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chetan2u
A bag contains only 3 different colours and atleast one ball of red, white and blue colour. If the number of balls of each colour is distinct and red coloured balls are more than each of the other two colours, what is the probability of picking red ball?

(1) number of blue and white ball is half of total number of ball.
(2) there are 3 red coloured balls.

Hi,

rephrase the stem question to R/(R+W+B) ?

1. it says W+B=(W+B+R)/2 ---> W+B=R put it back in above equetion and it gives 1/2. sufficient
2. if there are 3 red balls and in stem it says the number of balls differ, there are more reds than other two and at least 1 of each exist then either w=1,B=2 or b=1,w=2. therefore sufficient.

have fun.
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trangphamthuy91
I think its A
(1) P picking red ball = 1/2
(2) no info about total ball number

Hi
Relook in the statement II..
Red ball are 3, buy the other info is..
1) red is max and ATLEAST one of each colour
2) all three are distinct number..

So clearly red is 3 and other 2 are 1 and 2..
Now we can find probability
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chetan2u
A bag contains only 3 different colours and atleast one ball of red, white and blue colour. If the number of balls of each colour is distinct and red coloured balls are more than each of the other two colours, what is the probability of picking red ball?

(1) number of blue and white ball is half of total number of ball.
(2) there are 3 red coloured balls.


D ..

A .(B+W) = 1/2x , R = 1/2x
p = 1/2
suff

B.Given red = 3 .. and in the question stem it is mentioned that number of each color is distinct and the bag have atlst one ball of each color ...so the possible value of red and blue will be 2,1 or 1,2
so p = 3/6 =1/2..
suff

So D.
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R>W and R>B

1) B+W= B+W+R/2 => 2B+2W=B+W+R => B+W=R
Probability of picking Red is R/B+W+R => R/R+R =R/2R Sufficient
2) R=3; So, W and B could be 1,2 or 2,1 => probability is 3/3+2+1 Sufficient
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