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From a group of 6 boys and 6 girls a volleyball team of 6 players is

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From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 25 Nov 2019, 01:45
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From a group of 6 boys and 6 girls a volleyball team of 6 players is to be selected. What is the probability that the team consists of 4 boys and 2 girls?

A. \(\frac{5}{33}\)

B. \(\frac{225}{308}\)

C. \(\frac{5}{22}\)

D. \(\frac{225}{311}\)

E. \(\frac{75}{308}\)


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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 25 Nov 2019, 01:59
Total selections: 12!/6!6!=924
favored selections: Boys 6!/2!4!=15; GIlrs 6!/2!6!=15; 15*15=225

\(\frac{225}{924}=\frac{75}{308}\)

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ans: E
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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 25 Nov 2019, 02:34
Total ways to choose team = 12c6
for boys = 6c4
for girls = 6c2
total P = 6c4*6c2/12c6 = \(\frac{75}{308}\)
IMO E

Bunuel wrote:
From a group of 6 boys and 6 girls a volleyball team of 6 players is to be selected. What is the probability that the team consists of 4 boys and 2 girls?

A. \(\frac{5}{33}\)

B. \(\frac{225}{308}\)

C. \(\frac{5}{22}\)

D. \(\frac{225}{311}\)

E. \(\frac{75}{308}\)


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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 25 Nov 2019, 03:20
Order is not important hence combinations can be used.

(6C4)*(6C2) / (12C6)
= E
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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 26 Nov 2019, 08:56
Bunuel wrote:
From a group of 6 boys and 6 girls a volleyball team of 6 players is to be selected. What is the probability that the team consists of 4 boys and 2 girls?

A. \(\frac{5}{33}\)

B. \(\frac{225}{308}\)

C. \(\frac{5}{22}\)

D. \(\frac{225}{311}\)

E. \(\frac{75}{308}\)


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P(4B2G)=FAVORABLE CASES/POSSIBLE CASES
TOTAL: 12C6
FAVORABLE: 6C4*6C2
P(4B2G)=6C4*6C2/12C6=75/308

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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 02 Dec 2019, 19:17
Bunuel wrote:
From a group of 6 boys and 6 girls a volleyball team of 6 players is to be selected. What is the probability that the team consists of 4 boys and 2 girls?

A. \(\frac{5}{33}\)

B. \(\frac{225}{308}\)

C. \(\frac{5}{22}\)

D. \(\frac{225}{311}\)

E. \(\frac{75}{308}\)


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The number of ways to select 2 girls from 6 girls is 6C2 = (6 x 5)/2! = 15. Similarly, the number of ways to select 4 boys from 6 boys is 6C4 = (6 x 5 x 4 x 3)/(4 x 3 x 2) = 15. Therefore, the total number of ways of selecting 2 girls and 4 boys is 15 x 15 = 225.

The number of ways to select 6 players from 12 players is:

12C6 = (12 x 11 x 10 x 9 x 8 x 7)/(6 x 5 x 4 x 3 x 2) = 2 x 11 x 2 x 3 x 7 = 924

So, the overall probability is 225/924 = 75/308.

Alternate Solution:

Let’s first calculate the probability of the choice B - B - B - B - G - G, in that order:

6/12 x 5/11 x 4/10 x 3/9 x 6/8 x 5/7 = (6 x 5 x 4 x 3 x 6 x 5)/(12 x 11 x 10 x 9 x 8 x 7) = 5/(11 x 4 x 7) = 5/308

Notice that B - B - B - B - G - G can be arranged in 6!/(4!*2!) = (6 x 5)/2 = 15 ways. Thus, the probability that the team consists of 4 boys and 2 girls is (5/308) x 15 = 75/308.

Answer: E
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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 11 Dec 2019, 21:56
I have a stupid question. Why isn't the total outcome over here = 2^ 6 = 64 ?

Isn't this similar to our fair coin problems where we have 2 possible outcomes for one scenario and we can just multiply them together.

Thank you for the feedback !
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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is  [#permalink]

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New post 12 Dec 2019, 02:00
is there a simpler way to solve this question
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Re: From a group of 6 boys and 6 girls a volleyball team of 6 players is   [#permalink] 12 Dec 2019, 02:00
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