Chiragjordan wrote:
Hey
chetan2u Can you please explain this one..
None of the above solution works for me ..
and What exactly are these acute obtuse cases?
i know that x can take values between (7,23)
Hi
Obtuse angled triangle is a triangle with one angle>90 degree..
Because of this there are few restriction on the legth of sides that you can have ..A simpler example..
let the sides be 6, 8 and 10... this is a right angled triangle with sides 6 , 8 and hypotenuse as 10..
If it is an obtuse angled triangle, 6,8,10 cannot be sides as no angle >90
here too we can have two case--
1) 15 is the biggest side..if it is 90 degree, x will be \(\sqrt{15^2-8^2}\) = \(\sqrt{161}\)= between 12 and 13..
if we take 13, the angle will become less than 90..
so 12 and values below it are correct..
but min value = 15-8 +1= 7+1 =8
so values are8 to 12= 5 values..2) let x be the largest sidesimilarly for it to be 90 degree, x should be \(\sqrt{8^2+15^2}\)= 17..
so it has to be >17..
max value = 5 +18-1 =22
so values = 18,19,20,21,22--- 5 more valuestotal - 5+5=10 values