First, let's make the denominator of the fraction the same for the ease of the calculation
LCM of 60, 15, 30, 10,20=60
T1=11/60, T2= 8/60, T3= 14/60, T4=18/60, T5=9/60
So we have to find the sum of books on lower shelf that include T3 or not and fraction of lower shelf should be greater than either 1/2 or 30/60
Now let's evaluate statement 1
If T2 and T4 are on the lower shelf, their combined fraction of pages is: (T2) + (T4) = 8/60+18/60=26/60
Which is less than 1/2 or 30/60
Now lets consider if T3 is the part Then T2+T4+T3=40/60 so we can say T3 is the part of lower shelf
Now let's consider if T3 is not the part and T1 and T5 is the part so T1+T5+T2+T4=40/60 which is also greater than 30/60 hence we can say T3 is not part which is disputing with the above one so, statement one is not enough
Now Let's evaluate Statement 2
If T1 and T5 are on the upper shelf, their combined fraction of pages is: Fraction(T1) + Fraction(T5) = 11/60+9/60=20/60
Since there are only two shelves and five books, the remaining books must be on the lower shelf.
The remaining books are T2, T3, and T4 = 8/60+14/60+18/60=40/60 which is greater than 1/2 or 30/60
Hence Statement 2 is sufficient to answer so answer will be B
Bunuel

Five mathematics textbooks, T1, T2, T3, T4, and T5, have been placed on two shelves, neither of which houses any other books. The table displays the number of pages in each book as a fraction of the total number of pages in the five books together. If more than 1/2 of the total pages that comprise the five books are found on the lower shelf, is T3 found on the lower shelf?
(1) T2 and T4 have been placed on the lower shelf.
(2) T1 and T5 have been placed on the upper shelf.
Attachment:
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