Hi All,

Another way to solve the question, imagine a square joining the centres of 4 circles. See picture below.

You know the radius=5. So the area of new square= 100.

You have to substract the 4 sectors. The area of sector= PI R*R*angle/360= PI* 5 *5 /4 = 25 PI/4 (multiplying by four, because we have 4 sectors)

=25PI. ( Angle subtended at the centre=90 and hence we took the angle 90)

So area of shaded region = 100-25PI.

genuinebot85 wrote:

Four identical circles are drawn in a square such that each circle touches two sides of the square and two other circles (as shown in the figure below). If the side of the square is of length 20 cm, what is the area of the shaded region?

Attachment:

The attachment **GeometryPost12Ques2.jpg** is no longer available

(A) 400 – 100π

(B) 200 – 50π

(C) 100 – 25π

(D) 8π

(E) 4π

Could not understand the solution, need help.

Attachments

GeometryPost12Ques2.jpg [ 8.75 KiB | Viewed 26992 times ]

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Kudos to you, for helping me with some KUDOS.