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# For every integer k from 1 to 10, inclusive, the kth term of a certain

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Joined: 15 Feb 2017
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For every integer k from 1 to 10, inclusive, the kth term of a certain  [#permalink]

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21 Oct 2018, 05:07
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For every integer k from 1 to 10, inclusive, the kth term of a certain sequence is given by \small \left ( -1 \right )^{k+1} \left ( \frac{1}{2^{k}} \right ). If T is the sum of the first 10 terms in the sequence, then T is

A greater than 2
B between 1 and 2
C between \small \frac{1}{2} and 1
D between \small \frac{1}{4} and \small \frac{1}{2}
E less than \small \frac{1}{4}

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IMPOSSIBLE IS JUST AN OPINION
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Joined: 02 Sep 2009
Posts: 57244
Re: For every integer k from 1 to 10, inclusive, the kth term of a certain  [#permalink]

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21 Oct 2018, 05:09
sonusaini1 wrote:
For every integer k from 1 to 10, inclusive, the kth term of a certain sequence is given by \small \left ( -1 \right )^{k+1} \left ( \frac{1}{2^{k}} \right ). If T is the sum of the first 10 terms in the sequence, then T is

A greater than 2
B between 1 and 2
C between \small \frac{1}{2} and 1
D between \small \frac{1}{4} and \small \frac{1}{2}
E less than \small \frac{1}{4}

Discussed here: https://gmatclub.com/forum/for-every-in ... 88874.html

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Re: For every integer k from 1 to 10, inclusive, the kth term of a certain   [#permalink] 21 Oct 2018, 05:09
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