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17 Apr 2020, 04:37
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (02:11) correct
22%
(02:35)
wrong
based on 113
sessions
History
Date
Time
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Not Attempted Yet
Cathy traveled half of the journey by train at 80 kmph, half of the remaining journey by bus at 40 kmph and the remaining part of the journey by bicycle at 20 kmph. What was Cathy's average speed for the entire journey ?
A. 30 kmph
B. 40 kmph
C. 45 kmph
D. 50 kmph
E. 60 kmph
A. 30 kmph
B. 40 kmph
C. 45 kmph
D. 50 kmph
E. 60 kmph
yashikaaggarwal
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17 Apr 2020, 05:20
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Let the total distance be X
Cathy travelled half of the distance at 80kmph by train
Then time taken throughout the train journey
(X/2)/80----(1) {distance/speed}
Cathy travelled half of the rest distance at 40kmph by bus
Then time taken throughout the bus journey
(X/4)/40---(2) {distance/speed}
Cathy travelled remaining distance by bicycle at 20kmph
Then time taken throughout the bicycle journey
(X/4)/20----(3)
{distance/speed}
Total time taken throughout journey=(1)+(2)+(3)
(X/2)/80+(X/4)/40+(X+4)/20
X/160+X/160+X/80
4X/160
Total time= X/40
Total distance=X
Average Speed= Total Distance/Total time
=X/(X/40)
Average Speed = 40
OA is B
Posted from my mobile device
Cathy travelled half of the distance at 80kmph by train
Then time taken throughout the train journey
(X/2)/80----(1) {distance/speed}
Cathy travelled half of the rest distance at 40kmph by bus
Then time taken throughout the bus journey
(X/4)/40---(2) {distance/speed}
Cathy travelled remaining distance by bicycle at 20kmph
Then time taken throughout the bicycle journey
(X/4)/20----(3)
{distance/speed}
Total time taken throughout journey=(1)+(2)+(3)
(X/2)/80+(X/4)/40+(X+4)/20
X/160+X/160+X/80
4X/160
Total time= X/40
Total distance=X
Average Speed= Total Distance/Total time
=X/(X/40)
Average Speed = 40
OA is B
Posted from my mobile device
17 Apr 2020, 05:23
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Bunuel
Solution:
Let x km be the total distance of Cathy’s journey.
- • Distance travelled by train = \(\frac{x}{2}\) km
- o Time taken to cover \(\frac{x}{2} = \frac{x}{160}\)
- o Time taken to cover \(\frac{x}{4} = \frac{x}{160}\)
- o Time taken to cover \(\frac{x}{4} = \frac{x}{80}\)
• Average speed = \(\frac{distance}{time}\) = \(\frac{x}{\frac{x}{40}} = 40\)kmph
