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RenB
Joined: 13 Jul 2022
Last visit: 30 Apr 2026
Posts: 388
Given Kudos: 304
Location: India
Concentration: Finance, Nonprofit
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82 
GPA: 3.74
WE:Corporate Finance (Consulting)
Schools: Stanford '26 Wharton '26 (D) Booth '26 (D) Yale '26 (D) CBS '26 (A$$$) Darden '26 (WL) HBS '26 (D) Ross '26 (A$$$$) LBS '26 (D) Tuck '26 (A$$) Kellogg '26 (A)
GMAT Focus 1: 715 Q90 V84 DI82
Posts: 388
20 Aug 2023, 04:39
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
67% (03:06) correct
33%
(03:16)
wrong
based on 356
sessions
History
Date
Time
Result
Not Attempted Yet
Chandler bought a new car that gives a mileage of 6.5 when driven at a constant speed of 45 miles per hour, and a mileage of 5.5 at a constant speed of 35 miles per hour. On 600-mile road trip, the car traveled certain initial part of the trip at 45 miles per hour and the rest at 35 miles per hour. If the car used a total of 100 gallons of gas for this trip, how many miles did the car travel at 45 miles per hour? (Mileage is defined as the number of miles covered per gallon of gas)
A. 162.5
B. 275
C. 325
D. 478.5
E. None
A. 162.5
B. 275
C. 325
D. 478.5
E. None
30 Oct 2024, 18:11
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I have another way to resolve this exercise:
600 miles / 100 gallons -> in average, 6 mpg
It is the middle between 5.5mpg and 6.5mpg written in the statement
It means that 50 gallons have been consumed at 35 mph and 50 gallons at 45 mph
calculation of the distance at 45 mph => 6.5 miles per gallon -> 50 gallons means = 6.5x50=325
600 miles / 100 gallons -> in average, 6 mpg
It is the middle between 5.5mpg and 6.5mpg written in the statement
It means that 50 gallons have been consumed at 35 mph and 50 gallons at 45 mph
calculation of the distance at 45 mph => 6.5 miles per gallon -> 50 gallons means = 6.5x50=325
General Discussion
20 Aug 2023, 06:06
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RenB
Assume that Chandler travels '\(x\)' miles at 45 miles per hour.
Amount of gas used for to travel \(x\) miles = \(\frac{x}{6.5}\)
Distance traveled at 35 miles per hour = \(600-x\)
Amount of gas used for to travel \((600-x)\) miles = \(\frac{600-x}{5.5}\)
\(\frac{x}{6.5} + \frac{(600 - x)}{5.5} = 100\)
\(5.5x + (600 * 6.5) - 6.5x = 100 * 6.5 * 5.5\)
\(-x = (100 * 6.5 * 5.5) - (600 * 6.5) \)
\(-x = 100 * 6.5 (5.5 - 6) \)
\(x = 100 * 6.5 * 0.5\)
\(x = 325\)
Option C
