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Data Sufficiency Pack 3, Question 3) A pet store sells three...

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Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post Updated on: 08 Nov 2015, 17:28
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QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 3 A pet store sells three...

A pet store sells three types of animals: cats, dogs and exotic fish. If the ratio of cats to dogs in the store is currently 5 to 13 and there are currently 168 total pets in the store, then how many more dogs than exotic fish are currently in the store?

(1) The ratio of cats to exotic fish in the store is currently 1 to 2
(2) There are currently 30 more exotic fish than cats in the store


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Originally posted by EMPOWERgmatRichC on 07 Nov 2015, 16:27.
Last edited by EMPOWERgmatRichC on 08 Nov 2015, 17:28, edited 1 time in total.
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post Updated on: 08 Nov 2015, 08:41
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EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 3 A pet store sells three...

A pet store sells three types of animals: cats, dogs and exotic fish. If the ratio of cats to dogs in the store is currently 5 to 13 and there are currently 168 total pets in the store, then how many more dogs than exotic fish are currently in the store?

(1) The ratio of cats to exotic fish in the store is currently 2 to 3
(2) There are currently 30 more exotic fish than cats in the store


48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

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Good question.

Let cats, dogs, fishes be C,D and F respectively.

C+D+F=168
C=5k, D=13k

D-F = ?

Per statement 1, C/F=2/3 ---> No need to calculate. Clearly sufficient.

Per statement 2, F-C=30 ---> the only case possible is C=30, D=78, F=60. Sufficient.

From F-C=30 ---> F=30+5k --> 5k+13k+30+5k=168 ---> 23k = 138 ---> k =6.

D is the correct answer.

Originally posted by ENGRTOMBA2018 on 07 Nov 2015, 16:55.
Last edited by ENGRTOMBA2018 on 08 Nov 2015, 08:41, edited 1 time in total.
Corrected the typos.
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 08 Nov 2015, 08:39
2
Engr2012 wrote:
EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 3 A pet store sells three...

A pet store sells three types of animals: cats, dogs and exotic fish. If the ratio of cats to dogs in the store is currently 5 to 13 and there are currently 168 total pets in the store, then how many more dogs than exotic fish are currently in the store?

(1) The ratio of cats to exotic fish in the store is currently 2 to 3
(2) There are currently 30 more exotic fish than cats in the store


48 Hour Window Answer & Explanation Window
Earn KUDOS! Post your answer and explanation.
OA, and explanation will be posted after the 48 hour window closes.

This question is part of the Quant 4-Pack series

Scroll Down For Official Explanation



Good question.

Let cats, dogs, fishes be C,D and F respectively.

C+D+F=168
C=5k, D=13k

D-E = ?

Per statement 1, C/E=2/3 ---> No need to calculate. Clearly sufficient.

Per statement 2, E-C=30 ---> the only case possible is C=30, D=75, F=60. Sufficient.

From E-C=30 ---> E=30+5k --> 5k+13k+30+5k=168 ---> 23k = 138 ---> k =6.

D is the correct answer.


Hi Engr,
Please review the highlighted part. i think D=78. Also, there is a typo error between E & F.
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 08 Nov 2015, 08:46
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Mo2men wrote:


Hi Engr,
Please review the highlighted part. i think D=78. Also, there is a typo error between E & F.


Thanks. Updated the typos. Final values are not important but you just need to realize that the statement 2 is sufficient based on the information given.
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 08 Nov 2015, 12:37
2
Engr2012 wrote:
Mo2men wrote:


Hi Engr,
Please review the highlighted part. i think D=78. Also, there is a typo error between E & F.


Thanks. Updated the typos. Final values are not important but you just need to realize that the statement 2 is sufficient based on the information given.



Thanks. I will do as did you in the exam. I won't solve till last number. However, I suspect that the question has not accurate numbers. If you review your numbers in statement 2, you will find C/F=30/60=1/3 which contradicts statement 1 which states C/F=2/3.

Therefore I tried to solve the question as PS using statement 1 as follows:

C:D= 5:13=10:26.......I
C:F=2:3=10:15...........II
C+D+F=168......III
From I & II
C:D:F=10:26:15

To Find number of cats= 168*10/51= Non integer number

Do I miss something in the above??I'm glad to receive your comments.
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 08 Nov 2015, 13:26
1
Mo2men wrote:
Engr2012 wrote:
Mo2men wrote:


Hi Engr,
Please review the highlighted part. i think D=78. Also, there is a typo error between E & F.


Thanks. Updated the typos. Final values are not important but you just need to realize that the statement 2 is sufficient based on the information given.



Thanks. I will do as did you in the exam. I won't solve till last number. However, I suspect that the question has not accurate numbers. If you review your numbers in statement 2, you will find C/F=30/60=1/3 which contradicts statement 1 which states C/F=2/3.

Therefore I tried to solve the question as PS using statement 1 as follows:

C:D= 5:13=10:26.......I
C:F=2:3=10:15...........II
C+D+F=168......III
From I & II
C:D:F=10:26:15

To Find number of cats= 168*10/51= Non integer number

Do I miss something in the above??I'm glad to receive your comments.


That is a very good catch. In actual GMAT DS questions, if both the statements are sufficient individually , then the answer will be the same. For this question, your doubt is well founded. I'll let EMPOWERgmatRichC update the question when the OE is posted.

But in GMAT don't bother with getting to the final unique value in DS question as that'll be a waste of time. Once you are sure that you will get a unique value, mark that answer and move on.

Hope this helps.
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 08 Nov 2015, 17:30
Hi Mo2men & Engr2012,

Thank you both for having the discussion that you had - it helped to discover a typo in Fact 1 (which has since been fixed).

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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 08 Nov 2015, 18:30
1
HI
A pet store sells three types of animals: cats, dogs and exotic fish. If the ratio of cats to dogs in the store is currently 5 to 13 and there are currently 168 total pets in the store, then how many more dogs than exotic fish are currently in the store?

(1) The ratio of cats to exotic fish in the store is currently 1 to 2
(2) There are currently 30 more exotic fish than cats in the store

IMO D is correct answer

I] ratio of Cat : dog = 5:13
ratio of cat : fish = 1:2
so we can derive ratio of cat:dog:fish = 5:13:10
so sufficient

II] Cat+30 = fish
ratio of Cat : dog = 5:13
we can alos write this as
F + C+D=168
C+30 +C+D=168
2C+D=138
plugging ratio values here we can get answer

so it is also sufficient

SO D
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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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New post 10 Nov 2015, 18:16
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1
EMPOWERgmatRichC wrote:
QUANT 4-PACK SERIES Data Sufficiency Pack 3 Question 3 A pet store sells three...

A pet store sells three types of animals: cats, dogs and exotic fish. If the ratio of cats to dogs in the store is currently 5 to 13 and there are currently 168 total pets in the store, then how many more dogs than exotic fish are currently in the store?

(1) The ratio of cats to exotic fish in the store is currently 1 to 2
(2) There are currently 30 more exotic fish than cats in the store


This DS prompt is based on ratios and ratio rules. Understanding how the ratios interact with one another (and the other pieces of information) will help you to answer this question without necessarily having to do that many calculations.

To start, we're told a number of facts about a pet store:
1) There are three types of animals: cats, dogs and fish.
2) The ratio of cats to dogs at the store is 5:13
3) There are a total of 168 pets at the store.

We're asked how many MORE dogs there are at the store than fish.

1) The ratio of cats to exotic fish in the store is currently 1 to 2

With this Fact, we can now construct a 'grand ratio' of how the number of cats, dogs and fish all relate to one another:

C:D
5:13

C:F
1:2

Since we cannot have a 'fraction' of an animal, the ratio of cats to dogs to fish is...

C:D:F
5:13:10

This means that the number of cats MUST be a multiple of 5, the number of dogs MUST be a multiple of 13 and the number of fish MUST be a multiple of 10. By extension, the total number of animals MUST be a multiple of 5+13+10 = 28.

Given this information, and the fact that the total number of animals is 168, the multiple must be 168/28 = 6. This would allow you to calculate the total number of each animal (even though you don't technically have to - those numbers are 30 cats, 78 dogs and 60 fish).
Fact 1 is SUFFICIENT.

2) There are currently 30 more exotic fish than cats in the store

Depending on how you interpret ratio data, you might have to do a bit more work with this Fact to prove that it's sufficient. We know the current ratio of cats to dogs (5 to 13) and the total number of pets (168), so we can create a table of possible 'total animals' that incorporate this new Fact (that there are 30 MORE fish than cats):

C/D/F
5/13/35 = 55 animals
10/26/40 = 76 animals
15/39/45 = 99 animals
20/52/50 = 122 animals
25/65/55 = 145 animals
30/78/60 = 168 animals
Etc.

There's just ONE WAY for the total number of animals to be 168.
Fact 2 is SUFFICIENT

Final Answer:

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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three... [#permalink]

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Re: Data Sufficiency Pack 3, Question 3) A pet store sells three...   [#permalink] 26 Mar 2017, 03:23
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