Last visit was: 18 Nov 2025, 19:02 It is currently 18 Nov 2025, 19:02
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
ankitranjan
Joined: 08 Sep 2010
Last visit: 13 Dec 2012
Posts: 109
Own Kudos:
846
 [79]
Given Kudos: 21
Location: India
Concentration: Finance
WE 1: 6 Year, Telecom(GSM)
Posts: 109
Kudos: 846
 [79]
6
Kudos
Add Kudos
73
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,081
 [48]
24
Kudos
Add Kudos
24
Bookmarks
Bookmark this Post
User avatar
ankitranjan
Joined: 08 Sep 2010
Last visit: 13 Dec 2012
Posts: 109
Own Kudos:
846
 [25]
Given Kudos: 21
Location: India
Concentration: Finance
WE 1: 6 Year, Telecom(GSM)
Posts: 109
Kudos: 846
 [25]
21
Kudos
Add Kudos
4
Bookmarks
Bookmark this Post
General Discussion
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
778,081
 [3]
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,081
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
ankitranjan
Bunuel You are the best.But there is one theorem that is Wilson's theorem...It states that
If n is a prime number ,(n-1)!+1 is divisible by n.

Hence 16!+1 i.e (17-1)! + 1 will be divisible by 17.

Consider Kudos if u find this interesting.

Yes, Wilson's theorem works for this particular number. Though you won't need this theorem for GMAT.
User avatar
stonecold
Joined: 12 Aug 2015
Last visit: 09 Apr 2024
Posts: 2,244
Own Kudos:
3,549
 [1]
Given Kudos: 893
GRE 1: Q169 V154
GRE 1: Q169 V154
Posts: 2,244
Kudos: 3,549
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Using the logic => Multiple +non multiple = non multiple => discarding all the options => only 17 is the viable choose..
Remember => we dont really have to compute the values here.. All is in the logic
avatar
bazu
Joined: 17 Aug 2016
Last visit: 06 Apr 2020
Posts: 37
Own Kudos:
15
 [1]
Given Kudos: 81
Posts: 37
Kudos: 15
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel could you advise me if the following is a correct solution or if I am inventing math?

16! = 17!/17 --> 17!/17 + 1 =(17!+17)/17 ---> 16!+1 divisible by 17
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 18 Nov 2025
Posts: 105,355
Own Kudos:
Given Kudos: 99,964
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 105,355
Kudos: 778,081
Kudos
Add Kudos
Bookmarks
Bookmark this Post
bazu
Bunuel could you advise me if the following is a correct solution or if I am inventing math?

16! = 17!/17 --> 17!/17 + 1 =(17!+17)/17 ---> 16!+1 divisible by 17

16!+1=(17!+17)/17 but how do you conclude that (17!+17)/17 is divisible by 17? In other words how do you know that [(17!+17)/17]/17 is an integer?
avatar
bazu
Joined: 17 Aug 2016
Last visit: 06 Apr 2020
Posts: 37
Own Kudos:
Given Kudos: 81
Posts: 37
Kudos: 15
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
bazu
Bunuel could you advise me if the following is a correct solution or if I am inventing math?

16! = 17!/17 --> 17!/17 + 1 =(17!+17)/17 ---> 16!+1 divisible by 17

16!+1=(17!+17)/17 but how do you conclude that (17!+17)/17 is divisible by 17? In other words how do you know that [(17!+17)/17]/17 is an integer?

oh, yes I see, what I had in my mind does't actually make sense! thanks!
User avatar
Mbawarrior01
Joined: 12 Oct 2012
Last visit: 23 Jan 2018
Posts: 92
Own Kudos:
Given Kudos: 198
WE:General Management (Other)
Posts: 92
Kudos: 366
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Learnt a new concept.
But when I apply the same to smaller factorials such as 5!+1 = 121 (divisible by 11 and not by 6-because of 3 & 2 in 5! but what about 7).

Is there any exception to the theorem?
User avatar
broall
User avatar
Retired Moderator
Joined: 10 Oct 2016
Last visit: 07 Apr 2021
Posts: 1,138
Own Kudos:
7,148
 [2]
Given Kudos: 65
Status:Long way to go!
Location: Viet Nam
Posts: 1,138
Kudos: 7,148
 [2]
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Mbawarrior01
Learnt a new concept.
But when I apply the same to smaller factorials such as 5!+1 = 121 (divisible by 11 and not by 6-because of 3 & 2 in 5! but what about 7).

Is there any exception to the theorem?

You could see this theorem here: https://en.wikipedia.org/wiki/Wilson's_theorem

The theorem is applied for prime p and (p-1)!+1 divisible by p.

Hence, 4!+1 is divisible by 5. However, 5!+1 will not be divisible by 6.

This theorem could be proved by using advanced mathematic tools, thus this theorem is too hard and we no need to learn this theorem in solving GMAT PS/DS questions.
User avatar
cavana
Joined: 20 Jan 2017
Last visit: 20 Jun 2018
Posts: 33
Own Kudos:
44
 [1]
Given Kudos: 15
Location: United States (NY)
Schools: CBS '20 (A)
GMAT 1: 610 Q34 V41
GMAT 2: 750 Q48 V44
GPA: 3.92
Products:
Schools: CBS '20 (A)
GMAT 2: 750 Q48 V44
Posts: 33
Kudos: 44
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
1) Two consecutive integers do not have any factors in common other than 1. This means that factor of 16!+1 has to be a number that is not a factor of 16!
2) 7, 1, and 6 are factors of 16! as they are multiples of 16!, 18 is also a factor of 16! because 2 and 9 are factors of 16!
3) By deduction, the only factor that is not a multiple of 16! is 17, and this means that it is a multiple of 16!+1

The correct answer is C.
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 18 Nov 2025
Posts: 21,712
Own Kudos:
26,990
 [1]
Given Kudos: 300
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 21,712
Kudos: 26,990
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
ankitranjan
Find the number that divides 16!+1?

A. 7
B. 11
C. 17
D. 6
E. 18

We need to determine which one of the numbers in the given answer choices divides into 16! + 1. In other words, which one is a factor of 16!+1. To determine this, we must recognize that 16! and 16! + 1 are consecutive integers, and consecutive integers will never share the same prime factors. Thus, 16! and 16! + 1 must have different prime factors.

However, rather than breaking 16! factorial into primes, we can look at the answer choices to determine which choice is not a factor of 16!. Since 16! = 16 x 15 x 14…5 x 4 x 3 x 2 x 1, we see that choices A, B, and D are factors of 16! Since 18 = 2 x 9, 2 and 9 are also factors of 16!. However, none of these numbers (6, 7, 11, and 18) will be a factor of 16! + 1, so the only number that can be a factor of 16! + 1 is 17.

Answer: C
User avatar
RahulJain293
Joined: 24 Apr 2022
Last visit: 25 May 2025
Posts: 167
Own Kudos:
Given Kudos: 96
Location: India
Concentration: General Management, Nonprofit
GMAT Focus 1: 585 Q81 V80 DI76
GMAT Focus 1: 585 Q81 V80 DI76
Posts: 167
Kudos: 100
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Here is how I went about this...

Unit's digit of 16! is 0 and + 1 gives 1 as unit's digit --> Hence this is an ODD Number.

Eliminate D & E as both are EVEN Numbers and hence cannot divide without leaving a remainder.

For A,B & C (7,11,17)

We know 16! has divisors 1 to 16 (option A&B divides 16!).. Meaning, 16!+1 (which is coprime to 16!) will not have an A&B as their divisors and hence only C (17) divides the number 16!+1­
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,588
Own Kudos:
Posts: 38,588
Kudos: 1,079
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Moderators:
Math Expert
105355 posts
Tuck School Moderator
805 posts