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14 Nov 2023, 02:30
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
59% (01:55) correct
41%
(02:06)
wrong
based on 559
sessions
History
Date
Time
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Not Attempted Yet
Families in which some members argue with each other compete for a chance to appear on Barry Wringer’s TV show. The greater the percentage of family members who argue with each other, the greater the family’s chances of appearing on Wringer’s show. If the Brown family and the Gonzales family both have the same number of members, does the Brown family have a better chance of appearing on Wringer’s show than does the Gonzales family?
(1) In each family, male members argue with each other, and female members argue with each other, but male members do not argue with female members and vice versa.
(2) The Brown family has the same number of male members as female members. The Gonzales family has more male members than female members.
(1) In each family, male members argue with each other, and female members argue with each other, but male members do not argue with female members and vice versa.
(2) The Brown family has the same number of male members as female members. The Gonzales family has more male members than female members.
14 Nov 2023, 13:16
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The answer should be (C).
(1) This statement clarifies that within each family, arguments occur among male members separately and among female members separately. However, it doesn’t provide information about the actual percentage or proportion of family members who argue --> Insufficient.
(2) This statement indicates that the Brown family has an equal number of male and female members, while the Gonzales family has more male members than female members. No information is provided about who can argue with whom --> Insufficient.
Combined:
Let the total members per family = 6
--> Brown family = 3 men (A, B & C) and 3 women (D, E & F)
Possibilities of arguments = AB, AC, BC, DE, DF, EF = 6
whereas, for Gonzales family let's take 4 men (A, B, C & D) and 2 women (E & F)
--> Possibilities of arguments = AB, AC, AD, BC, BD, CD, EF = 7
or let's take 5 men (A, B, C, D & E) and 1 woman (F)
--> Possibilities of arguments = AB, AC, AD, AE, BC, BD, BE, CD, CE, DE = 10
Hence, taken together the statements indicate that the Gonzales family has a higher chance of appearing on the show.
(1) This statement clarifies that within each family, arguments occur among male members separately and among female members separately. However, it doesn’t provide information about the actual percentage or proportion of family members who argue --> Insufficient.
(2) This statement indicates that the Brown family has an equal number of male and female members, while the Gonzales family has more male members than female members. No information is provided about who can argue with whom --> Insufficient.
Combined:
Let the total members per family = 6
--> Brown family = 3 men (A, B & C) and 3 women (D, E & F)
Possibilities of arguments = AB, AC, BC, DE, DF, EF = 6
whereas, for Gonzales family let's take 4 men (A, B, C & D) and 2 women (E & F)
--> Possibilities of arguments = AB, AC, AD, BC, BD, CD, EF = 7
or let's take 5 men (A, B, C, D & E) and 1 woman (F)
--> Possibilities of arguments = AB, AC, AD, AE, BC, BD, BE, CD, CE, DE = 10
Hence, taken together the statements indicate that the Gonzales family has a higher chance of appearing on the show.
14 Nov 2023, 21:51
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Bunuel
OA is C.
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