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# Common Mistakes in Geometry Questions - Exercise Question #1

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Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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Updated on: 07 Aug 2018, 04:09
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Exercise Question #1 Common Mistakes in Geometry Questions

ABCD is a quadrilateral as shown in the figure above. Find the area of the quadrilateral.

(1) The diagonals bisect each other at $$90^o$$ and they are equal.
(2) The length of each diagonal is 10 cm.

A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.

C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.

D. EACH statement ALONE is sufficient.

E. Statements (1) and (2) TOGETHER are NOT sufficient.

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Originally posted by EgmatQuantExpert on 22 Nov 2016, 05:32.
Last edited by EgmatQuantExpert on 07 Aug 2018, 04:09, edited 5 times in total.
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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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Updated on: 01 Dec 2016, 01:47
Note: This questions is related to the article on Common Errors in Geometry

Kindly go through the article once, before solving the question or going through the solution.

Official Solution

Analysing statement 1:

The first statements states :

The diagonals bisect each other at $$90^o$$ and they are equal.

From the above statement, we can conclude that the quadrilateral is a square.

But to find the area of the quadrilateral we need the length of each side, which is not given.

Hence statement 1 is not sufficient to answer the question.

Analysing statement 2:

The length of each diagonal is 10 cm.

Using only the 2nd statement, we cannot find the area of the quadrilateral, since we don't know what kind of quadrilateral it is.

Hence statement 2 is not sufficient to answer the question.

Combining statement 1 and 2:

Using both the statements, we can conclude that the quadrilateral is a square and the length of it's diagonal is 10cm.

Therefore, AB = BC = CD = AD

AC = BD = 10 (diagonals)

Since ABCD is a square angle ABC = 9$$0^o$$, therefore we can infer that the diagonal(AC) is the hypotenuse and the sides AB and BC are the perpendicular and base.

Hence we can write A$$B^2$$ + B$$C^2$$ = A$$C^2$$

2A$$B^2$$ = 1$$0^2$$.............(i)

And we know the area of the square = (side$$)^2$$ = A$$B^2$$

We can find the value of AB from (i) and hence we can find the area of the square!

Hence combining both the statements we can find out the answer.

Correct Option : C

Thanks,
Saquib
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Originally posted by EgmatQuantExpert on 22 Nov 2016, 11:13.
Last edited by EgmatQuantExpert on 01 Dec 2016, 01:47, edited 2 times in total.
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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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22 Nov 2016, 13:15
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An interesting variant is to figure out what the answer should be if the word 'bisect' is removed from statement (1)
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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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27 Nov 2016, 09:23
Hey Everyone,

The official solution has been posted. Kindly go through it and if you have any doubts feel free to post your query.

Thanks,
Saquib
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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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20 Jun 2017, 17:16
Could you please share the relation between all the polygon .
For Eg . How can a square be a Rhombus .
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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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21 Jun 2017, 11:04
abhisheknandy08 wrote:
Could you please share the relation between all the polygon .
For Eg . How can a square be a Rhombus .

Hi abhisheknandy08,

There can be many types of polygons based on number of sides.
Now, there are regular polygons and non-regular polygons.
Regular polygons have all sides equal but non-regular polygons can have any shape.

For the purpose of understanding this question, I'll stick with regular and non regular 4 sided polygon which have opposites sides parellel.

So, any polygon which has 2 of its opposite sides parallel and equal will be a parallelogram (so rectangle, rhombus and square are all parallelogram)
If in a parallelogram we make 2 sides equal (not all 4) and all angles 90 degree, we get a rectangle.
If we make all sides equal but the angles are not equal to 90 degree, we get a rhombus
Now if we make all angles 90 degree and all sides equal, we get a square (all squares are rhombus with 90 degree angles or all squares are rectangle with equal sides and all rhombus are parallelogram).

Hope it helps.
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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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11 May 2018, 11:49
in that case, Answer would have been E.

ccooley wrote:
An interesting variant is to figure out what the answer should be if the word 'bisect' is removed from statement (1)

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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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14 Aug 2018, 22:30
Dear Experts,

Statement 1 says that the diagonals bisect each other at 90 degrees and that they are equal. This is could mean that the given quadrilateral could just be a rectangle instead of a square. If this is the case, then combining statement 1 and 2, we still cannot find the area since two adjacent sides of a rectangle can be different.

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Re: Common Mistakes in Geometry Questions - Exercise Question #1  [#permalink]

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14 Aug 2018, 22:58
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kckartick wrote:
Dear Experts,

Statement 1 says that the diagonals bisect each other at 90 degrees and that they are equal. This is could mean that the given quadrilateral could just be a rectangle instead of a square. If this is the case, then combining statement 1 and 2, we still cannot find the area since two adjacent sides of a rectangle can be different.

Hey kckartick,

Not in each and every rectangle the diagonals bisect each other at 90 degrees. It happens only when the rectangle is a square - in that case, the lengths of the adjacent sides remain same.
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Re: Common Mistakes in Geometry Questions - Exercise Question #1 &nbs [#permalink] 14 Aug 2018, 22:58
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