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Quote:
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


Given At + Bt -3 = Ct.

We have to answer if Ct < At && Ct<Bt

(1) All three < 6. Here the cases can be At = 1, Bt = 5, Ct=3 and also At=1.5, Bt=2.5 and Ct=1, hence this doesn't answer.

(2) At < Bt. We can take the same cases as in (1) and see that this doesn't answer as well.

Taking both together, we can't answer since Ct can either win, or not win based on these combos. Hence, the correct answer is (E)
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So if we assume speeds for three of them based on 1st condition the only possiblities are 6km/hr, 5km/hr and 3 or 2km/hr. The only possible combination we get to determine that Carl did win can be found because there are only 3 possiblities and every one is deterministic. But based on 2nd statemenrt we do not get any relation between speed or time taken of Carl which is what we need to find. So 1st statement is sufficient but 2nd is not.
Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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Rewriting the question: Let A,B,C be the time Anton, Beatrice, and Carl took to complete the race, respectively. A+B = 3+C. Is C< A,B?
(1) None of the three ran faster than 6 kilometers per hour = A, B, C all took more than 5 hours. So if both Anton and Beatrice took 5 hours 1 min each, then Carl took 7 hours and 2 mins. Carl clearly took more time than both. Even if we took larger numbers for both Anton and Beatrice, Carl will always take longer than them. Sufficient.
(2) Anton finished before Beatrice. A<B. But this doesn't give us any way to know if C< A, B. Not sufficient.
Option A.
Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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Statement 1 says that no one ran faster than 6 km/h, which means each person took at least 5 hours to finish the 30 km race. So A, B, and C are all greater than or equal to 5.

Now plugging into the equation A + B = C + 3, the left side is the sum of two values each ≥ 5, so A + B ≥ 10.
This means C + 3 ≥ 10 → C ≥ 7

So Carl’s time is at least 7 hours, while Anton and Beatrice each took at least 5. Therefore, Carl’s time is definitely not less than both A and B — meaning he did not win. That answers the question with certainty.

Statement 1 is sufficient.
Statement 2 only says Anton finished before Beatrice, which doesn’t help compare either to Carl. So it's not sufficient.

Final answer: A.
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Quote:
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.



Given At + Bt -3 = Ct.

We have to answer if Ct < At && Ct<Bt

(1) All three < 6. Here the cases can be At = 1, Bt = 5, Ct=3 and also At=1.5, Bt=2.5 and Ct=1, hence this doesn't answer.

(2) At < Bt. We can take the same cases as in (1) and see that this doesn't answer as well.

Taking both together, we can't answer since Ct can either win, or not win based on these combos. Hence, the correct answer is (E)
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Assuming A,B,C are the constant rates of the three people Anton, Beatrice, and Carl.

We are given 30/A + 30/B = 3 + 30/C

We are to answer if C is greater than A and B

Statement 1 - Maximum speed is 6 km/h

Assuming A and B run at the maximum speed, we get C as

30/6 + 30/6 = 3 + 30/C
C = 30 / 7 = 4.xx

C is lower than A and B

On the other hand, if A and B run at minimum speeds of say 1 km/h, then C is

30/1 + 30/1 = 3+ 30/C

We can deduce that C is less than 1 km/h

Since C is lower than A and B on both extremes, C did not win the race.

Statement 1 is sufficient.

Statement 2 - We do not know if Carl finished before Anton. Therefore, this statement is not sufficient.

Therefore, Option A
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Assume time taken By Carl is x hours and time taken by Anton and Beatrice y.

Given that y - x = 3

Statement (1): None of the three ran faster than 6 km/h. This means 5 hours is the least time someone can take

Lets try some values to make Carl win and lose:

1. Lets Y = 10(5+5), then 10 - x = 3, and x = 7, Hence carl Lost.
2. Lets Y = 1000(500+500), then 1000 - x = 3, and x = 997, Carl also Lost here.
Hence No matter what value of Y we choose Carl will always lose. Hence Statement 1 is sufficient.

Statement (2): Anton finished before Beatrice

In this situation there is no minimum hour limit so any value of x and why satisfy y - x = 3 are possible values, Carl can win in situations like

(1.6 + 1.5) + x = 3; x = 0.1

And there are multiple Situations in which Carl lost in first statement, so we are not getting certain win or lose situations for Car Hence it is insufficient.

(A) Statement (1) alone is sufficient, but statement (2) alone is not sufficient.
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A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked.

Let rate (speed) of Anton, Beatrice, and Carl be a, b & c respectively.
We know that time taken by Anton + time taken by Beatrice = time taken by Carl + 3
since time = distance / speed
30 / a + 30 / b = (30 / c) + 3 ----- (1)

1st statement : None of the three ran faster than 6 kilometers per hour.
hence 30 / a , 30 / b & (30 / c) will always be greater than 5.
so from (1), (30 / c) + 3 will always be greater than 10
30 / c > 7
c < 30 / 7 == c < 4.3
Hence, the rate of Carl will always be less than Anton & Beatrice, making his time taken always more. Indicating that he did not win the race. Hence, sufficient.

2nd approach : time taken by Anton + time taken by Beatrice = time taken by Carl + 3
Let's take some numbers >= 5 for example since their times will always be more than 5
Case 1) 9 + 5 = time taken by Carl + 3
time taken by Carl = 11
Case 2) 5 + 5 = time taken by Carl + 3
time taken by Carl = 7

Hence, Carl's time will always be greater.

2nd statement : Anton finished before Beatrice.
Hence, in terms of time
30 / a < 30 / b
from 30 / a + 30 / b = (30 / c) + 3
(30 / c) + 3 > 2 (30 / b)
solving for c,
c = 10 * b/(20 - b)
which will always be greater than b except when b <= 1
Since we do not have any information about this possibility, we cannot say that Carl wins or not. Hence, not sufficient.
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\(T_a\) + \(T_b\) = \(T_c\) +3

Statement 1 says none of them ran faster than 6km/hr,
which means \(T_a\) , \(T_b\) , \(T_c\) \(\geq{5}\)

If we take min value for \(T_a\) and \(T_b\) i.e., 5, we get
5+5 = \(T_c\) +3
\(T_c\) = 7

If we keep either one of \(T_a\) or \(T_b\) minimum and keep on increasing the other one, \(T_c\) will also increase.
\(T_c \)can be less than either of them but cannot become the least.
So, Carl can never win the race.
Thus, Statement 1 is sufficient.

Statement 2 says \(T_a < T_b\)

Lets assume \(T_a\) = 0.6 and \(T_b\) = 2.5
\(T_c\) will be 0.1
In this case \(T_c\) is least so Carl wins.

Now, lets assume \(T_a\) = 5 and \(T_b\) = 6
\(T_c\) will be 8
In this case \(T_c\) is not least so Carl doesnt win.
Therefore Statement 2 is insufficient.


Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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A I think, I tried putting in values 6 km/hr is fastest speed, so before 4, no values works, as you will get values less than 5, CHECKING IN TIME FOR EACH, they come out to be always less than Carl's time, so Carl cannot be the 1st. Sufficient
Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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Option A is the correct answer

The question tells was that the distance of the race is 30 km and the combined time that Anton & Beatrice took was exactly 3 more hours longer than the time Carl took to find the race. And then the it asks us whether Carl win the race or not.

The 1st statement tells us that no one ran faster than 6 km per hour. So from here we can take that the fastest time in which Carl could complete the race is Carl ≥ 5 hr. similarly for combined time take by both Anton & Beatrice ≥ 8. And this information is actually enough to answer the question because from here we can get the combinations for Anton & Beatrice for example: if Carl took 5 hr. then Anton & Beatrice took 8 hr. combined so the pairs could be (1,7), (2,6), (3,5),...(7,1). With this information we can tell that Carl did not win the race. So this is sufficient.

Now lets look at 2nd Statement which only tells us that Anton finished before Beatrice. From here I can get that Carl finished the race in 1 hr. and Anton & Beatrice took 4 hr. which could be (0.5,3.5), (1,3), (1.5,2.5) and so on. So this statement does not gives us the confirmed answer so not sufficient.




Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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Given:
Distance = 30km
\(T_a+T_b=3+T_c\)
To find: \(T_c< T_a\) and \(T_c <T_b\)

Statement 1: No one runs faster than 6 km/h
So, \(T_a\),\(T_b \),\(T_c\) \(\geq{5}\)
Even if we consider the case where \(T_a \) and \(T_b \) have the lowest possible values of 5 hours, \(T_c \)=7 hours
In all possible cases, Carl will never be the one with the fastest time. So, it can be concluded that Carl will not win.
So, Statement 1 alone is sufficient.

Statement 2: \(T_a<T_b\)
Consider cases:
Case 1: \(T_a=2.8\), \(T_b=2.9\), then, \(T_c = 2.7\)
So, Carl wins.

Case 2: \(T_a=7\), \(T_b=9\), then, \(T_c = 13\)
So, Carl loses.

Statement 2 is not enough.

Answer - A.
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From the question stem, we know that,

\(time_A + time_B = 3 + time_C\) or

\(\frac{30}{speed_A} + \frac{30}{speed_B} = 3 + \frac{30}{speed_C}\)

Statement 1: None of the three ran faster than 6 kilometers per hour.

\(\frac{30 km}{6 km/h} = 5 hours.\) So, all of the participants took atleast \(>= 5 hours.\).

Thus, if time taken by A and B is 5 each, 5 + 5 = 3 + time taken by Carl. Clearly, Carl's time needs to be greater than 7. So, Carl did not win the race as he took more time. [color=#17b529]Sufficient.[/color]


Statement 2: Anton finished before Beatrice.

This doesn't give us any information about the relation between A, B and C.[color=#c10300] Insufficient.[/color]


Answer is (A).

Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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A should be the answer.

Statement 1 says that the minimum time taken = 5 hrs
Hence the minimum time taken by Carl is = tc + 3 = Total (min. of A and B)
the minimum time taken by Carl = tc = 10 - 3 = 7 hours
In that case also Carl loses as A and B win.
The answer is No and A is sufficient.

Statement B gives two answers.
tC+3 = tA + tB
If tA = 1 & tB=2.5 then tC = 0.5, C wins
If tA = 1 & tB = 4 Then tC = 2, C loses

Not sufficient.
Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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Anton’s time + Beatrice’s time = Carl’s time + 3 hours →
So Carl was faster on average.

Statement (1):
None ran faster than 6 km/h
So Carl’s max speed = 6 km/h.
If Carl ran 30 km at 6 km/h, his time = 5 hrs.

Then Anton + Beatrice = 8 hrs combined → both must have taken more than 5 hrs each → Carl was fastest → Sufficient.

Statement (2):
Anton finished before Beatrice → says nothing about Carl → Not sufficient.

Answer: (A) Statement (1) alone is sufficient, but statement (2) alone is not.
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Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.

Let time taken be Ta, Tb and Tc.
Given that Ta + Tb = Tc +3.

Since question is if C won the race, we can assume that for C to win the race Tc ≤ Ta and Tc ≤ Tb.

ie; Tc ≤ Ta and Tc ≤ Tb => 2*Tc ≤ Ta + Tb

2Tc ≤ Ta + Tb => 2Tc ≤ Tc + 3 => Tc ≤ 3.

Now, going to each of the given statements:

(1) None of the three ran faster than 6 kilometers per hour.

This means the fastest time for anyone is less than 30/6 = 5hours => Tfastest ≤ 5
Since we know Tc ≤ 3, it is impossible with the provided condition Tfastest ≤ 5. So, we can determine sufficiently that C did not win the race. Options AD are valid.


(2) Anton finished before Beatrice.

ie; Ta < Tb. But this alone is not enough information to say if C won the race. Option D eliminated.

Answer: A
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Bunuel
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?

(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.


 


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TA = 30/SA, TB =30/SB, TC=30/SC
TA+TB= TC+3 or 1/SA+1/SB-1/SC=1/10

AD -> can be interpreted as all of them takes at least 5 hours to complete the race -> TA+TB= TC+3 - > 5+5 = 7+ 3 -> 9 + 5 = 11 +3 -> C always looses sufficient.
BCE -> Not sufficient hence A is the answer
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