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Speed of small bottles - 3 per sec - 3*60 = 180 bottles per minute
Speed of large bottles = 5 bottles per 6 second = 5*60/6 = 50 bottles per minute

Now 10 crates consists the same number of small bottles and the same number of large bottles in each crate.
Now each shipping crate consists - 180/10 = 18 small bottles and 50/10 = 5 large bottles.
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small bottles = 3*60 = 180/min
large bottles = 5*10 = 50/min

180/10 = 18/shipping_crate
50/10 = 5/shipping_crate

Small Bottles = 18
Large Bottles = 5
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SB rate 3 per sec, then in 1 min(60sec)
Total SB is 3*60=180 and therefore 18/crates distribution( total crate)

LB rate 5/6 per sec, then in 1 min
Total LB is 5×60/6=50 &therefore 5/crate(total 10 crate)

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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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total time we have is 1min=60 seconds.
No. of small bottles we can fill in that time is 180
No. of big bottles we can fill is 5* (60/6) =50 bottles

After this, I approached to see the highest common factor which is 10.
now if we have 10 shipping crates and we have to distribute 180 small and 50 big bottles then we will have 18 small in and 5 big in each crates

So, 5 big and 18 small is the correct choice
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Bunuel
A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Rate for Small = 3 bottle / sec;
Rate for Large = 5 bottle / 6 sec;

For One minute continuous operation; 3 * 60 = 180 Small; 5 * 60 / 6 = 50 Large;
180 small in 10 shipping crates; 18 per crate
50 large in 10 shipping crates; 5 per crate
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3 small bottles per second, that is, 180 small bottles in one minute (60/1*3).

5 large bottles every 6 seconds, that is, 50 large bottles in one minute (60/6*5).

To create 10 packs with the same amount of small and large bottles, we need to divide 180 and 50 by 10. Finally, we have 18 small bottles and 5 large bottles per case.
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Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Rate of small bottles = 3 per sec

Hence in 1 minute = 3* 60 = 180 bottles

Rate of large bottles = 5 per 6 seconds
Hence rate in 1 minute = 5 * 10 = 50 bottles

Therefore, If all these are packed in 10 shipping containers then in 1 crater = 180/10 for small bottles = 18
and = 50/10 = 5 of Large bottles. Hence, the answer.
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Bunuel
 


This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.

Small bottles = \(\frac{3 bottles }{sec}\)

Large bottles = \(\frac{5 bottles }{ 6 sec}\)

Total bottles filled in 1 minute

Small bottles = \(\frac{3 bottles }{ 1 sec} * 60 sec\) = 180

Large bottles = \(\frac{5 bottles }{ 6 sec} * 60 sec\) = 50

Total crates = 10

If each crate contains same number of large and small bottles then for each crate we have

Large bottles per crate = \(\frac{50}{10}\) = 5

Small bottles per crate = \(\frac{180}{10}\) = 18

Small Bottles = 18
Large Bottles = 5
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Small bottles:
Rate = 3 per second
Time = 60 seconds
Total bottles = 3*60 = 180

Large bottles:
Rate = 5/6 per second
Time = 60 seconds
Total bottles = (5/6)*60 = 50

Each crate contains same number of large and small bottles and there are 10 crates
So,

=> Small bottles in each crate = 180/10 = 18
Large bottles in each crate = 50/10 = 5

Small bottles : 18
Large bottles : 5
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  • Small bottles filled in 1 minute or 60 seconds: 3×60=180
  • Large bottles filled in 1 minute or 60 seconds: (5/6)×60=50

  • Small bottles per crate: 180/10=18
  • Large bottles per crate: 50/10=5

Answer: Small bottles - 18; Large bottles - 5
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3 small bottles/s * 60 s/min = 180 small bottles/min
5 large bottles/6s * 60 s/min = 50 large bottles/min

180 small bottles/10 shipping crates = 18 small bottles/shipping crate
50 large bottles/10 shipping crates = 5 large bottles/shipping crate

Answers: Small Bottles = 18, Large Bottles = 5
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If it fills small bottles at a constant rate of 3 per second, it fills 180 in one minute.
If it fills large bottles at a constant rate of 5 every 6 seconds, it fills 50 in one minute.

As we have 10 shipping crates, 180/10 = 18 small bottles and 50/10 = 5 large bottles in each shipping crate.

Correct answers are 18 small bottles and 5 large bottles.
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Small bottles per crate=18
Large Bottles per crate=5
explanation
small bottles
rate=3/5 which is 180 in a minute(3*60)
per crate= 180/10= 18

2 Large bottles
rate= 5 every 6 sec.
50 in a min. (5*(60/6)
per crate= 50/10= 5 crates
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First i need to find the total number of bottles in order to know how many are going to be packed.

For Small: 30 x 60 =1,800
For Large: 5/6*60 = 50
TOTAL 1,850
And i know that in each packed there MUST be 185 bottles: Small + Large
Looking at the answer 180 and 5 are the best, and Small have a highest number of bottles (because the rate is quicker).
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in 1 min(60 secs) the number of Small bottles filled= 3*60=180 bottles
The number of Large bottles filled= 5*60/5=50 bottles
It has to distributed in to 10 crates
so no of Large bottles in each crate= 50/10=5
no of small bottles in each crate=180/10=18
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SB per minute = 3*60 = 180
LB per minute = 5*10 = 50

SB per shipping crate = 180/10 = 18
LB per shipping crate = 50/10 = 5

The right answers are Small Bottles = 18 and Large Bottles = 5
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In this question if you misread or did not pay attention at one or the other part of the question you are bound to make error.
Points to be notice
1 Both bottles are being filled at same time
2 Rate of filling small bottle = 3 Bottle/sec
3 Rate of filling large bottle = 5/6 Bottle/sec
4 number of bottles in each 10 crates are same
5 All 10 crates are being filled in 1 min or 60 sec

Lets say there are x small bottle in each crate and y large bottle in each crate and question is asking us to find small/large bottle in each crate.

For small bottle
Total small bottles = 10x
Work = rate X Time
10x/3 = 60
x = 18

For large bottle
Total large bottle = 10y
10y/(5/6) = 60
y = 5
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