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a x,y,z all can be negative | x or y or z can be negative. Not sufficient.

b x|y negative giving nothing about Z.

a+b

x= -10 y = 10 , z = 1 Z is in between. yes
y= -10 x = 1, z=2 Z is outside. No.

Hence E.
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(1)

z--------0---x----------------y


x--------0---z----------------y


Insufficient

(2)


x--------0---z----------------y

z-----x--------0-------------------y

Insufficient

(1) + (2)

From Diagram in (2)

Insufficient

Answer - E
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question states that d(x,y)>d(x,z) also from (1) and (2) we know that z is positive
(as xy<0=>z>0)
thus looking at above conditions we can say that z is between x and y
where am i going wrong
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skbjunior
Distance between x and y is greater than distance between x and z. Does z lie between x and y on the number line?

(1) xyz < 0
(2) xy < 0


OPEN DISCUSSION OF THIS QUESTION IS HERE: on-the-number-line-the-distance-between-x-and-y-is-greater-127014.html

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