Bunuel
The ratio of two positive integers, m and n, is 4 to 3. If the values of m and n are increased in a ratio of 1 to 1, which of the following cannot be the resulting integers?
I. 8 to 5
II. 6 and 5
III. 15 and 14
A. I only
B. II only
C. III only
D. I and II only
E. I and III only
GMAT Club Official Explanation:
When two numbers are
increased in a ratio of 1:1, it implies that the
same positive number was added to both of them.
If a fraction is between 0 and 1, adding the same positive number to both the numerator and denominator increases the value of the fraction. For instance, if we add 2 to the numerator and denominator of 1/3, we get (1 + 2)/(3 + 2) = 3/5, which is greater than the initial fraction of 1/3.
If a fraction is more than 1, adding the same positive number to both the numerator and denominator decreases the value of the fraction. For instance, if we add 2 to the numerator and denominator of 3/2, we get (3 + 2)/(2 + 2) = 5/4 = 1.25, which is less than the initial fraction of 3/2 = 1.5.
For the question at hand, the original ratio was 4:3, which is more than 1 (≈1.3), thus adding the same positive number to both the numerator and the denominator will decrease the value of the new ratio, bringing it closer to, but still above 1. Therefore, both 6 and 5 (6/5 = 1.2), and 15 and 14 (15/14 ≈ 1.07), are possible values for the resulting integers since their ratio is less than 1.3, while 8 to 5 cannot be the resulting integers, as their ratio is 1.6, which is greater than 1.3.
Answer: A.