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firas92
Current Student
Joined: 16 Jan 2019
Last visit: 02 Dec 2024
Posts: 616
Given Kudos: 142
Location: India
Concentration: General Management
Schools: Tepper '23 (M$) Foster '23 (D)
GMAT 1: 740 Q50 V40
WE:Sales (Other)
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21 Jun 2019, 23:29
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
24% (01:44) correct
76%
(02:03)
wrong
based on 86
sessions
History
Date
Time
Result
Not Attempted Yet
Find the number of ways in which 5 men can watch 4 movies such that each movie is watched by at least one person and no one can watch more than one movie.
A. 150
B. 240
C. 360
D. 480
E. 120
A. 150
B. 240
C. 360
D. 480
E. 120
22 Jun 2019, 06:19
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firas92
One way not to go wrong is to first get the persons in proper grouping..
So, get the way two people can be one group and rest all in single --- 5C2=10
Next we have persons in 2-1-1-1 groups and each such combination can watch 4 different movies in 4! ways..
Total ways = 5C2*4!=\(\frac{5*4}{2}*4!=10*24=240\)
B
28 Jun 2019, 01:48
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total movie combination ; 4! ; 24
and choosing men at least 1 out of 5 ; 5c2; 10 ways
total possiblitiesl 24*10; 240
IMO B
and choosing men at least 1 out of 5 ; 5c2; 10 ways
total possiblitiesl 24*10; 240
IMO B
firas92
