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Typical GRE problem which the most important thing is just to follow the instructions: pick up a smart number and you can see also in the denominator of the answr choices which is 40 1/2 red so we have 20. we left with 20 picked uop NO red. 1/4 of the rest is 5. so 5 picjed up blue and 15 left. of the rest 1/5 picked up green so we have 3 students with green. therefore we have 12 whoc picked up NO red, green , or blue. The oever all fraction is 12/40=3/10. E should be the answer The question here https://gmatclub.com/forum/gre-quant-qu ... 28816.html should be posted as text and not image. would be easier......

The diagonal of the exagon is also the circumference of the circle and the arc LMN is 1/3 of the circle. 1/3*2 pi r and r is 5 and the circumference is 10 making the calculation you have a quantity A < of 10. B is the answer

carcass , has given the perfect way. In these questions take total as product of denominators so 2*4*5 or 40……Red:20,….Blue: (40-20)*1/4=5….G: (15-5)*1/5=3…people who did not like any of the three = 40-(20+5+3) = 12….fraction = 12/40=3/10

How did you calculate 120 degree in the hexagon problm for the LMN arc

ax^2+bx+C is a quadratic equation and gives a parabola. If a>0, it opens upwards and if a<0, then it opens downwards. Now Determinant which is b^2-4ac gives number of roots. If D is 0, it gives one real root. So look for a parabola that opens upwards and cuts x axis at one point ……B

@chetan2u what if b2-4ac>0 or b2-4ac<0 then

Total sum of angles = (n-2)*180, where n is number of sides, so (6-2)*180. Each angle is 4*180/6=120. If b^2-4ac 0, you will have two roots, that is parabola will cut x axis at two places.

I know this way i was asking the the angle of the arc

Ok, I didn’t read the word arc. The circle has 360 degree. There are 6 equidistant point here including L, Mand N. Thus LM and LN will be 360/6 or 60 each. LMN will be 60+60