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3/sec x 60 seconds = 180 per minute

5/6 sec X 10 = 50 per min

= 180 small + 50 large per crate
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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R(small bottle)=3 per sec
total small bottles =3*60=180
R(large bottles)=5/6
total large bottles=60*5/6=50
shipping crates=10
small bottle per crate=180/10=18
large bottle per crate=50/10=5
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Quote:
A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Small Bottles Large Bottles
3
5
18
50
90
180


Number of small bottles in 1 minute = 60*3 = 180

Number of large bottles in 1 minute = 5/6*60 = 50

If both the same and large number bottles have to be same, and we have to make 10 crate, then large bottles is the limiting factor here.

Max large bottles that can be in each crate = 50/10 => 5, and the small will also be the same = 5

Hence, for both the answer is 5
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small bottles filled in one minute= 3*60 = 180
Large bottles filled in one minute= 5/6 * 60 = 50
There are 10 crates and there is equal division of bottles.
Small bottles in one crate= 180/10 = 18
Large bottles in one crate= 50/10 = 5
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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The machine runs for one minute, which is 60 seconds.

Small bottles:
Rate = 3 per second
In 60 seconds: 3 × 60 = 180 small bottles

Large bottles:
Rate = 5 every 6 seconds = 5 ÷ 6 per second
In 60 seconds: (5 ÷ 6) × 60 = 50 large bottles

These 180 small and 50 large bottles are packed into exactly 10 identical shipping crates.

So each crate has:
180 ÷ 10 = 18 small bottles
50 ÷ 10 = 5 large bottles

Answer: Small bottles = 18, Large bottles = 5
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From the question stem, we can deduce that 3 small bottles and 5/6 large bottles are filled per second.

In one minute, 3*60 = 180 small bottles and 5/6*60 = 50 large bottles will be filled.

In 10 shipping crates with equal number of small and large bottles, 180/10 =18 small bottles and 50/10 = 5 large bottles can be packed.

Therefore, Small Bottles = 18 and Large Bottles = 5
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In 1 minute the no. of small bottles filled = 180

In 1 minute the no. of large bottles filled = 50

So the no. of small bottles per crate = 180/10 = 18

and the no. of large bottles per crate = 50/10 = 5

Answer: 18, 5
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Small Bottle

1 second = 3 bottles
60 secs = 3*60=180 bottles

Large bottle

6 seconds = 5 bottles
60 seconds = 5*60/6 = 50 bottles

Each of 180 small and 50 large bottles are packed in 10 crates each. Therefore each crate contains 18 small and 5 large bottles.
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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The answer is Small Bottles :- 18 ; Large bottles :- 5
Small bottles are filled at 3 per sec.
Hence after 1 minute , 180 small bottles are filled.
Since 10 shipping crates are filled , 180/10 = 18 small bottles should be there in each crate.

Large bottles are filled at 5 per 6 seconds.
Hence , (5/6) * 60 = 50 large bottles are filled in 1 minute.
Hence 50/10 = 5 large bottles should be there in each crate.

Bunuel
 


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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Small bottles: In 1 sec --- it fills 3, In 60 sec --- it fills 180 bottles.
large bottles: In 6 secs--- it fills 5 bottles. In 1 sec--- it fills \(\frac{5}{6}\) bottles, In 60 secs--- it fills 50 bottles.
Now,we have 180 small ones and 50 large ones.
To fill them in 10 crates, divide by 10. Thus, each crate will have 18 small ones and 5 large ones.
Bunuel
 


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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Small bottles = 18, Large bottles = 5

Given that Rate for Small bottles = 3 per sec
Rate for Large bottles = 5 per 6 sec
Hence total Small bottles in 1 minute (60 seconds) is 3 * 60 = 180 and Large bottles = 5/6 * 60 = 50
By distributing these numbers in 10 bottles equally,
Small bottles = 180/10 = 18
Large bottles = 50/10 = 5
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First, calculate the number of bottles that machine filled in 1 min = 60s.
- Small bottle: 1s-> 3 bottles
60s-> 180 bottles
- Large bottle: 6s-> 5 bottles
60s-> 50 bottles
So 180 small and 50 large bottles are packed into exactly 10 shipping crates, so each crate will be 18 small and 5 large bottles.
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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5,5. Because small and large have too be same in each cart, we need to find the value which is lesser, as in whose rate is less. Looking at the info given, 5 every 6 seconds is less, which will give 5o bottles in a min, so 50-50 for small and large both, there are 10 cartons, each will hence have 5.
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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In one minute:
Small bottles filled will be 3*60 seconds = 180 bottles
Large bottles filled will be 5/6 * 60 seconds = 50 bottles

But these are equally divided into 10 shipping crates, so each crate will have 18 small bottles and 5 large bottles.
Bunuel
 


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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Small -Given 3 per second which means in 60 seconds=it will produce 60*3=180 Bottles
Large-
Given 5 every 6 seconds
in 1 second=[5/6]
60 seconds=[5/6]*60= 50

Therefore the produced rate is now 180 small bottles and 50 large bottles. These have to be put in 10 crates, with each crate having equal number of Small and large bottles- which means we divide both by 10.
Therefore each Crate will have 18 Small Bottles and 5 large bottles.

Bunuel
 


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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Total small bottles produced in 1 min is 3 x 60 which is 180 and total large bottles produced in 1 min is 5//6 x 60 which is 50

the Q.S. states that the bottles are packed in 10 crates, thus 1 crate will have 18 small bottles and 5 large bottles.
Bunuel
 


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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Rates given:

Small bottle = 3/sec
Large bottle = 5/6 sec


So, in 6 sec 18 small and 5 large bottles => in 60 seconds 180 small and 50 large.

Divided into 10 equal crates => 18*10 small and 5*10 large bottles.

Answer: 18 small/crate and 5 large/crate.
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