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10 Jul 2025, 06:24
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Two participants, Leo and Marco, competed for the same amount of time
During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs.
We want to know,
Marco’s average rate, in hot dogs per hour
From the given info, lets say
Total time = t hrs
Leo's rate of eating hot dogs = 36/t
Marco's rate of eating hot dogs = 30/t
Given the statements,
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
=> 30/t = 36/t - 6
=> t = 1
=> Marco's rate of eating hot dogs = 30/t = 30/1 = 30 hotdogs/hr
Statement (1) is sufficient
(2) In the first 20 minutes, Leo ate 12 hot dogs.
This tells us something about Leo's rate in the first 20 minutes, BUT there are more things in the dark i.e, we don't know if Leo kept eating at that rate, it tells us nothing about Marco and we dont know the total time they ate together for
So it is not sufficient
Statement (2) is not sufficient
A. Statement (1) alone is sufficient, but (2) alone is not
During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs.
We want to know,
Marco’s average rate, in hot dogs per hour
From the given info, lets say
Total time = t hrs
Leo's rate of eating hot dogs = 36/t
Marco's rate of eating hot dogs = 30/t
Given the statements,
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
=> 30/t = 36/t - 6
=> t = 1
=> Marco's rate of eating hot dogs = 30/t = 30/1 = 30 hotdogs/hr
Statement (1) is sufficient
(2) In the first 20 minutes, Leo ate 12 hot dogs.
This tells us something about Leo's rate in the first 20 minutes, BUT there are more things in the dark i.e, we don't know if Leo kept eating at that rate, it tells us nothing about Marco and we dont know the total time they ate together for
So it is not sufficient
Statement (2) is not sufficient
A. Statement (1) alone is sufficient, but (2) alone is not
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10 Jul 2025, 06:39
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Let the amount of time spent in competition = t
Leo’s rate = 36/t
Marco’s rate = 30/t
Q: 30/t?
St1: 30/t = (36/t) – 6
Solve to get t =1
St2: We get to know that Leo’s rate for the 1[sup]st[/sup] 20 min was 0.6H/min but we can’t assume the rate to be same beyond 20 mins. It could be more or less than 0.6H. Insufficient.
Option A
Leo’s rate = 36/t
Marco’s rate = 30/t
Q: 30/t?
St1: 30/t = (36/t) – 6
Solve to get t =1
St2: We get to know that Leo’s rate for the 1[sup]st[/sup] 20 min was 0.6H/min but we can’t assume the rate to be same beyond 20 mins. It could be more or less than 0.6H. Insufficient.
Option A
Bunuel
10 Jul 2025, 07:17
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Average rate = total hot dogs/ total time
(1)30/t = 36/t - 6
We can find a unique value of t this way. Sufficient.
(2) In the first 20 minutes leo ate 12 hot dogs. This might prompt us to think that leo's constant speed was 12/20 mins or 36 hot dogs per hour, Hence think that the time was 1 hour, but it was not given to us that they had a constant hot dog eating speed.
Not sufficient.
Answer: Option A.
(1)30/t = 36/t - 6
We can find a unique value of t this way. Sufficient.
(2) In the first 20 minutes leo ate 12 hot dogs. This might prompt us to think that leo's constant speed was 12/20 mins or 36 hot dogs per hour, Hence think that the time was 1 hour, but it was not given to us that they had a constant hot dog eating speed.
Not sufficient.
Answer: Option A.
Bunuel
