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Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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Updated on: 02 Nov 2012, 14:10
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Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color? A. 4 B. 8 C. 12 D. 13 E. 16
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Originally posted by MariaF on 02 Nov 2012, 12:18.
Last edited by Bunuel on 02 Nov 2012, 14:10, edited 1 time in total.
Renamed the topic and edited the question.



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Re: One more easy question
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02 Nov 2012, 12:56
MariaF wrote: ok... My brains don't work for today.... Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4 B. 8 C. 12 D. 13 E. 16 Maria, I doubt if it is algebra. It is a probability problem. Grace, in the worst case may take out 8 red jellyes ► 4 green ► and the next will be the blue one. So 13  is the minimum number of jellybeans.



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Re: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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02 Nov 2012, 14:15
MariaF wrote: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4 B. 8 C. 12 D. 13 E. 16 The worst scenario is when she takes 8 red and 4 green, total of 12 jellybeans, and still doesn't have 3 distinct colors. But the next draw (13th) will surely be the third color jellybean (blue) as there is no other color jellybeans left in pocket. Answer: D.
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Re: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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01 Apr 2016, 14:21
The worst case arises when she takes 8 red and 4 green, and still doesn't have 3 distinct colors. So she draws (13th) next which will surely be the third color jellybean (blue) as no other colour jellybean is left in her pocket Answer  D



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Re: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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03 Apr 2016, 07:19
Bunuel wrote: MariaF wrote: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4 B. 8 C. 12 D. 13 E. 16 The worst scenario is when she takes 8 red and 4 green, total of 12 jellybeans, and still doesn't have 3 distinct colors. But the next draw (13th) will surely be the third color jellybean (blue) as there is no other color jellybeans left in pocket. Answer: D. Shouldn't it be 9 actually...in case she picks G and B, then on 9th trial she can get a R.



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Re: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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03 Apr 2016, 11:45
Avinashs87 wrote: Bunuel wrote: MariaF wrote: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4 B. 8 C. 12 D. 13 E. 16 The worst scenario is when she takes 8 red and 4 green, total of 12 jellybeans, and still doesn't have 3 distinct colors. But the next draw (13th) will surely be the third color jellybean (blue) as there is no other color jellybeans left in pocket. Answer: D. Shouldn't it be 9 actually...in case she picks G and B, then on 9th trial she can get a R. For such cases when we should ensure, guarantee some outcome we always consider the worst case scenario. For 9 picks it's possible that Grace picks 8 R's and 1 G. Check other Worst Case Scenario Questions from our Special Questions Directory to understand the concept better.
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Re: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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04 Aug 2019, 04:56
MariaF wrote: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
A. 4 B. 8 C. 12 D. 13 E. 16 13 (8+4+1) worst case




Re: Grace has 16 jellybeans in her pocket. She has 8 red ones, 4
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04 Aug 2019, 04:56






