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Eleven members of Club A are also members of Club B, and five members

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Eleven members of Club A are also members of Club B, and five members [#permalink]

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Eleven members of Club A are also members of Club B, and five members of Club B are also members of Club C. How many members of Club A are also members of Club C?

(1) Club B has 16 members.
(2) Exactly two people from Club C are also members of Club A.


Kudos for a correct solution.
[Reveal] Spoiler: OA

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 16 Feb 2015, 02:14
Ans - E

Stmnt 1 - Clearly insuff
Stmnt 2 - Not suff

Combining, also notsuff

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 16 Feb 2015, 04:01
buddyisraelgmat wrote:
Ans - E

Stmnt 1 - Clearly insuff
Stmnt 2 - Not suff

Combining, also notsuff


hi,
why should statement 2 not be sufficient?
It tells exactly what we want and that is how many members are common between the two groups..
ans B
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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 16 Feb 2015, 06:34
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Bunuel wrote:
Eleven members of Club A are also members of Club B, and five members of Club B are also members of Club C. How many members of Club A are also members of Club C?

(1) Club B has 16 members.
(2) Exactly two people from Club C are also members of Club A.


Kudos for a correct solution.


VERITAS PREP OFFICIAL SOLUTION

Correct Answer: B

Explanation:

(1) It is possible that the 11 members of Club A who belong to Club B include the 5 members who also belong to Club C. It is also possible that no one who belongs to Club A also belongs to Club C. Accordingly, statement 1 is insufficient.

(2) This statement answers the question directly, indicating that two people are members of both Club A and Club C. Accordingly, this statement is sufficient. Since statement (2) alone is sufficient to answer the question, the correct answer is B.
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Collection of Questions:
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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 27 Aug 2015, 07:39
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Does Statement 2 comprises of both common between A & C and common among A, B, & C. By the term exactly, I understood as if they are just common between A & C and since we do not know those who are common among all three clubs the information is insufficient; and hence Answer is E.

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 22 Mar 2017, 00:46
Bunuel wrote:
Eleven members of Club A are also members of Club B, and five members of Club B are also members of Club C. How many members of Club A are also members of Club C?

(1) Club B has 16 members.
(2) Exactly two people from Club C are also members of Club A.


Kudos for a correct solution.


This question asks us if we have enough information to determine how many members of club A are also member of club C- it is important to note that conditional logic doesn't necessarily apply in set theory- in other words, we if know how many members of club C are also members of club A then we know how many members of club A are members of club c. If this were critical reasoning, for example, then the argument if all A are B then all B are A would be fallacious ( All humans are mammals but not all mammals are humans). Though if you look at this scenario on a three circle venn diagram you can see that whatever numbers falls into the intersection of Group A and C ( the circle that intersects those groups) this number applies both ways.

Statement (1) tells us the size of club B which in itself does not allow us to find the number of members in club C. Insufficient

Statement (2) answers the question. Sufficient.

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 27 Aug 2017, 05:04
scorpionkapoor77 wrote:
Does Statement 2 comprises of both common between A & C and common among A, B, & C. By the term exactly, I understood as if they are just common between A & C and since we do not know those who are common among all three clubs the information is insufficient; and hence Answer is E.



Hi Bunuel

Even i had a similar problem. Can you please explain the flaw in our understanding ?

Kudos [?]: 6 [0], given: 64

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 27 Aug 2017, 05:17
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Kevinjoshi wrote:
scorpionkapoor77 wrote:
Eleven members of Club A are also members of Club B, and five members of Club B are also members of Club C. How many members of Club A are also members of Club C?

(1) Club B has 16 members.
(2) Exactly two people from Club C are also members of Club A.



Does Statement 2 comprises of both common between A & C and common among A, B, & C. By the term exactly, I understood as if they are just common between A & C and since we do not know those who are common among all three clubs the information is insufficient; and hence Answer is E.



Hi Bunuel

Even i had a similar problem. Can you please explain the flaw in our understanding ?


(2) Exactly two people from Club C are also members of Club A means that the overlap between C and A is 2. Below is one of the possible cases:
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_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Kudos [?]: 135331 [1], given: 12687

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Kudos [?]: 6 [0], given: 64

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WE: Engineering (Consulting)
Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 27 Aug 2017, 05:54
Bunuel wrote:
Kevinjoshi wrote:
scorpionkapoor77 wrote:
Eleven members of Club A are also members of Club B, and five members of Club B are also members of Club C. How many members of Club A are also members of Club C?

(1) Club B has 16 members.
(2) Exactly two people from Club C are also members of Club A.



Does Statement 2 comprises of both common between A & C and common among A, B, & C. By the term exactly, I understood as if they are just common between A & C and since we do not know those who are common among all three clubs the information is insufficient; and hence Answer is E.



Hi Bunuel

Even i had a similar problem. Can you please explain the flaw in our understanding ?


(2) Exactly two people from Club C are also members of Club A means that the overlap between C and A is 2. Below is one of the possible cases:



Thank you Bunuel for your prompt reply. I understood the case.

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 26 Oct 2017, 07:24
From St1, we don't know the number of members of club A in C. It may or may not be an overlapping set.
From St2, Its the other way of projecting the answer. If exactly 2 from Club C are present in Club A, the same is true in vice-versa.

So ans is B.

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Re: Eleven members of Club A are also members of Club B, and five members [#permalink]

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New post 12 Nov 2017, 13:32
scorpionkapoor77 wrote:
Does Statement 2 comprises of both common between A & C and common among A, B, & C. By the term exactly, I understood as if they are just common between A & C and since we do not know those who are common among all three clubs the information is insufficient; and hence Answer is E.


Exactly, language is imprecise and hence there gotta be an inference to solve the question...
Veritas' inferece is that AuC excludes B, we (cause I made the same inference) is that not necessary does, because the problem doesn't says so...

I've find Veritas practice kinda annoying because of that

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Re: Eleven members of Club A are also members of Club B, and five members   [#permalink] 12 Nov 2017, 13:32
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