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Re: For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 [#permalink]
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Engineer1 wrote:
lpetroski wrote:
For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 for each 1/2 mile or fraction of 1/2 miles. If, for every number x, [ x ] is defined to be the least integer greater than or equal to x, then which of the following represents the company's charge, in dollars, for a trip that is r miles long?

A. 2.00 + [ \(\frac{0.75r}{2}\) ]
B. 2.00 + 0.75[ \(\frac{r}{2}\) ]
C. 2.00 + 0.75[ r ]
D. 2.00 + [1.5r ]
E. 2.00 + 0.75 [ 2r]



chetan2u KarishmaB MartyMurray

Hi All, I did it correctly in my practice test 6. And I understand that in 5.5 miles, it would be 11 half miles, and in 5.7 it will be 12 half miles.
I also solved the kind of problems before similar to the sentence below, but just not together as it is in this problem. I got the answer of my calculation as E, so I checked it. But I could not figure out where the below sentence fit in. Is it because 5.7 means 6? Well, even without this sentence, the problem does not change, I guess. Any clarification is highly appreciated.

Thank you!

for every number x, [ x ] is defined to be the least integer greater than or equal to x,



It is because r need not be an integer.

Say he traveled 0.6 miles. The cost he incurred is 2$ as fixed charge and 0.75$ for first 0.5 miles and another 0.75$ for remaining 0.1 miles.
Total becomes 2+2*0.75 = 3.5$

Now, if we did not have [x], the answer would be 2+0.75*(2*0.6) = 2.9$, which will be wrong.
The answer is 2+0.75[2*0.6] = 2+0.75*2 = 3.5$

So, [] is ensuring that you have miles in multiples of 1/2 mile.
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Re: For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 [#permalink]
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