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TanyaBhargava
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TanyaBhargava
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That’s what studying for 6 hours straight does to me I guess :lol:
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TanyaBhargava
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yes this was a tricky one too!

Bunuel

Data Sufficiency Butler: September 2024
September 16DS 1DS 2
whats the ans , official one isnt provided..
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Madhvendrasinh
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It’ll be posted after 24 hours
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TanyaBhargava
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oh, thanks
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Bunuel

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September 16DS 1DS 2
DS2- D? Anyone confirm ?
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nitish2610
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A

Sorry my bad
It’s D

Sorry my bad

its D
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i feel a

but i solved the eqn mentally so could be wrong
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All you need is to find the distance
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agnee
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if you are given individual velocities so you can have the whole distance too which serves your purpose.
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First option directly gives it
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i tried , 2nd statement does give us the answer

for individual times travelled- the ratio of speeds gives away the proportion of time used by each ,right?
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yes I agree
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2*x*y/ x+y is your average velocity

distance is not required

8 miles per hour
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TanyaBhargava
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agnee
2*x*y/ x+y is your average velocity
oh , we can straight away use this formula. instead of ( total dist/total time)

using the above also i got the answer but av vel formula is just easier
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Or u can try knowing where this came from :

Avg Vel= total distance travelled/ tool time taken
= 2D/ (D/x+ D/y) (assuming one leg=D)
=2xy/x+y
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yes, i know this- i always get a bit confused with this topic tho! - instead expanded total dis in terms of (speed *individual times) for both- hence the question about time split between the 2- but thats where weighted averages came in handy. but av velocity formula would definitely save time. thanks
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