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Bunuel
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Bunuel
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I like the solution - it’s helpful.
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I don’t quite agree with the solution. To ensure at least one from all 3 groups:

Maximum - Take all candies from the two largest groups and then 1 from the smallest group
Minimum - Take all candies from the two smallest groups and then 1 from the largest group

In the solution, minimum and maximum ways are interchanged.
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prayashpnd577
I don’t quite agree with the solution. To ensure at least one from all 3 groups:

Maximum - Take all candies from the two largest groups and then 1 from the smallest group
Minimum - Take all candies from the two smallest groups and then 1 from the largest group

In the solution, minimum and maximum ways are interchanged.

You are wrong.

“Minimum number needed to guarantee” means the fewest picks that guarantees success in the worst case.

In the worst case, Rita avoids one flavor as long as possible, so she could first pick all candies from the two largest flavor groups. Only the next pick guarantees the missing flavor.

So we use:

two largest groups + 1

not two smallest groups + 1.

Check other Worst Case Scenario Questions from our Special Questions Directory to understand the concept better.
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There is no way to measure deterministically the minimum criteria right as its a random draw. The only thing certain is that after picking all Mango and Lime Candy, the next random draw will have to be a cherry.
prayashpnd577
I don’t quite agree with the solution. To ensure at least one from all 3 groups:

Maximum - Take all candies from the two largest groups and then 1 from the smallest group
Minimum - Take all candies from the two smallest groups and then 1 from the largest group

In the solution, minimum and maximum ways are interchanged.
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I like the solution - it’s helpful.
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