GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 17 Jun 2018, 16:59

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# From a group of 10 boys and 7 girls, how many different 6-person hocke

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 46035
From a group of 10 boys and 7 girls, how many different 6-person hocke [#permalink]

### Show Tags

13 May 2017, 14:33
00:00

Difficulty:

15% (low)

Question Stats:

88% (00:53) correct 13% (00:55) wrong based on 44 sessions

### HideShow timer Statistics

From a group of 10 boys and 7 girls, how many different 6-person hockey teams can be formed if the team must consist of 3 girls and 3 boys?

A. 155
B. 1200
C. 1360
D. 4200
E. 12376

_________________
Senior CR Moderator
Status: Long way to go!
Joined: 10 Oct 2016
Posts: 1387
Location: Viet Nam
Re: From a group of 10 boys and 7 girls, how many different 6-person hocke [#permalink]

### Show Tags

13 May 2017, 20:36
Bunuel wrote:
From a group of 10 boys and 7 girls, how many different 6-person hockey teams can be formed if the team must consist of 3 girls and 3 boys?

A. 155
B. 1200
C. 1360
D. 4200
E. 12376

Select 3 girls from 7 girls, there are $$7C3= \frac{5\times 6 \times 7}{2 \times 3}=35$$ different selections.

Select 3 boys from 10 boys, there are $$10C3=\frac{8 \times 9 \times 10}{2 \times 3}=120$$ different selections

The total combination is $$35 \times 120 =4200$$

_________________
SVP
Joined: 08 Jul 2010
Posts: 2114
Location: India
GMAT: INSIGHT
WE: Education (Education)
Re: From a group of 10 boys and 7 girls, how many different 6-person hocke [#permalink]

### Show Tags

13 May 2017, 20:55
Bunuel wrote:
From a group of 10 boys and 7 girls, how many different 6-person hockey teams can be formed if the team must consist of 3 girls and 3 boys?

A. 155
B. 1200
C. 1360
D. 4200
E. 12376

Step 1: SELECT 3 boys out of 10 available boys = 10C3 = 120

Step 2: SELECT 3 Girls out of 7 available Girls = 7C3 = 35

For dependent events, we multiply the steps

Total Ways to make team = 10C3 * 7C3 = 120*35 = 4200

_________________

Prosper!!!
GMATinsight
Bhoopendra Singh and Dr.Sushma Jha
e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772
Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi
http://www.GMATinsight.com/testimonials.html

22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION

Manager
Joined: 04 Jan 2016
Posts: 167
Location: United States (NY)
GMAT 1: 620 Q44 V32
GMAT 2: 600 Q48 V25
GMAT 3: 660 Q42 V39
GPA: 3.48
Re: From a group of 10 boys and 7 girls, how many different 6-person hocke [#permalink]

### Show Tags

14 May 2017, 15:14
The solution is numbers of chosen boys times the number of chosen girls, therefore:

$$10C3 * 7C3 = \frac{10*9*8}{1*2*3} * \frac{7*6*5}{1*2*3}= 120*35=4200$$

The Correct option is: D
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 2738
Location: United States (CA)
Re: From a group of 10 boys and 7 girls, how many different 6-person hocke [#permalink]

### Show Tags

18 May 2017, 20:09
1
Bunuel wrote:
From a group of 10 boys and 7 girls, how many different 6-person hockey teams can be formed if the team must consist of 3 girls and 3 boys?

A. 155
B. 1200
C. 1360
D. 4200
E. 12376

We need to determine how many 6-person hockey teams can be formed if the team must consist of 3 girls and 3 boys.

The number of ways to select the boys is 10C3 = 10!/[3!(10-3)!] = (10 x 9 x 8)/3! = (10 x 9 x 8)/(3 x 2) = 120.

The number of ways to select the girls is 7C3 = 7!/[3!(7-3)!] = (7 x 6 x 5)/(3 x 2) = 35.

Thus, the number of ways to select the teams is 120 x 35 = 4,200.

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Re: From a group of 10 boys and 7 girls, how many different 6-person hocke   [#permalink] 18 May 2017, 20:09
Display posts from previous: Sort by