Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
02 Jul 2025, 02:34
Kudos
Bookmarks
Anton, Beatrice, and Carl, each running at a constant rate, competed in a 30-kilometer race. The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer than the time Carl took. Did Carl win the race?
(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.
This is a Yes or No question.
Did Carl win the race or is the time taken by Carl in the race less than the time taken by Anton or Beatrice
Meanwhile:
The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer
Let Time taken by each of the runners be denoted thus:
Ta= Time taken by Anton
Tb=Time taken by Beatrice
Tc=Time taken by Carl
Ta + Tb=Tc + 3
Statement 1
None of the three ran faster than 6 kilometers per hour
Thus the minimum time taken by Anton or Beatrice is: (30/6)=5
So Ta >= 5, Tb >= 5
Therefore: Ta + Tb >= 10
Tc >= 10 - 3
Tc >= 7
Hence carl ran slower than the other 2 runners
Statement 1 is sufficient
Statement 2
Anton finished before Beatrice.
It means that Ta > Tb
It does not any information in relation to the time Carl took to run the race. Therfore statement 2 is insufficient
(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.
This is a Yes or No question.
Did Carl win the race or is the time taken by Carl in the race less than the time taken by Anton or Beatrice
Meanwhile:
The combined time Anton and Beatrice took to finish the race was exactly 3 hours longer
Let Time taken by each of the runners be denoted thus:
Ta= Time taken by Anton
Tb=Time taken by Beatrice
Tc=Time taken by Carl
Ta + Tb=Tc + 3
Statement 1
None of the three ran faster than 6 kilometers per hour
Thus the minimum time taken by Anton or Beatrice is: (30/6)=5
So Ta >= 5, Tb >= 5
Therefore: Ta + Tb >= 10
Tc >= 10 - 3
Tc >= 7
Hence carl ran slower than the other 2 runners
Statement 1 is sufficient
Statement 2
Anton finished before Beatrice.
It means that Ta > Tb
It does not any information in relation to the time Carl took to run the race. Therfore statement 2 is insufficient
02 Jul 2025, 02:42
Kudos
Bookmarks
My guess is D.
(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.
Carl would finish earlier than both of them in either situation.
(1) None of the three ran faster than 6 kilometers per hour.
(2) Anton finished before Beatrice.
Carl would finish earlier than both of them in either situation.
02 Jul 2025, 02:42
Kudos
Bookmarks
Let time taken by Anton, Beatrice, & Carl to finish the race be ta, tb, & tc
Given, d = 30 km; ta + tb = tc + 3
Considering Statement 1,
The maximum speed is mentioned as 6km/hr for all 3 of the contestants.
Let their speeds be va, vb, & vc are speeds of Anton, Beatrice, & Carl respectively. Then,
ta = 30/va; tb = 30/vb; tc = 30/vc
Assuming maximum speed for all we get,
ta >= tb >= tc >= 5 hrs.
This is the lowest time possible for all three of the candidates.
But this statement alone does not provide a conclusion on whether Carl wins the race ∴ Not Sufficient.
Considering Statement 2,
This mentions that ta < tb or va > vb but this does not provide any further insights - Not sufficient
Taking Statements 1 & 2 together,
We have,
ta >= tb >= tc >= 5 hrs. & ta < tb
ta + tb = tc + 3
Substituting values for ta, tb, & tc,
tc cannot be 5 as then tb + tc should be equal to 5 + 3 = 8, which is not possible as 5 is the minimum time taken among all 3 candidates.
∴ as per the conditions, ta = 5, tb = 6 ⟹ tc = 8
ta = 5, tb = 7 ⟹ tc = 9
ta = 6, tb = 7 ⟹ tc = 10 & this pattern continues with tc always being greater than the values of ta & tb.
In none of the cases can Carl be seen to have the lowest time taken among the 3 to complete the race, which is a requirement to win the game. So the answer is no, Carl does not win the game, in any of the cases.
∴Both the statements taken together are sufficient.
Correct option is Option C
Given, d = 30 km; ta + tb = tc + 3
Considering Statement 1,
The maximum speed is mentioned as 6km/hr for all 3 of the contestants.
Let their speeds be va, vb, & vc are speeds of Anton, Beatrice, & Carl respectively. Then,
ta = 30/va; tb = 30/vb; tc = 30/vc
Assuming maximum speed for all we get,
ta >= tb >= tc >= 5 hrs.
This is the lowest time possible for all three of the candidates.
But this statement alone does not provide a conclusion on whether Carl wins the race ∴ Not Sufficient.
Considering Statement 2,
This mentions that ta < tb or va > vb but this does not provide any further insights - Not sufficient
Taking Statements 1 & 2 together,
We have,
ta >= tb >= tc >= 5 hrs. & ta < tb
ta + tb = tc + 3
Substituting values for ta, tb, & tc,
tc cannot be 5 as then tb + tc should be equal to 5 + 3 = 8, which is not possible as 5 is the minimum time taken among all 3 candidates.
∴ as per the conditions, ta = 5, tb = 6 ⟹ tc = 8
ta = 5, tb = 7 ⟹ tc = 9
ta = 6, tb = 7 ⟹ tc = 10 & this pattern continues with tc always being greater than the values of ta & tb.
In none of the cases can Carl be seen to have the lowest time taken among the 3 to complete the race, which is a requirement to win the game. So the answer is no, Carl does not win the game, in any of the cases.
∴Both the statements taken together are sufficient.
Correct option is Option C
