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Henry purchased 3 items during a sale. He received a 20
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Updated on: 08 Mar 2015, 12:29
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66% (02:21) correct 34% (02:25) wrong based on 1080 sessions
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Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total amount of the 3 discounts greater than 15 percent of the sum of the regular prices of the 3 items? (1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20 (2) The regular price of the least expensive item was $15 Attachment:
Henry discount on items.GIF [ 14.71 KiB  Viewed 18228 times ]
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Originally posted by docabuzar on 27 Jan 2012, 05:24.
Last edited by Bunuel on 08 Mar 2015, 12:29, edited 3 times in total.
Added the OA




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Re: Henry purchased 3 items during a sale. He received a 20
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27 Jan 2012, 05:32
docabuzar wrote: Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total discount of these three items greater than 15 percent of the sum of the regular prices of the 3 items?
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20 (2) The regular price of the least expensive item was $15 Let the prices be a, b, and c, so that a > b > c. Basically the questions: is \(0.2a+0.1b+0.1c>0.15(a+b+c)\)? > is \(a>b+c\)? (1) The regular price of the most expensive item was $50 and the regular price of the next most expensive item was $20 > \(a=50\), \(b=20\), \(c\leq{20}\) (as the second most expensive item was $20 then the least expansive item, the third one, must be less than or equal to 20). So the question becomes: is \(50>20+c\) > is \(c<30\)? As we got that \(c\leq{20}\), hence the above is always true. Sufficient. (2) The regular price of the least expensive item was $15. Clearly insufficient. Answer: A.
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Re: Henry purchased 3 items during a sale. He received a 20
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27 Jan 2012, 06:21
Then it makes sense. Thanks



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Re: Henry purchased 3 items during a sale. He received a 20
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27 Jan 2012, 06:25
THe Q asks for the which of discounts will be greater 20%, 10%, 10% on A, B, C resp or 15% on (A+B+C). How can we say its same as 50> 20+C ? Now I m totally lost.



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Re: Henry purchased 3 items during a sale. He received a 20
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27 Jan 2012, 06:30



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Re: Henry purchased 3 items during a sale. He received a 20
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27 Jan 2012, 06:34
Thanks. Its clear now.
Just how do you know to keep A on one side & B & C on other? This simplied the Ans a lot.



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Re: Henry purchased 3 items during a sale. He received a 20
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27 Jan 2012, 06:38



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Re: Henry purchased 3 items during a sale. He received a 20
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22 Aug 2014, 19:30
Bunuel: if the first item is 50, the next 2 are 20. If I take 20% of 50 I get 10 and 10% of 20 I get 2. Total discount is 14 and total price is 90. 14/90>.15. What's am I doing wrong?



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Re: Henry purchased 3 items during a sale. He received a 20
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23 Aug 2014, 11:21
bankerboy30 wrote: Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total discount of these three items greater than 15 percent of the sum of the regular prices of the 3 items?
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20 (2) The regular price of the least expensive item was $15
Bunuel: if the first item is 50, the next 2 are 20. If I take 20% of 50 I get 10 and 10% of 20 I get 2. Total discount is 14 and total price is 90. 14/90>.15. What's am I doing wrong? Total discount = $14. The sum of the regular prices of the 3 items = $90. 15% of $90 = $13.5. $14 > $13.5.
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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Re: Henry purchased 3 items during a sale. He received a 20
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15 Jul 2017, 10:24
I believe this question is a perfect example of an "Easy C" trap. Just by realizing that A&B would be sufficient and make the problem way too easy, we can eliminate C,D and E. This is a simple rule that could improve one's chances on 700+ problems



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Re: Henry purchased 3 items during a sale. He received a 20
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18 Dec 2017, 23:35
Fortunately or Unfortunately, the OA is C for this one. I'm staring at the answer on GMATPREP software :/ Attaching screenshot



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Re: Henry purchased 3 items during a sale. He received a 20
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18 Dec 2017, 23:47



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Re: Henry purchased 3 items during a sale. He received a 20
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14 Jul 2018, 20:03
Bunuel wrote: docabuzar wrote: Henry purchased 3 items during a sale. He received a 20 percent discount off the regular price of the most expensive item and a 10 percent discount off the regular price of each of the other 2 items. Was the total discount of these three items greater than 15 percent of the sum of the regular prices of the 3 items?
(1) The regular price of the most expensive item was $50, and the regular price of the next most expensive item was $20 (2) The regular price of the least expensive item was $15 Let the prices be a, b, and c, so that a > b > c. Basically the questions: is \(0.2a+0.1b+0.1c>0.15(a+b+c)\)? > is \(a>b+c\)? (1) The regular price of the most expensive item was $50 and the regular price of the next most expensive item was $20 > \(a=50\), \(b=20\), \(c\leq{20}\) (as the second most expensive item was $20 then the least expansive item, the third one, must be less than or equal to 20). So the question becomes: is \(50>20+c\) > is \(c<30\)? As we got that \(c\leq{20}\), hence the above is always true. Sufficient. (2) The regular price of the least expensive item was $15. Clearly insufficient. Answer: A. Where is it mentioned that b>c? both the items could've the same price or even c>b? No? Please correct me.
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Re: Henry purchased 3 items during a sale. He received a 20 &nbs
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