Kris88 wrote:
I understand the point of the article, but what would be the solution for " x^2 – 5x – 5 = 0" where it will be positive and negative?
tdotmba wrote:
Kris88 wrote:
I understand the point of the article, but what would be the solution for " x^2 – 5x – 5 = 0" where it will be positive and negative?
You would have to use the quadratic equation if you actually wanted to solve it.
Your two solutions of x would equal [(5+ √45) / 2] & [(5 - √45) / 2]
approx: (x - 5.854) (x + 0.854 )
You actually don't have to solve. Sum of roots = 5 and product is -ve. So definitely one of them is +ve and other one is -ve and +ve root is more than -ve root by 5.
And as quadratic equations are only defined for real numbers, we will be having only real number solution.
So statement 1 will not be sufficient.
So statement 2 will be required to solve the DS question. Answer will be C)