
Carlos decreased his daily caloric intake by 20%, and Carol increased her daily caloric intake by 20%. If they both now consume the same number of calories, how much percent greater was Carlos’s original caloric intake than that of Carol?

A. 33⅓
B. 37%
C. 40%
D. 48%
E. 50%


Always try to pick smart numbers.... here it can be 120...
so Carlos decreased his daily caloric intake by 20%,
\(\frac{80}{100}x=120.......x=120*\frac{100}{80} = 150\)

and Carol increased her daily caloric intake by 20%
\(\frac{120}{100}y=120.......y=120*\frac{100}{120} = 100\)

Increase % = \(\frac{150-100}{100}*100=50\)%
E


Sir chetan2u
How did you decide the smart number to be 120. I took 100, which involved a little more calculations.
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Re: Carlos decreased his daily caloric intake by 20%, and Carol increased &nbs [#permalink] 10 Mar 2018, 03:58
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Carlos decreased his daily caloric intake by 20%, and Carol increased

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