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01 Jul 2025, 10:17
Kudos
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Small bottles = 18, Large bottles = 5
Given that Rate for Small bottles = 3 per sec
Rate for Large bottles = 5 per 6 sec
Hence total Small bottles in 1 minute (60 seconds) is 3 * 60 = 180 and Large bottles = 5/6 * 60 = 50
By distributing these numbers in 10 bottles equally,
Small bottles = 180/10 = 18
Large bottles = 50/10 = 5
Given that Rate for Small bottles = 3 per sec
Rate for Large bottles = 5 per 6 sec
Hence total Small bottles in 1 minute (60 seconds) is 3 * 60 = 180 and Large bottles = 5/6 * 60 = 50
By distributing these numbers in 10 bottles equally,
Small bottles = 180/10 = 18
Large bottles = 50/10 = 5
01 Jul 2025, 10:22
Kudos
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Let's say speed of A = a kmph, B = b kmph, C = c kmph.
Time taken by A = Ta
Time taken by B = Tb
Time taken by C = Tc.
Ta + Tb = Tc + 3.
Is Tc<(Ta,Tb)?
Statement 1:
(1) None of the three ran faster than 6 kilometers per hour.
It takes minimum 5 hours to run 30 Km if they ran at 6 Kmph speed. So,
Ta,Tb,Tc >5.
This means Sum of Ta and Tb > 10 That means Tb + 3 >1 That means surely Tb is greater than either Ta or Tb or both. For ex: Ta = 5.1, Tb =5.2, Tc = (5.1+5.2)-3 = 7.3. So carl didn't finish first.
Another scenario, Ta = 10.2, Tb = 20.2, still Tc = 17.4, again carl didn't finish first.
So statement (1) is sufficient.
Statement 2:
(2) Anton finished before Beatrice.
Ta<Tb. Scenario 1: Ta = 1.5, Tb = 1.6, Tc = 3.1 -3 = 0.1. C finished first. But take scenario Two from Above: Ta = 10.2. Tb = 20.2, here Tc = 17.4. C didn't finish first. Hence insufficient.
Ans (A).
Time taken by A = Ta
Time taken by B = Tb
Time taken by C = Tc.
Ta + Tb = Tc + 3.
Is Tc<(Ta,Tb)?
Statement 1:
(1) None of the three ran faster than 6 kilometers per hour.
It takes minimum 5 hours to run 30 Km if they ran at 6 Kmph speed. So,
Ta,Tb,Tc >5.
This means Sum of Ta and Tb > 10 That means Tb + 3 >1 That means surely Tb is greater than either Ta or Tb or both. For ex: Ta = 5.1, Tb =5.2, Tc = (5.1+5.2)-3 = 7.3. So carl didn't finish first.
Another scenario, Ta = 10.2, Tb = 20.2, still Tc = 17.4, again carl didn't finish first.
So statement (1) is sufficient.
Statement 2:
(2) Anton finished before Beatrice.
Ta<Tb. Scenario 1: Ta = 1.5, Tb = 1.6, Tc = 3.1 -3 = 0.1. C finished first. But take scenario Two from Above: Ta = 10.2. Tb = 20.2, here Tc = 17.4. C didn't finish first. Hence insufficient.
Ans (A).
Bunuel
01 Jul 2025, 10:31
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Bunuel
Let time taken to complete the race by Anton be A, Beatrice be B and Carl be C.
given: 30/A + 30/B = 30/C +3
asked: is C<A and C<B?
Statment 1:
30/A, 30/B, 30/C < 6 km/hr OR A,B,C > 5 hrs. So not sufficient
Hence B,C,E
Statment 2:
A< B . Not sufficient
Combine 1 and 2:
A,B,C > 5 hrs and A<B. So no information about C being less than A and B. Hence Option E.
