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Bunuel
 


This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
1- Small bottles

Rate = 3 bottles for 1 seconds.

So the machine will fill a total of : 60 seconds *3 bottles/seconds = 180 small bottles in 1 minutes (60 seconds)

The tricky part is that we are asked the number of small bottles in each shipping crate. As we have 10 shipping crates, the number of small bottles for each crates is 180 / 10 = 18

2- Large bottles

Rate = 5 bottles every 6 seconds. Following the same logic we find :

Total Large bottles = 60*5/6 = 50 large bottles

The number in each crate = 50/10 = 5 large bottles
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Small Bottle rate of machine: 3 bottles per 1 sec or 18 bottles per 6 sec. So in 1 minute it will fill 180 bottles.

Large Bottle rate of machine: 5 bottles per 6 sec. So in 1 minute it will fill 50 bottles.

Now there are 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Small can be 180/10 = 18, Large can be 50/10 = 5 i.e. total 23 bottles in each crate.

Answer is C, B.
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We are told:

Small bottles are filled at 3 per second, so in 60 seconds:

3×60=180 small bottles

Large bottles are filled at 5 every 6 seconds, so per second it's:

(5/6)bottles/sec

In 60 seconds ⇒(5/6)×60=50 large bottles

Now, these bottles are packed into 10 shipping crates, each with the same number of small and large bottles.

So:

Small bottles per crate = 180/10 = 18

Large bottles per crate = 50/10 = 5
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Let \( s\) = number of small bottles per crate, \( l \) = number of large bottles per crate.

- Small bottles filled in 1 minute = \( 3 \times 60 = 180 \).
- Large bottles filled in 1 minute = \( \frac{5}{6} \times 60 = 50 \).
- Total crates = 10.

- Total small bottles = \( 180 \), total large bottles = \( 50 \).
- Per crate: \( \frac{180}{10} = 18 \) small bottles, \( \frac{50}{10} = 5 \) large bottles.
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Bunuel
 


This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
Rate for small bottles = 3 per second, Large = 5/6 per second
Lets aasumme in each caret number of small bottle = x, Large bottle = y
In 10 crate = 10x , 10y

10x/3=10y/(5/6)=60y/5=12y
X=36/10*Y =18/5Y

Upon trying combinations when y = 50 -> x=180
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small bottles: 3 per second
large bottles: 5 every 6 seconds = 5/6 per second
in 1 minute (60 seconds):

small: 3 × 60 = 180 bottles
large: (5/6) × 60 = 50 bottles

these go into 10 crates equally:

small per crate: 180 ÷ 10 = 18
large per crate: 50 ÷ 10 = 5

so its 18 small bottles and 5 large bottles per crate.
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Rate:
Small bottles = 3b/sec => 180b/min
Large bottles = 5b/6sec => 50b/min

Now, since, the total number of each type of bottle is packed into 10 crates with each crate having the same number of small and large bottles,

Total small bottles in each crate = 180/10 = 18
Total large bottles in each crate = 50/10 = 5
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Small Bottle 3 qty per second, 3*60=180 Bottles
Large Bottle 5 qty every 6 second, 5*10 for 6*10 seconds=50 bottles. Total 10 crates ,
per crate is 180/10 =18 small bottles
per crate is 50/10 =5 large bottles .
Each crate contains 18 small bottles , 5 large bottles.
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Small bottles 3 per second =
In 60 seconds: 3*60 = 180
Per Box: 180/10 = 18

Large bottles 5 per 6 seconds
In 60 seconds: 5*10 = 50
Per Box: 50/10 = 5

Hence, Small Bottles per crate: 18
Large Bottles per crate: 5
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R1 3 per sec = 180 per minute
R2 5 per 6 sec = 50 per minute
Both to be packed at exactly 10 shipping crates means divide each by 10 so you get 18 for the small and 5 for the large
ANS CB
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This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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Small bottles at a constant rate of 3 per second -> R_S = 3 bottles/1sec
->R_S = (3 bottles/1sec) *60 = 180 bottles/1 min
Large bottles at a constant rate of 5 every 6 seconds -> R_L = 5 bottles/6sec
->R_S = (5 bottles/6sec) *10 = 50 bottles/1 min

Since the machine is designed to fill two types of bottles—small and large—at the same time, we have :

Small bottles = 50
Large bottles = 180
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Correct Answer: 18 Small Bottles and 5 Large Bottles
Here in 1 minute total bottles filled are
Small Bottles- 60 seconds*3 bottles per second= 180 total bottles
Large Bottles- 10 seconds*5 bottles per 6 seconds= 50 bottles
Here we divide total bottles with 10 to find per shipping crate bottles
So we get 18 for Small bottles and 5 Large bottles per crate.
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Rate of filling of small bottle = 3 bottle /sec
Therefore bottle filled in 1 minute = 180
No. of small bottles per crate = 18 ........ (select for column 1)

Rate of filling large bottles = 5 bottle/sec
Therefore bottles filled in 1 minute = 50
No. of small bottles per crate = 5 ........ (select for column 2)
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We know that the question is asking for number of small and large bottles in 1 crate, and that filling the bottles in 1 min is enough for 10 crates. Therefore

Small bottles: 3 bottles/sec x 60 secs / 10 crates = 18 bottles
Large bottles: 5/6 bottles/sec x 60 secs / 10 crates = 5 bottles

Mark 18 and 5 for small and large bottles.
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We can first determine the total amount of small and large bottles that got filled in the one minute of continuous operations to be 180 small bottles (3 bottles/sec * 60 sec) and 50 large bottles (5 bottles/ 6 seconds * 60 seconds). Because we know the number of shipping crates as well as that each crate contains the same number of small and large bottles we can determine the number of small and large bottles per crate to be 18 and 5, respectively.

Regards,
Lucas
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This question was provided by GMAT Club
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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
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It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds. So in 60s (or 1 min) we have 180 small bottles and 50 large bottles, which will be contained in 10 crates. Each create would have 18 small and 5 big bottles.
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Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

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A water bottling machine is designed to fill two types of bottles—small and large—at the same time.

It fills small bottles at a constant rate of 3 per second and large bottles at a constant rate of 5 every 6 seconds.

In one minute of continuous operation at these rates, the machine fills small and large bottles that are packed into exactly 10 shipping crates, with each crate containing the same number of small bottles and the same number of large bottles.

Select for Small Bottles and Large Bottles the number of small and large bottles, respectively, in each shipping crate. Make only two selections, one in each column.
After reading the question twice, we want to make the rates the same, so every 6 seconds we get 18 small bottles and 5 large bottles. The machines work for 1 minute or 60 seconds, so that would be 10 sets. We are dividing them up amongst 10 crates so each crate gets one set, so 18 small and 5 large.
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