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Re: cups of milk [#permalink]
D) 8/3

X/2 * x/4 = 4(total number of cups)
Cross multiply
you get 4x+2x =4
combine like terms
6x = 4
solve for x
x = 4/6, must reduce to 2/3

check answer

2(2/3)+4(2/3)=4
1 (1/3) + 2 (2/3) = 4 (1.333- + 2.6666- = 4) ((- = continuing to infinity.))
4 = 4 Verified.

4 cup = 2.6666- (8/3)

Actually now that I looked at it it's D), though my math is correct I forget it only applies to 4 cup glass so 8/3 would be in it.

Originally posted by Goobers82 on 21 May 2009, 07:51.
Last edited by Goobers82 on 21 May 2009, 16:19, edited 7 times in total.
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Re: cups of milk [#permalink]
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Quote:
Four cups of milk are to be poured into a 2-cup bottle and a 4-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 4-cup bottle?
(A) 2/3
(B) 7/3
(C) 5/2
(D) 8/3
(E) 3


Is the correct answer C?

I tried by POE.
a) 4 cups - 2/3 cups -->Fraction -1/6
1/6 of 2 cup bottle =1/3 cup
2/3+1/3 =1 cup

b) 4 cups - 7/3 cups -->Fraction -7/12
7/12 of 2 cup bottle =7/6 cup
7/3+7/6 =2.3 cup

c)4 cups - 5/2 cups -->Fraction -5/8
5/8 of 2 cup bottle =5/4 cup
5/2+5/4 =3.75 cup
close to 4 cups

d)8/3 came up to 2 cups

e)3 cups- the total would be 4.5

What is the answer?
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Re: cups of milk [#permalink]
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D is the correct answer


let x be the fraction.
4x+2x=4
6x=4 ==>x=2/3
4x=4*2/3=8/3 cups

for confirmation,
4x+2x= 4*2/3+2*2/3==>8/3+4/3=12/3==>4

hence 8/3 is the right ans...

please ignore my earlier post...
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Re: cups of milk [#permalink]
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The OA is D
I had this question on my GMATPREP and got it correct
Here is my approach
let x is the amount of milk we will pour in the 2 cups bottle and y is the amount of milk we will pour in the 4 cups bottle
=> x/2=y/4 => x=y/2
x+y=4
3y/2=4
y=8/3
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Re: cups of milk [#permalink]
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I think the easiest way to approach fraction problems is by visually tie in the actual fractions to the problem.

so if X cups are poured into the 4C cup : To make the two fractions equal : X/4 (for the four Cup ) should be equal to whatever remains / 2 (to equal the 2 cup fraction-wise)!!

So the equation would become:

x/4 = (4-x)/2

Solving this:
=>x/2 = (4-x)
=>x = 8 - 2x
=>3x = 8
=>x = 8/3
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Re: cups of milk [#permalink]
nice way to solve practically Karishma. What resources do you recommend for these types of problems, I always have trouble with them. Would it be the Manhattan GMAT word translations book? Thanks
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Re: cups of milk [#permalink]
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gettinit wrote:
nice way to solve practically Karishma. What resources do you recommend for these types of problems, I always have trouble with them. Would it be the Manhattan GMAT word translations book? Thanks


Actually, these are not 'types of problems'. These are 'types of solutions'. Many GMAT problems need little to no calculations. Very few need you to define variables and solve equations. It is just about getting exposed to such approaches and putting in the effort to figure these out. The more you think, the less you need to solve. After you read a statement in the question, pause and think, "What does it imply?"
Quite often, by the time you reach the question, you will have the answer in your head! Saves you loads of time but the skill is acquired with practice.
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Re: cups of milk [#permalink]
Got it thanks Karishma, thought I was missing something from my review, but need to just stop and think of a better approach rather than diving into solving.
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Re: PS 1000 Section7 Question 17 [#permalink]
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x/2 = (4-x)/4

4x = 8 - 2x

=> x = 8/6 = 4/3

So 4 - 4/3 = 8/3

I think the answer is D, but it's a typo (also, 8/2 is 4).
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Re: PS 1000 Section7 Question 17 [#permalink]
X/2 = Y/4

X+Y = 4

substituing equation 1 in 2 we get Y = 8/3

Answer is D.

And I agree with subhashghosh on the typo, option D should have been 8/3 not 8/2
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Re: cups of milk [#permalink]
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Vavali wrote:
Four cups of milk are to be poured into a 2-cup bottle and a 4-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 4-cup bottle?
(A) 2/3
(B) 7/3
(C) 5/2
(D) 8/3
(E) 3


Kind of an idiosyncratic way to solve, but here it is:

we know that putting 1 cup in the 2 cups makes it 1/2 full
and that 2 cups in the 4 cups makes it 1/2 full

we have 1 cup left to distribute. need to distribute 1 part to the 2 cup and 2 parts to the 2 cup to keep the ratio.

1/3 + 2/3 =1

thus the 4 cup has 6/3+ 2/3 = 8/3
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Re: Four cups of milk are to be poured into a 2-cup bottle and [#permalink]
10 Second Method!!!

Fraction of 2 cup bottle - x
Fraction of 4 cup bottle - 2x
The above is because the fractions have to be the same and one volume is double the other

x + 2x = 4

x = 4/3

2x (4 cup bottle ) = 8/3

Hence D
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Re: Four cups of milk are to be poured into a 2-cup bottle and [#permalink]
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Hi All,

This question can be approached in a number of different ways (depending on how you prefer to 'do the math'). Some ways are faster than others though...

We're told to pour 4 cups of milk into 6 cups of 'space' - this means that 2/3 of the space will be 'filled'....

We're told that the same fraction of each bottle will be filled, so we'll fill 2/3 of the 2-cup bottle and 2/3 of the 4-cup bottle.

We're asked for the amount of milk that is put in the 4-cup bottle: (2/3)(4) = 8/3

Final Answer:

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Four cups of milk are to be poured into a 2-cup bottle and [#permalink]
I went by this approach

If it was 3 cups we would divide it in a way that is : 1 cup in the first one and 2 cups in the 2nd one.. so the ratio in both of them are same.. i.e 1/2 full..

now take the 4th cup..since we have 4 cups and divide it in similar ratio..i.e 1:2.. so 1/3rd of that cup goes into first bottle and 2/3rd goes into 2nd bottle.. so the 2nd cup..i.e 4 cup bottle now has 2 and 2/3 cups.. which is 3/8 cups..
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Re: Four cups of milk are to be poured into a 2-cup bottle and [#permalink]
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Vavali wrote:
Four cups of milk are to be poured into a 2-cup bottle and a 4-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 4-cup bottle?

(A) 2/3
(B) 7/3
(C) 5/2
(D) 8/3
(E) 3

Given: 4 litres of milk and two empty bottles. One of 2 litres and another of 4 litres.

Total milk = 4 litres.
Total space = 6 litres.

Hence each bottle will be filled to 2/3rd capacity.
Quantity of milk in 4 litres bottle = 4*(2/3) = 8/3 litres

Correct option: D
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Re: Four cups of milk are to be poured into a 2-cup bottle and [#permalink]
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Vavali wrote:
Four cups of milk are to be poured into a 2-cup bottle and a 4-cup bottle. If each bottle is to be filled to the same fraction of its capacity, how many cups of milk should be poured into the 4-cup bottle?

(A) 2/3
(B) 7/3
(C) 5/2
(D) 8/3
(E) 3


If we let the amount of milk poured into the 2-cup bottle = n, then the amount poured into the 4-cup bottle is 4 - n; thus:

n/2 = (4- n)/4

4n = 2(4 - n)

4n = 8 - 2n

6n = 8

n = 8/6 = 4/3 = 1 1/3

The amount poured into the 4-cup bottle is 4 - 1 1/3 = 2 2/3 = 8/3.

Answer D
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Re: Four cups of milk are to be poured into a 2-cup bottle and [#permalink]
Let's read carefully, this is all about this question.

Four cups of milk are to be poured into a 2-cup bottle and a 4-cup bottle.
2-cup bottle = x and 4-cup bottle = y, then x +y = 4

If each bottle is to be filled to the same fraction of its capacity, So, x/2 = y/4 or, y = 2x

So, x +2x = 4 or, x =4/3 or y = 8/3 = 4-cup bottle

So, I think D. :)
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