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If 1,500 is increased by 20%, and then reduced by y%

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If 1,500 is increased by 20%, and then reduced by y% [#permalink]

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New post Updated on: 20 Sep 2013, 17:34
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If 1,500 is increased by 20%, and then reduced by y%, yielding 1,080, what is y?

OA is
40%

Originally posted by jlgdr on 20 Sep 2013, 17:20.
Last edited by Bunuel on 20 Sep 2013, 17:34, edited 1 time in total.
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Re: If 1,500 is increased by 20%, and then reduced by y% [#permalink]

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New post 20 Sep 2013, 17:26
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Re: If 1,500 is increased by 20%, and then reduced by y% [#permalink]

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New post 21 Mar 2017, 23:33
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jlgdr wrote:
If 1,500 is increased by 20%, and then reduced by y%, yielding 1,080, what is y?

OA is
40%



Using percent-fraction equivalents:

1500 * (6/5) * n = 1080

n = 1080/300*6 = 3/5

This is equivalent to a reduction of 40%. So y = 40

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Re: If 1,500 is increased by 20%, and then reduced by y% [#permalink]

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New post 22 Mar 2017, 07:11
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jlgdr wrote:
If 1,500 is increased by 20%, and then reduced by y%, yielding 1,080, what is y?

OA is
40%


\(\frac{1500*( 100 + 20 )}{100} * \frac{( 100 - y )}{100} = 1080\)

Or, \(1800*\frac{( 100 - y )}{100} = 1080\)

Or, \(18( 100 - y ) = 1080\)

Or, \(2( 100 - y ) = 120\)

Or, \(100 - y = 60\)

So, \(y = 40\)
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Re: If 1,500 is increased by 20%, and then reduced by y% [#permalink]

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New post 23 Mar 2017, 16:59
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jlgdr wrote:
If 1,500 is increased by 20%, and then reduced by y%, yielding 1,080, what is y?

OA is
40%


If 1,500 is increased by 20%, we have:

1,500 x 1.2 = 1,800

If 1,800 is reduced by y% to give us 1,080, we have:

(1 - y/100)(1800) = 1,080

1,800 - 18y = 1,080

720 = 18y

y = 40
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If 1,500 is increased by 20%, and then reduced by y% [#permalink]

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New post 17 May 2017, 15:55
If 1,500 is increased by 20%, and then reduced by y%, yielding 1,080, what is y?

1500 increased by 20% = 120% of 1500 = \(\frac{120}{100}\) x 1500 = 1800
1800 decreased by y% = (100-y) % of 1800 = \(\frac{(100-y)}{100}\) x 1800 = (100-y) x 18 = 1080
100-y = \(\frac{1080}{18}\) = 60
y = 100 - 60 = 40
y = 40%

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If 1,500 is increased by 20%, and then reduced by y%   [#permalink] 17 May 2017, 15:55
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