Last visit was: 19 Nov 2025, 05:20 It is currently 19 Nov 2025, 05:20
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Mardee
Joined: 22 Nov 2022
Last visit: 16 Oct 2025
Posts: 127
Own Kudos:
110
 [1]
Given Kudos: 17
Products:
Posts: 127
Kudos: 110
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
SumnerSCB
Joined: 27 Apr 2025
Last visit: 08 Sep 2025
Posts: 36
Own Kudos:
Posts: 36
Kudos: 22
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
jkkamau
Joined: 25 May 2020
Last visit: 19 Nov 2025
Posts: 132
Own Kudos:
107
 [1]
Given Kudos: 122
Location: Kenya
Schools: Haas '25
GMAT 1: 730 Q50 V46
GPA: 3.5
Products:
Schools: Haas '25
GMAT 1: 730 Q50 V46
Posts: 132
Kudos: 107
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
RedYellow
Joined: 28 Jun 2025
Last visit: 09 Nov 2025
Posts: 80
Own Kudos:
74
 [1]
Posts: 80
Kudos: 74
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
timeBob=4*timeAlice
80/speedBob=4*80/speedAlice
4*speedBob=speedAlice
4(3-s)=2+s
12-4s=2+s
s=2

speedBob=1 -> finalTimeBob=80
speedAlice=4 -> finalTimeAlice=20

The easiest way of calculate the meet time is to add the speeds: 1+4=5 and dividing 80 by this sum: 80/5=16

Alice walks at 2 steps per second relative to the scalator, so she walks 2*20=40 steps.

Correct answers are t=16 and n=40
User avatar
Manu1995
Joined: 30 Aug 2021
Last visit: 11 Nov 2025
Posts: 81
Own Kudos:
55
 [1]
Given Kudos: 18
Posts: 81
Kudos: 55
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given:
Escalator length = 80 steps

Escalator speed = s steps/sec (upward)

Alice walks upward at 2 steps/sec relative to the escalator
⇒ Her net speed = 2+s

Bob walks downward at 3 steps/sec relative to the escalator
⇒ His net speed = 3−s

Bob takes 4 times as long to reach the bottom as Alice takes to reach the top

Let:

t = time in seconds after which Alice and Bob meet

T = time Alice takes to reach the top ==> T = 80/(2+s)

Then Bob takes 4T = 320/(2+s) to go from top to bottom
==> his speed = 3−s

So, Bob also travels 80 steps in 320/(2+s) seconds

==> 80 = (3-s)* 320/(2+s)

On solving for s:
s=2

Now Alice speed ==> 2+s = 4
Time to reach to the top = 80/4= 20sec
So T= 20
Bob takes 4× longer = 80 sec, going down at 3−2 =1 step/sec

Alice goes up at 4 steps/sec
Bob comes down at 1 step/sec
Relative speed = 4+1=5 steps/sec
They meet when they’ve together covered 80 steps

Therefore,time when they meet = 80/5= t= 16sec
Alice walks at 2 steps/sec relative to escalator in 20 sec
==>2 × 20 = n= 40 steps
User avatar
Jarvis07
Joined: 06 Sep 2017
Last visit: 19 Nov 2025
Posts: 295
Own Kudos:
236
 [1]
Given Kudos: 160
GMAT 1: 750 Q50 V41
GMAT 1: 750 Q50 V41
Posts: 295
Kudos: 236
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Because Bob’s ride takes four times as long as Alice’s, the escalator must be helping both by 2 steps per second. That means Alice actually goes up 4 steps each second and Bob comes down 1 step each second. Starting 80 steps apart, they close the gap at 5 steps per second, so they meet after 16 seconds. Alice reaches the top in 20 seconds and, walking 2 steps every second on the moving escalator, she physically climbs 40 steps.

Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 



Alice and Bob are on an escalator with 80 steps from bottom to top. The escalator moves upward at a constant rate of s steps per second.

Alice starts from the bottom and walks upward at a constant rate of 2 steps per second relative to the escalator. Bob starts from the top and walks downward at a constant rate of 3 steps per second relative to the escalator.

Bob takes four times as long to reach the bottom as Alice takes to reach the top.

Select for t the time in seconds after which Alice and Bob meet, and select for n the number of steps Alice would have walked on the escalator by the time she reaches the top. Make only two selections, one in each column.
User avatar
Lemniscate
Joined: 28 Jun 2025
Last visit: 09 Nov 2025
Posts: 80
Own Kudos:
72
 [1]
Posts: 80
Kudos: 72
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Speeds:
SB=3-s
SA=s+2

Comparing times:
TB=4*TA
80/SB=4*80/SA
4SB=SA
4*(3-s)=s+2
12-4*s=s+2
5*s=10
s=2

Bob reaches the botton in 80/1=80 seconds
Alice reaches the top in 80/4=20 seconds

Aggregate speed B y A = 1+4 = 5
80/5 = 16 -> time they meet

steps of Alice = time Alice reaches the top * relative speed of Alice = 20*2=40

Answers are t=16 and n=40
avatar
ManifestDreamMBA
Joined: 17 Sep 2024
Last visit: 18 Nov 2025
Posts: 1,282
Own Kudos:
Given Kudos: 236
Products:
Posts: 1,282
Kudos: 785
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Speed in steps/secAliceBob
Relative Speed23
Effective Speed2+s3-s
Time takenx4x

They both covered the same distance, so
x(2+s)=4x(3-s)
2+s=12-4s
s=2

Effective speeds are 4 and 1step/sec for Alice and both
If they walk simultaneously their relative speed = 5
Time taken to meet = 80/5=16 secs

In 16secs, Alice covered = 16*4 = 64 steps

Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 



Alice and Bob are on an escalator with 80 steps from bottom to top. The escalator moves upward at a constant rate of s steps per second.

Alice starts from the bottom and walks upward at a constant rate of 2 steps per second relative to the escalator. Bob starts from the top and walks downward at a constant rate of 3 steps per second relative to the escalator.

Bob takes four times as long to reach the bottom as Alice takes to reach the top.

Select for t the time in seconds after which Alice and Bob meet, and select for n the number of steps Alice would have walked on the escalator by the time she reaches the top. Make only two selections, one in each column.
User avatar
sanya511
Joined: 25 Oct 2024
Last visit: 10 Nov 2025
Posts: 100
Own Kudos:
Given Kudos: 101
Location: India
Products:
Posts: 100
Kudos: 52
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Alice's speed = 2 + S
Bob's speed = 3-s
Bob takes four times as long to reach the bottom as Alice takes to reach the top.
4(80/(2+s)) = 80/(3+s)
s = 2, Alice's speed = 4, Bob's speed = 1
t= 80/(4+1) = 16 seconds
to calculate n, time taken by Alice to reach the top= 80/4 = 20 seconds
20 * Alice's relative speed = 20 *2 = 40 steps

t = 16
n = 20
Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 



Alice and Bob are on an escalator with 80 steps from bottom to top. The escalator moves upward at a constant rate of s steps per second.

Alice starts from the bottom and walks upward at a constant rate of 2 steps per second relative to the escalator. Bob starts from the top and walks downward at a constant rate of 3 steps per second relative to the escalator.

Bob takes four times as long to reach the bottom as Alice takes to reach the top.

Select for t the time in seconds after which Alice and Bob meet, and select for n the number of steps Alice would have walked on the escalator by the time she reaches the top. Make only two selections, one in each column.
User avatar
UfuomaOh
Joined: 14 Sep 2023
Last visit: 17 Nov 2025
Posts: 83
Own Kudos:
50
 [1]
Given Kudos: 14
Products:
Posts: 83
Kudos: 50
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let Ta= time alice takes to reach the top
Tb= time bob takes to reach the bottom

Alice total speed = 2+s

Bobs total speed as he is moving against the escalator's constant speed=3-s

Bob takes four times as long to reach the bottom as Alice takes to reach the top.

Hence Tb=4Ta

Meanwhile Ta= (80/2+s)

so Tb= 4*(80/2+s)

Solve for s using the expression Tb=4Ta

80/(3-s) = 4*(80/2+s)

400s=800

s = 2

Ta= 20 seconds
Tb=80 seconds

The number of steps Alice would have walked on the escalator by the time she reaches the top.

Alice walks 2 steps per second and takes 20 seconds to complete the entire step in the escalator. Hence the total number of steps she would have worked to reach the top is

2 X 20= 40 steps.

n= 40

Select for t the time in seconds after which Alice and Bob meet

Alice net speed is 4

so she has climbed 4t steps from the bottom

Bob's net speed is 1

so he has descended 1 x t steps = t steps from the top, meaning that he is at 80-t steps from the bottom

so they meet where

4t=80 - t

t= 16
User avatar
harishg
Joined: 18 Dec 2018
Last visit: 19 Nov 2025
Posts: 85
Own Kudos:
100
 [1]
Given Kudos: 27
Products:
Posts: 85
Kudos: 100
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Let alice and bob be A and B respectively and s be speed of escalator. As per the statements provided, we can deduce that the speed of A is 2+s and B is 3-s

We are given that

4* 80/(2+s) = 80 / (3-s)

Solving for s, we get s = 2

Therefore Speed of A = 4 and B = 1

Time taken for A and B to meet => 80/(4+1) = 16 seconds = t

Similarly, the number of steps Alice would have walked on the escalator by the time she reaches the top

time taken to reach the top by A => 80/4 = 20

In 20 seconds, A would have walked 20*2 = 40 steps.

Therefore, t = 16 and n = 40
User avatar
Aishna1034
Joined: 21 Feb 2023
Last visit: 19 Nov 2025
Posts: 219
Own Kudos:
Given Kudos: 150
Products:
Posts: 219
Kudos: 64
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The time for meeting has to be calculated with s=D/T formula. speeds for Alice and Bob will be s+2, and 3-s respectively, it will come out to be 16. And total steps alice would have walked will be 80, as thats the total steps required to reach at the Top
Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 



Alice and Bob are on an escalator with 80 steps from bottom to top. The escalator moves upward at a constant rate of s steps per second.

Alice starts from the bottom and walks upward at a constant rate of 2 steps per second relative to the escalator. Bob starts from the top and walks downward at a constant rate of 3 steps per second relative to the escalator.

Bob takes four times as long to reach the bottom as Alice takes to reach the top.

Select for t the time in seconds after which Alice and Bob meet, and select for n the number of steps Alice would have walked on the escalator by the time she reaches the top. Make only two selections, one in each column.
User avatar
Aarushi100
Joined: 17 Jul 2024
Last visit: 18 Nov 2025
Posts: 56
Own Kudos:
Given Kudos: 88
Products:
Posts: 56
Kudos: 44
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
 


This question was provided by GMAT Club
for the GMAT Club Olympics Competition

Win over $30,000 in prizes such as Courses, Tests, Private Tutoring, and more

 



Alice and Bob are on an escalator with 80 steps from bottom to top. The escalator moves upward at a constant rate of s steps per second.

Alice starts from the bottom and walks upward at a constant rate of 2 steps per second relative to the escalator. Bob starts from the top and walks downward at a constant rate of 3 steps per second relative to the escalator.

Bob takes four times as long to reach the bottom as Alice takes to reach the top.

Select for t the time in seconds after which Alice and Bob meet, and select for n the number of steps Alice would have walked on the escalator by the time she reaches the top. Make only two selections, one in each column.

Total steps: 80 steps

Speed of escalator: s steps/sec.
For Alice:
Bottom to Top:
Rate: 2 steps/sec
Total rate: 2+s steps/sec

For Bob:
Top to Bottom:
Rate: 3 steps/sec
Total Rate: 3-s steps/sec

Bob is against the escalator and takes 4 times are long are Alice.
2+s= 4(3-s)
=> s=2 steps/sec

Alice takes 4 steps/sec and Bob takes 1 step/sec.

Since, Alice is moving from Bottom to Top,
After 16 seconds: She will cover 64 steps whereas Bob will cover 16 steps.
Hence, they'll meet after 16 seconds.

t=16 seconds

Number of steps Alice takes till she reaches the top: 80/4= 20steps.

ANSWER:
t=16
n=20
   1   2   3   4   5 
Moderators:
Math Expert
105385 posts
496 posts