Given:Leo ate 36 hotdogs and Marco ate 30 hot dogs in same time.
Question: Marco's avg Rate/hour?
Statement 1: Marco’s average rate was 6 hot dogs per hour less than Leo’sSo we know together they ate 66 hotdogs in a certain time
Also Marco's Avg rate/hour=Leo's Rate/hour-6 hotdogs/hour
Their combined rate is (L+L-6)=2L-6
Total time taken=66/(2L-6)=66/2(L-3)=33/L-3
Now We know total time taken is 33/L-3
Also we know Leo's Rate i.e L and Hotdogs he ate i.e 36. So we can say
L=36/33/(L-3)
L=(L-3)*12/11
11L=12L-36
L=36
So, M=30
Yes we can say this st. is sufficient alone.Statement 2: In the first 20 minutes, Leo ate 12 hot dogs.In 20 mins Leo ate 12 hotdogs
in 60 min he will eat 12*3=36 hotdogs so we know he ate his 36 hot dogs in 1 hour
We know he and Marco took same amount of time.
Marco ate his 30 hot dogs in one hour
therefore, his rate/hour=30
This is also sufficientSo,
Answer D both are sufficient alone.Bunuel
In a hot dog eating contest, two participants, Leo and Marco, competed for the same amount of time. During that time, Leo ate 36 hot dogs, and Marco ate 30 hot dogs. What was Marco’s average rate, in hot dogs per hour, during that time?
(1) Marco’s average rate was 6 hot dogs per hour less than Leo’s.
(2) In the first 20 minutes, Leo ate 12 hot dogs.