Jul 16 03:00 PM PDT  04:00 PM PDT Join a free live webinar and find out which skills will get you to the top, and what you can do to develop them. Save your spot today! Tuesday, July 16th at 3 pm PST Jul 16 08:00 PM EDT  09:00 PM EDT Strategies and techniques for approaching featured GMAT topics. Tuesday, July 16th at 8 pm EDT Jul 19 08:00 AM PDT  09:00 AM PDT The Competition Continues  Game of Timers is a teambased competition based on solving GMAT questions to win epic prizes! Starting July 1st, compete to win prep materials while studying for GMAT! Registration is Open! Ends July 26th Jul 20 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. Jul 21 07:00 AM PDT  09:00 AM PDT Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes
Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 05 Nov 2012
Posts: 64
Concentration: International Business, Operations
GPA: 3.65

During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
24 May 2013, 15:44
Question Stats:
72% (02:15) correct 28% (02:26) wrong based on 184 sessions
HideShow timer Statistics
During a certain week, a seal ate 50 percent of the first 80 smelt it came across, and 30 percent of the remaining smelt it came across. If the seal ate 40 percent of the smelt it came across during the entire week, how many smelt did it eat? A. 32 B. 40 B. 55 D. 64 E. 80
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
___________________________________________ Consider +1 Kudos if my post helped



Math Expert
Joined: 02 Sep 2009
Posts: 56244

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
24 May 2013, 15:50
pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 Total smelt = x. Then, 0.5*80+0.3(x80)=0.4*x > x=160 > 0.4*x=64. Answer: D.
_________________



Intern
Joined: 15 Oct 2012
Posts: 20

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
25 May 2013, 03:34
Bunuel wrote: pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 Total smelt = x. Then, 0.5*80+0.3(x80)=0.4*x > x=160 > 0.4*x=64. Answer: D. Bunuel why I am getting a different answer? Let say Total number of Smelt be  100 Seal ate  50% of 80 I.e 40 Than..... 30% of remaining 20(10080) I.e 6 Which comes to total of 46(40+6) Now its given seal ate total of 40%.... In that case 46/40*100 comes to 115 total no of spate...... Where I am going wrong ...can you explain please???



Math Expert
Joined: 02 Sep 2009
Posts: 56244

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
25 May 2013, 03:37
nikhilsehgal wrote: Bunuel wrote: pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 Total smelt = x. Then, 0.5*80+0.3(x80)=0.4*x > x=160 > 0.4*x=64. Answer: D. Bunuel why I am getting a different answer? Let say Total number of Smelt be  100 Seal ate  50% of 80 I.e 40 Than..... 30% of remaining 20(10080) I.e 6 Which comes to total of 46(40+6) Now its given seal ate total of 40%.... In that case 46/40*100 comes to 115 total no of spate...... Where I am going wrong ...can you explain please??? The number of smelt is some particular number you cannot assume that it's 100.
_________________



Intern
Joined: 10 Dec 2010
Posts: 3

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
23 May 2014, 02:45
Hi,
I am getting a different answer. My approach: 1. First Part  80 smelts  50% eaten = 40 ....... Statement 1 2. 2nd Part  x smelts  30% eaten = 0.3x ....... Statement 2
Total Smelts = 1st part + 2nd part = 80+x Seal ate 40% of total smelts => 0.4 (80+x) ....... Statement 3
Therefore , combining Statement 1,2,3 40 + 0.3x = 0.4(80+x) . This is giving x = 80 and 32 as the answer.
Kindly assist where I have gone wrong. Thanks



Math Expert
Joined: 02 Sep 2009
Posts: 56244

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
23 May 2014, 03:04
mayankgc wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80
Hi,
I am getting a different answer. My approach: 1. First Part  80 smelts  50% eaten = 40 ....... Statement 1 2. 2nd Part  x smelts  30% eaten = 0.3x ....... Statement 2
Total Smelts = 1st part + 2nd part = 80+x Seal ate 40% of total smelts => 0.4 (80+x) ....... Statement 3
Therefore , combining Statement 1,2,3 40 + 0.3x = 0.4(80+x) . This is giving x = 80 and 32 as the answer.
Kindly assist where I have gone wrong. Thanks We are told that the seal ate 30% of the remaining smelt it came across. Thus x in your solution must be the number of the remaining smelt. Which makes the total number of smelt equal to 80 + x = 160. 40% of 160 is 64. Does this make sense?
_________________



Intern
Joined: 10 Dec 2010
Posts: 3

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
24 May 2014, 07:51
Yes it clears out my confusion Thanks Bunuel...



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9433
Location: Pune, India

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
25 May 2014, 23:25
pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 Responding to a pm: The seal ate 50% of first portion and 30% of second portion. Overall (average), it ate 40% of the entire portion. Using scale method, Second portion/First portion = (50  40)/(40  30) = 1/1 So both portions need to be equal i.e. of 80 smelts each. So both portions together had 160 smelts and the seal ate 40% of it i.e. (40/100)*160 = 64 smelts
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >



Director
Joined: 05 Mar 2015
Posts: 990

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
22 May 2016, 00:09
pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 Let total no of smelts be X. eaten smalts: 50% of first 80==40 && 30 % of remaining (X80)==30(X80)/100 total 40% of X 40+ 30(X80)/100=40X/100 X=160. so eaten smelts= 40*160/100==64 Ans D.



Current Student
Joined: 18 Oct 2014
Posts: 830
Location: United States
GPA: 3.98

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
22 May 2016, 11:15
pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 First the seal ate 50% of 80 i.e 40 smelt. Suppose the number of remaining smelts is x. Seal then ate .30x of these remaining smelts. Total smelts are 80+ x and seal ate 40% of 80+x .4(80+x)= 40+.3x x= 80 Total smelts eaten are .4(80+80)= 64 D is the answer
_________________
I welcome critical analysis of my post!! That will help me reach 700+



Current Student
Joined: 19 Aug 2016
Posts: 148
Location: India
GPA: 3.82

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
25 Apr 2017, 02:05
mayankgc wrote: Hi,
I am getting a different answer. My approach: 1. First Part  80 smelts  50% eaten = 40 ....... Statement 1 2. 2nd Part  x smelts  30% eaten = 0.3x ....... Statement 2
Total Smelts = 1st part + 2nd part = 80+x Seal ate 40% of total smelts => 0.4 (80+x) ....... Statement 3
Therefore , combining Statement 1,2,3 40 + 0.3x = 0.4(80+x) . This is giving x = 80 and 32 as the answer.
Kindly assist where I have gone wrong. Thanks Hi, I did the same thing and I think what you have to do is assume the remaining smelts as x. Thus, x will be 80 and 30% of the remaining smelts will be 24 which will give total as 64. Hope its clear.
_________________
Consider giving me Kudos if you find my posts useful, challenging and helpful!



Director
Joined: 12 Nov 2016
Posts: 713
Location: United States
GPA: 2.66

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
21 Jun 2017, 07:47
pikachu wrote: During a certain week, a seal ate 50% of the first 80 smelt it came across, and 30% of the remaining smelt it came across. If the seal ate 40% of the smelt it came across during the entire week, how many smelt did it eat?
A. 32 B. 40 B. 55 D. 64 E. 80 (.5) 80 + .3(x80) =.4x x= 160 .5(80) + .3(80)= 64 Thus "D"



MBA Section Director
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 2555
GPA: 4
WE: Engineering (Computer Software)

During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
Updated on: 12 Jul 2018, 06:07
A seal ate 50 percent of the first 80 smelt it came across => \(\frac{50}{100} * 80\) Let x be the remaining number of smelt the seal came across Total number is smelt the seal ate is \(\frac{50}{100} * 80 + \frac{30}{100} * x\) => \(\frac{50}{100} * 80 + \frac{30}{100} * x = \frac{40}{100} * (80 + x)\) => \((50 * 80) + 30x = 40 * (80 + x)\) => \(4000 + 30x = 40x + 3200\) => \(10x = 4000  3200\) => \(x = 80\) UPDATE : At first I solved only for 'x' and chose option E but the question actually asks for the number of smelt the seal ate which is \(\frac{50}{100}* 80 + \frac{30}{100}* 80 = 64\) Hence option D Thanks EgmatQuantExpert for the correct solution Important learning for meAfter solving the variables, do explicitly check what the question has asked for. Don't just stop after calculating the variables you have assumed and pick an answer.
_________________
Originally posted by workout on 12 Jul 2018, 02:32.
Last edited by workout on 12 Jul 2018, 06:07, edited 4 times in total.



Director
Joined: 20 Feb 2015
Posts: 790
Concentration: Strategy, General Management

During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
Updated on: 12 Jul 2018, 06:55
Bunuel wrote: During a certain week, a seal ate 50 percent of the first 80 smelt it came across, and 30 percent of the remaining smelt it came across. If the seal ate 40 percent of the smelt it came across during the entire week, how many smelt did it eat?
A. 24
B. 32
C. 55
D. 64
E. 80 let x+40 be the total no of smelts 50% of the first 80 smelt = 40 remaining = x 30% of the remaining =0.3x it ate 40% of the total 0.4(x+40)=40+0.3x 0.4x+16=40+0.3x 0.1x=24 x=240 total no of smelts = 280 it ate 40% of 280 =112 help me out here !! Corrected above !! let x+40 be the total no of smelts 50% of the first 80 smelt = 40 remaining would be (x+40)80=x40 so the equation becomes 0.4(x+40)=40+0.3(x40) 0.4x+16=40+0.3x12 x=120 total no of smelts =120+40=160 it ate 40% of 160 = 64 D
Originally posted by CounterSniper on 12 Jul 2018, 05:04.
Last edited by CounterSniper on 12 Jul 2018, 06:55, edited 2 times in total.



MBA Section Director
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 2555
GPA: 4
WE: Engineering (Computer Software)

During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
12 Jul 2018, 05:28
CounterSniper wrote: it ate 40% of the total 0.4(x+40)=40+0.3x
CounterSniperit ate 40% of the total, so the equation becomes 0.4(x+ 80)=40+0.3x
_________________



MBA Section Director
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 2555
GPA: 4
WE: Engineering (Computer Software)

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
12 Jul 2018, 05:32
CounterSniper wrote: let x+40 be the total no of smelts
Also, here the total number of smelts is x+80 not x+40
_________________



eGMAT Representative
Joined: 04 Jan 2015
Posts: 2942

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
12 Jul 2018, 05:48
Solution Given:• In a certain week, a seal ate 50 percent of the first 80 smelt it came across. • The seal ate 30% of remaining seal it came across. • In total, seal ate 40 percent of the smelt it came across To find:• How many smelts did seal eat in the week? Approach and Working: Let us assume that seal came across x smelts after eating 50% of first 80 smelts it came across. • 50% of 80+ 30% of x= 40% of (x+80) • 40+0.3x= 0.4x+32 • x=80 Hence, seal ate 40+ 24= 64 Hence, the correct answer is option D. Answer: D
_________________



eGMAT Representative
Joined: 04 Jan 2015
Posts: 2942

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
12 Jul 2018, 05:50
Hey workout, I think you found x but did not calculate the number of smelts the seat ate. Please check once.
_________________



MBA Section Director
Affiliations: GMATClub
Joined: 22 May 2017
Posts: 2555
GPA: 4
WE: Engineering (Computer Software)

Re: During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
12 Jul 2018, 05:54
workout wrote: A seal ate 50 percent of the first 80 smelt it came across => \(\frac{50}{100} * 80\)
Let x be the remaining number of smelt the seal came across
Total number is smelt the seal ate is \(\frac{50}{100} * 80 + \frac{30}{100} * x\)
=> \(\frac{50}{100} * 80 + \frac{30}{100} * x = \frac{40}{100} * (80 + x)\)
=> \((50 * 80) + 30x = 40 * (80 + x)\)
=> \(4000 + 30x = 40x + 3200\)
=> \(10x = 4000  3200\)
=> \(x = 80\)
Hence option E It looks like I solved for the wrong thing. The question asks for the number of smelts the seal ate which is \(\frac{50}{100}* 80 + \frac{30}{100}* 80 = 64\) Hence option D Thanks EgmatQuantExpert for the correct solution
_________________



VP
Joined: 31 Oct 2013
Posts: 1392
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)

During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
Show Tags
12 Jul 2018, 06:36
Bunuel wrote: During a certain week, a seal ate 50 percent of the first 80 smelt it came across, and 30 percent of the remaining smelt it came across. If the seal ate 40 percent of the smelt it came across during the entire week, how many smelt did it eat?
A. 24
B. 32
C. 55
D. 64
E. 80 let assume the no. of smelt be x. Case 1: 80*50% = 40 Case 2: Remaining smelt : (x 80) So, the no. of smelt ate at second phase : (x  80)*30% 3(x  80) / 10 Case 3: we can form an equation based on the information that seal ate a total of 40% smelt. 40 + 3(x 80) / 10 = x * 40% (400 + 3x  240) / 10 = 2x / 5 x = 160. No of smelt ate : 40 + ( 160 80) 30% = 40 + 24 = 64. Thus the best answer is D.




During a certain week, a seal ate 50 percent of the first 80 smelt it
[#permalink]
12 Jul 2018, 06:36



Go to page
1 2
Next
[ 21 posts ]



