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Difficulty:
5%
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Question Stats:
81% (00:41) correct
19%
(01:18)
wrong
based on 468
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Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4
B. 8
C. 12
D. 13
E. 16
A. 4
B. 8
C. 12
D. 13
E. 16
02 Nov 2012, 12:56
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MariaF
ok... My brains don't work for today....
Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4
B. 8
C. 12
D. 13
E. 16
Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4
B. 8
C. 12
D. 13
E. 16
Maria,
I doubt if it is al-gebra.
It is a probability problem.
Grace, in the worst case may take out 8 red jellyes ► 4 green ► and the next will be the blue one.
So 13 - is the minimum number of jellybeans.
02 Nov 2012, 14:15
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MariaF
Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4
B. 8
C. 12
D. 13
E. 16
A. 4
B. 8
C. 12
D. 13
E. 16
The worst scenario is when she takes 8 red and 4 green, total of 12 jellybeans, and still doesn't have 3 distinct colors. But the next draw (13th) will surely be the third color jellybean (blue) as there is no other color jellybeans left in pocket.
Answer: D.
